[x]
Posted via EE Mobile

Search, ask, and monitor your questions on the go with EE Mobile. Visit Experts Exchange from your mobile device and never be out of touch again.

08/19/2005 at 02:20PM PDT, ID: 21533533
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!

9.8

Select Where In statement

Asked by ncw in MySQL Server

Tags: where, select

Mysql v3.23.49 says I have an error with the following syntax:

SELECT * FROM enquiry_courses WHERE enquiry_id IN (  SELECT enquiry_id FROM enquiries WHERE session_id =  '4cd3420a16dbd61c6af58f6199ac00f1' )

Myslq says: You have an error in your SQL syntax near 'SELECT enquiry_id FROM enquiries WHERE session_id =  '4cd3420a16dbd61c6af58f6199'

The sub query works on it's own: SELECT enquiry_id FROM enquiries WHERE session_id = '4cd3420a16dbd61c6af58f6199ac00f1'

Any suggestions? Once working I then want to change SELECT * to DELETE.
[+][-]08/19/05 02:32 PM, ID: 14713134

View this solution now by starting your 30-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

 

About this solution

Zone: MySQL Server
Tags: where, select
Sign Up Now!
Solution Provided By: Squeebee
Participating Experts: 1
Solution Grade: A
 
 
[+][-]08/19/05 03:55 PM, ID: 14713529

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 30-day free trial to view this Author Comment or ask the Experts your question.

 
 
Loading Advertisement...
20091111-EE-VQP-91