January 8, 2009 12:38am pst

1. ushastry 28,000
2. angelIII 11,100
3. mwvisa1 10,450
4. ionutz2k2 6,000
5. cxr 4,900
6. Sandman... 4,400
7. Ray_Pas... 3,600
8. arnold 2,875
9. fibo 2,750
10. objects 2,500
10. Juan_Bar... 2,500
12. HayesJupe 2,000
12. bluebelldis... 2,000
12. azadisaryev 2,000
12. matthews... 2,000
12. LordOfPo... 2,000
12. jason1178 2,000
18. ryancys 1,600
18. thehagman 1,600
18. BrandonG... 1,600
21. tchamtieh 1,500
21. DanielWilson 1,500
23. PIERCGG 1,400
23. v2Media 1,400
23. jausions 1,400

1. angelIII 2,268,940
2. todd_far... 1,724,617
3. snoyes_jw 765,508
4. Raynard7 704,144
5. ushastry 630,074
6. hernst42 620,899
7. Squeebee 555,077
8. leannonn 502,006
9. hielo 481,986
10. routinet 393,202
11. NovaDeni... 374,559
12. akshah123 328,218
13. virmaior 324,848
14. psadac 324,195
15. AdrianSRU 321,878
16. yodercm 317,867
17. mankowitz 304,286
18. fibo 293,857
19. ee_rlee 219,254
20. teraplane 193,956
21. ldbkutty 184,558
22. racek 181,131
23. glcummins 180,665
24. gamebits 179,036
25. steelseth12 177,995

05.30.2008 at 05:41AM PDT, ID: 23444347

	[x] Attachment Details

Query to create summary / statistic from a table

[x]

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8.4

Zone:

MySQL Server

Hi,

I need help to create a query for this situation.

I have this tables:

table_product
- product_model VARCHAR(10)
- description VARCHAR(200)

table_transaction
- distributor_code VARCHAR(10)
- product_model VARCHAR(10)
- status INT

I need a query to COUNT all the product_model for each distributor that has status=1

There are only 25 product_models btw.

So, the summary will look like this (see in the code snippet).

Basically it will list all the distributors and then count for each product_model if the status=1.

I am not sure if this can be done with single query? Or should I use temporary table? view?

Please help.

Thanks.

         
             distributor product1 product2 product3 ... product25
 
ABC                0        1        0            50
CDEF               1       14        0            90

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Answered By:	Ray_Paseur
Expert Since:	02/08/2007
Accepted Solutions:	1015
Computer Expertise:	Advanced

Ray_Paseur has been an Expert for 1 year 11 months, during which he has posted 4427 comments and answered 1015 questions. Ray_Paseur is just one of 2167 experts in the MySQL Server Zone. 2 experts collaborated on this answer, which was graded an "A" by the asker.

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