Question

how to get [balance] in such condition?

Asked by: kengkit

-----------------------------------------------------------------------------
Date         ID             Type     Debit     Credit    Balance
1-10-06    DN-1111    DN       86.00       0.00       86.00  
4-10-06    CN-8888    PAY       0.00      56.00       30.00  
1-11-06    DN-2222    DN      120.00       0.00      150.00
1-12-06    DN-3333    DN       15.00       0.00      165.00  
5-12-06    CN-9999    PAY       0.00     165.00        0.00
------------------------------------------------------------------------------
The above query result is wat i trying to get..

but my current sql statement can't calculate the [balance]

the condition to calculate as below

if 4-10-06's type = PAY, Then
4-10-06's [balance] = 1-10-06's [balance] MINUS 4-10-06's [credit]

-------------------------------------------------------------------------------

if 4-10-06's type = DN, Then
4-10-06's [balance] = 1-10-06's  [balance] ADD 4-10-06's [debit]

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Asked On
2007-01-24 at 02:25:10ID22134459
Tags

balance

,

credit

,

debit

Topic

MySQL Server

Participating Experts
2
Points
40
Comments
10

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Answers

 

by: kengkitPosted on 2007-01-24 at 02:26:43ID: 18384270

Date        ID              Type     Debit     Credit  
1-10-06    DN-1111    DN       86.00        0.00      
4-10-06    CN-8888    PAY       0.00       56.00      
1-11-06    DN-2222    DN      120.00        0.00      
1-12-06    DN-3333    DN       15.00        0.00      
5-12-06    CN-9999    PAY       0.00     165.00  

i can get the above query result by using the following sql..
-----------------------------------------------------------------------------
SELECT i.date, i.ID, i.Type, i.debit, i.credit FROM
(
SELECT dn.date, dn.dn_id AS ID, dn.Type, dn.amount AS Debit, 0.00 AS Credit FROM debit_note_table dn
UNION ALL
SELECT cn.date, cn.cn_id AS ID, cn.Type, 0.00 AS Debit, cn.amount AS Credit FROM credit_note_table cn
) i ORDER BY date ASC

 

by: todd_farmerPosted on 2007-01-24 at 07:08:56ID: 18386280

Try:

SELECT i.date, i.ID, i.Type, SUM(i.debit) AS debit, SUB(i.credit) AS credit FROM
(
SELECT dn.date, dn.dn_id AS ID, dn.Type, dn.amount AS Debit, 0.00 AS Credit FROM debit_note_table dn
UNION ALL
SELECT cn.date, cn.cn_id AS ID, cn.Type, 0.00 AS Debit, cn.amount AS Credit FROM credit_note_table cn
) i
GROUP BY i.date, i.ID, i.Type
ORDER BY date ASC

 

by: todd_farmerPosted on 2007-01-24 at 07:10:06ID: 18386299

Sorry, forgot to add the balance:

SELECT i.date, i.ID, i.Type, SUM(i.debit) AS debit, SUB(i.credit) AS credit, SUM(i.credit - i.debit) AS balance FROM
(
SELECT dn.date, dn.dn_id AS ID, dn.Type, dn.amount AS Debit, 0.00 AS Credit FROM debit_note_table dn
UNION ALL
SELECT cn.date, cn.cn_id AS ID, cn.Type, 0.00 AS Debit, cn.amount AS Credit FROM credit_note_table cn
) i
GROUP BY i.date, i.ID, i.Type
ORDER BY date ASC

 

by: mankowitzPosted on 2007-01-24 at 10:22:39ID: 18388376

todd-

I think he needs a running balance from all the transactions. I don't think your code will deliver that.

Go to the shell and do something like this:

SET @bal=0;
SELECT i.date, i.ID, i.Type, i.debit, i.credit, (@bal:=@bal-i.debit+i.credit) as Balance FROM
(
SELECT dn.date, dn.dn_id AS ID, dn.Type, dn.amount AS Debit, 0.00 AS Credit FROM debit_note_table dn
UNION ALL
SELECT cn.date, cn.cn_id AS ID, cn.Type, 0.00 AS Debit, cn.amount AS Credit FROM credit_note_table cn
) i ORDER BY date ASC

 

by: todd_farmerPosted on 2007-01-24 at 10:30:21ID: 18388466

mankowitz:

Yeah, I didn't understand the problem sufficiently, it seems.  I'm not sure that using a variable works here, since that is evaluated before the ORDER BY clause.  Maybe something like:

SELECT i.date, i.ID, i.Type, SUM(i.debit) AS debit, SUB(i.credit) AS credit, (SELECT SUM(i2.credit - i2.balance) FROM
SELECT dn2.amount AS Debit, 0.00 AS Credit FROM debit_note_table dn2 WHERE dn2.date < i.date
UNION ALL
SELECT 0.00 AS Debit, cn2.amount AS Credit FROM credit_note_table cn2 WHERE cn2.date < i.date
) i2
)AS balance FROM
(
SELECT dn.date, dn.dn_id AS ID, dn.Type, dn.amount AS Debit, 0.00 AS Credit FROM debit_note_table dn
UNION ALL
SELECT cn.date, cn.cn_id AS ID, cn.Type, 0.00 AS Debit, cn.amount AS Credit FROM credit_note_table cn
) i
GROUP BY i.date, i.ID, i.Type
ORDER BY date ASC;

Lots of ugliness here with correlated subqueries.

 

by: kengkitPosted on 2007-01-24 at 18:40:38ID: 18392646

hi todd... error came up when i try to execute ur query string..

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT dn2.amount AS Debit, 0.00 AS Credit FROM debit_note_table dn2 WHERE dn2.d' at line 2

 

by: mankowitzPosted on 2007-01-25 at 14:14:45ID: 18399877

kengkit-

I think he meant SUM instead of SUM

 

by: mankowitzPosted on 2008-09-02 at 18:08:04ID: 22373173

I think that mankowitz and todd farmer should get credit. We each offered workable solutions.

20120131-EE-VQP-002

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