second line was supposed to be value2
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"Split Function" in SQL Server
Hi,
Since a while I'm messing arround trying to build a "Split Function" in SQL Server:
declare @value nvarchar(50)
declare @splitter nvarchar(50)
declare @delimit nvarchar(1)
select
@delimit = '/'
select
@splitter = 'Any Section/Department A'
SET
@value = SUBSTRING(@splitter,1,CHAR
select
@value as retSplittedValue
Looks good, but I'm only able to receive the string before the delimit: "Any Section"
I wonder if anyone has an idea how to get the the string behind the delimit: "Department A"
Best regards,
Raisor
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Answers
sorry....also missed an @:
declare @value1 nvarchar(50)
declare @value2 nvarchar(50)
declare @splitter nvarchar(50)
declare @delimit nvarchar(1)
select
@delimit = '/'
select
@splitter = 'Any Section/Department A'
SET
@value1 = SUBSTRING(@splitter,1,CHAR
, @value2 = SUBSTRING(@splitter,CHARIN
select
@value1 as retSplittedValue1
, @value2 as retSplittedValue2
If you will only have 1 delimiter, you can use the technique discussed in the following link:
http://www.sql-server-help
Basically, it uses the PARSENAME function. To use it in your case:
DECLARE @splitter VARCHAR(50)
SET @splitter = 'Any Section/Department A'
SELECT PARSENAME(REPLACE(@splitte
Hi,
@jrb1: Thanks a lot jrb, I've tested your solution and it returned:
Server: Msg 170, Level 15, State 1, Line 10
Line 10: Incorrect syntax near ','.
@josenich: Your peace of code did the job!
Parameter set to "2" returns: 'Any Section'
Parameter set to "1" returns: 'Department A'
... and I'll read the article too!
Thanks for the quick and professional help!
Best regards,
Raisor
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by: jrb1Posted on 2005-10-14 at 13:30:44ID: 15088799
do it:
declare @value1 nvarchar(50)
declare @value1 nvarchar(50)
declare @splitter nvarchar(50)
declare @delimit nvarchar(1)
select
@delimit = '/'
select
@splitter = 'Any Section/Department A'
SET
@value1 = SUBSTRING(@splitter,1,CHAR
, @value2 = SUBSTRING(@splitter,CHARIN
select
@value1 as retSplittedValue1
, @value2 as retSplittedValue2