Question

Quick SQL question

Asked by: llght

i have three tables as follows;

1. items
   -----
   itemID
   itemName
   "

2. comments
   --------
   itemID
   comment

3. links
   -----
   itemID
   link

essentially i would like to create a sql select statment to produce a summary i.e:

| itemID | itemName | numberOfLinks | numberOfComments |

i cannot seem to do this without using subselects which is unfortunatly not posible as i am using mysql.

anyone have any ideas??

cheers

pat...

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Asked On
2002-09-18 at 08:10:17ID20360532
Topic

MySQL Server

Participating Experts
4
Points
70
Comments
6

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Answers

 

by: angelIIIPosted on 2002-09-18 at 08:43:30ID: 7288621

Hi,
your original question:
http://www.experts-exchange.com/Databases/Q_20360535.html

Not sure if my comment there helps, but hope you find the best answer for you!

CHeers

 

by: bobbit31Posted on 2002-09-18 at 11:36:19ID: 7289197

angelll, i'm too lazy to check out your link as ee is operating so slow for me right now... if this duplicates your answer there, please accept my apologies:

but you can try:

select t1.itemID, t1.itemName, COUNT(DISTINCT t2.itemID) as numComments, COUNT(DISTINCT t3.itemID) as numLinks
FROM items t1
LEFT JOIN comments t2 ON t1.itemID = t2.itemID
LEFT JOIN links t3 ON t1.itemID = t3.itemID
GROUP BY t1.itemID

 

by: kelfinkPosted on 2002-09-18 at 15:49:19ID: 7289907

Bobbit's answer would only show numComments = 1 for a case where there are two records in "comments" having itemId = 1.

If, however, there were some unique ID column on the Comments table, you could "count(DISTINCT CommentID)" and you'll avoid the duplicates.

 

by: bobbit31Posted on 2002-09-19 at 07:25:16ID: 7291439

>  you could "count(DISTINCT CommentID)"
yes, that's what i meant, when i did my test i used the primary key of my t1 and t2... thanks for the correction.

 

by: SqueebeePosted on 2003-11-22 at 15:37:15ID: 9804385

llght,
No comment has been added lately (429 days), so it's time to clean up this TA.
I will leave a recommendation in the Cleanup topic area for this question:

RECOMMENDATION: split points between bobbit31 http:#7289197 and kelfink http:#7289907

Please leave any comments here within 7 days.

-- Please DO NOT accept this comment as an answer ! --

Thanks,

Squeebee
EE Cleanup Volunteer

20120131-EE-VQP-002

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