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| 02.01.2008 at 04:40PM PST, ID: 23131251 |
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Attachment Details
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The Solution Rating System
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With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.
Your Input Matters If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support. Thank you! |
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CREATE TABLE customer (
idCustomer int unsigned auto_increment,
active int(1) unsigned,
city varchar(50),
primary key (idCustomer));
insert into customer values (1,1,"San Francisco");
insert into customer values (2,1,"Honolulu");
insert into customer values (3,0,"San Diego");
insert into customer values (4,1,"New York");
insert into customer values (5,1,"Seattle");
CREATE TABLE product (
idProduct int unsigned auto_increment,
idCustomer int unsigned not null,
productDate date,
product varchar(150),
primary key(idProduct));
insert into product values (1,1,'2008-01-30','IPOD');
insert into product values (2,1,'2008-01-31','Britney Spears Lifetime CD');
insert into product values (3,1,'2008-02-01','PORSCHE');
insert into product values (4,2,'2008-01-30','SONY TV');
insert into product values (5,2,'2008-01-31','Britney Spears Lifetime CD II');
insert into product values (6,5,'2008-02-01','GOLD');
insert into product values (7,3,'2008-02-01','PIZZA');
select a.idCustomer,b.idProduct,a.city,b.product from customer as A
LEFT JOIN product as b on a.idCustomer=b.idCustomer
WHERE b.idProduct=(select max(idProduct) from product as X
where x.idCustomer=a.idCustomer) and a.active=1
group by a.idCustomer;
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