Question

Invalid use of group function

Asked by: Paul_F_Robinson

Hello,

When I run the query:

SELECT names.name, Count(names.name) AS CountOfname, photos.user, photos.censored FROM photos
RIGHT JOIN names ON photos.photo=names.photo
GROUP BY names.name, CountOfname, photos.user, photos.censored
HAVING ((photos.user='paul') AND (photos.censored=0))
ORDER BY Count(names.name) DESC

I receive the error:  "Invalid use of group function"

Does anyone know what is happening?

Thanks,

Paul Robinson.

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Asked On
2003-10-07 at 13:22:54ID20759872
Tags

use

,

group

,

invalid

,

function

Topic

MySQL Server

Participating Experts
5
Points
500
Comments
12

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Answers

 

by: VGRPosted on 2003-10-07 at 13:43:37ID: 9509027

try this :

SELECT names.name, Count(names.name) AS CountOfname, photos.user, photos.censored FROM photos
RIGHT JOIN names ON photos.photo=names.photo
GROUP BY names.name, CountOfname, photos.user, photos.censored
HAVING ((photos.user='paul') AND (photos.censored=0))
ORDER BY CountOfname DESC;

 

by: SqueebeePosted on 2003-10-07 at 13:44:11ID: 9509033

You don't group by an aggregate, try removing CountOfName from your GROUP BY list.

 

by: VGRPosted on 2003-10-07 at 13:48:42ID: 9509057

true. I missed it

agregate = alias

 

by: SqueebeePosted on 2003-10-07 at 13:52:55ID: 9509085

I had to look twice myself.

 

by: LowfatspreadPosted on 2003-10-07 at 16:45:27ID: 9510029

Hi Paul_F_Robinson,

this is better ...
put these sort of conditions in the where clause....
use the having clause for conditions testing the aggregate functions (count(.) etc)

SELECT names.name, Count(names.name) AS CountOfname, photos.user, photos.censored
FROM photos
RIGHT JOIN names
ON photos.photo=names.photo
Where photos.user='paul' AND photos.censored=0
GROUP BY names.name, photos.user, photos.censored
ORDER BY CountOfname DESC;

you could also substitute a 0 instead of photos.censored, and 'Paul' instead of the photos.user
and that would mean they could also come out of the group by clause.. which would reduce the amount
of work the database engine has to perform...


hth


Cheers!

 

by: VGRPosted on 2003-10-08 at 00:26:52ID: 9511691

except that the Query Optimizer will first strip them off :D

 

by: LowfatspreadPosted on 2003-10-08 at 07:20:31ID: 9513497

must re-read up on that ...
;-)

 

by: psadacPosted on 2003-10-08 at 12:15:54ID: 9515622

as lowfatspread explained you HAVING clause only applies to aggregate functions. but if you use a condition (WHERE) on the left table in a RIGHT JOIN it will transform it in an INNER JOIN, so it should not provide the desired result.
there is something unclear in your query : do you have many names for on photo, or many photos for one name ?
Anyway, could you post few lines of your tables and explain describe the desired result in simple words (not SQL) ?

 

by: Paul_F_RobinsonPosted on 2003-10-09 at 02:51:13ID: 9519423

Hello,

The query i presented has had the desired effect when using MS Access. However I have now moved to MySQL.

Basically there is one photo record with many name records.

mysql> describe names;
+-------+-------------+------+-----+---------+-------+
| Field | Type        | Null | Key | Default | Extra |
+-------+-------------+------+-----+---------+-------+
| photo | varchar(50) |      | MUL |         |       |
| name  | varchar(50) | YES  |     | NULL    |       |
+-------+-------------+------+-----+---------+-------+
2 rows in set (0.00 sec)

mysql> describe photos;
+--------------------+-------------+------+-----+---------+-------+
| Field              | Type        | Null | Key | Default | Extra |
+--------------------+-------------+------+-----+---------+-------+
| photo              | varchar(50) |      | PRI |         |       |
| top_level_catagory | varchar(50) | YES  |     | NULL    |       |
| location           | varchar(50) | YES  |     | NULL    |       |
| censored           | tinyint(1)  | YES  |     | NULL    |       |
| catagory           | varchar(50) | YES  |     | NULL    |       |
| user               | varchar(50) |      | MUL |         |       |
| recycled           | tinyint(1)  | YES  |     | NULL    |       |
| date               | date        | YES  |     | NULL    |       |
+--------------------+-------------+------+-----+---------+-------+
8 rows in set (0.00 sec)

A photo would have a collection of people associated with it. I want to get a list of people with a number representing how many photos they are in.

Thanks for the help,

Paul.

 

by: SqueebeePosted on 2003-10-09 at 06:04:29ID: 9520258

Did removing countofname from your group by clause work?

 

by: Paul_F_RobinsonPosted on 2003-10-09 at 06:24:52ID: 9520394

Hello,

Thanks for all the help. I just copied and pasted lowFatSpread's sql into my code and it worked.

Squeebee: I tried removing countOfName from my origional sql, it madfe no difference.

I'm not sure why the sql works in MS Access but not in MySQL. I'd be interested to know why? (no points for that tho!)

Anyway, as LowFatSpread gave the correct solution, I have awarded hime the 500 points.

Thanks everyone for the help.

Paul.

 

by: truckpoetryPosted on 2004-07-21 at 11:36:05ID: 11605590

The REAL reason that your code works (I just figured it out) is the ORDER BY.  The error says Error in GROUP BY clause, but it is really the Order By that is causing you problems.  If you notice the original code:

ORDER BY Count(names.name) DESC

and the replacement code:

ORDER BY CountOfname DESC;

The reason this works is because mySQL doesn't appear to support aggregate functions in the ORDER BY clause, and therefore you must declare an alias to the aggregate column in your select list.

Too bad you already gave out the points :).

Cameron

20120131-EE-VQP-002

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