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7.0

MySQL syntax query problems and PHP

Asked by -ZugZug- in MySQL Server

Hey thanks for taking a look, I am trying to to access data through a form and i am incountering a couple problems. This is the error i am getting when i pass it to the php script:

"You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT sa.AgencyID FROM AgencyAreas aa"

here is the code for the query:

$result = mysql_query("SELECT ag.AgencyID, ag.CompanyName, ag.Address, ag.StateOrProvince, ag.City, ag.PostalCode
FROM Agencies ag
WHERE ag.StateOrProvince ='$province'

AND ag.AgencyID IN ( SELECT sa.AgencyID
FROM AgencyAreas aa
INNER JOIN Areas ar ON (aa.AreaServedID=
ar.AreaServedID)
WHERE a.AreaServed LIKE '%$city')

AND ag.AgencyID IN ( SELECT as.AgencyID
FROM AgencyServices
WHERE ServiceID IN ($services))"
) or die("Invalid query: " . mysql_error() );
// $services is a check box array

My second problem is that $services is an array from check boxes and i have no clue how to include it in the query, WHERE ServiceID IN ($services))" just seems way to easy for the luck i have been having with this.
what i am trying to do is to return information based on the areas the agency serves based on a text field input from the user  and services provided based on a check box query. I hope this makes sense, if not sorry my brain is mush right now. Thanks again

[+][-]07/29/03 06:38 AM, ID: 9027871Expert Comment

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[+][-]07/29/03 08:36 AM, ID: 9028784Author Comment

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[+][-]07/29/03 09:32 AM, ID: 9029263Expert Comment

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[+][-]07/29/03 09:33 AM, ID: 9029273Accepted Solution

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About this solution

Zone: MySQL Server
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Solution Provided By: pizzametsalami
Participating Experts: 1
Solution Grade: A
 
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