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08.11.2008 at 08:03PM PDT, ID: 23640024
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8.0

mySQL update statement

Asked by bglodde in MySQL Server

Hi - I'm using mySQL v 4.1.22, so it should be ok to use DATEDIFF

This is my table description:

CREATE TABLE `spots` (
  `SpotId` int(11) NOT NULL auto_increment,
  `WidgetUUID` varchar(255) NOT NULL default '',
  `Approved` char(1) NOT NULL default '0',
  `ApprovedDate` datetime default NULL,
  `SpotImage` varchar(255) default NULL,
  `SpotLink` varchar(255) default NULL,
  `SpotLinkText` varchar(50) default NULL,
  `SpotMessage` varchar(255) default NULL,
  `SpotEmail` varchar(255) default NULL,
  `Active` char(1) NOT NULL default '1',
  `SpotCost` double NOT NULL default '0',
  `Paid` char(1) NOT NULL default '0',
  `PaymentFee` double unsigned NOT NULL default '0',
  `PaymentType` varchar(50) default NULL,
  `TransactionId` varchar(255) default NULL,
  `BuyerName` varchar(255) default NULL,
  `SpotReimbursed` char(1) NOT NULL default '0',
  `LastModified` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
  PRIMARY KEY  (`SpotId`),
  UNIQUE KEY `SpotId` (`SpotId`),
  KEY `SpotId_2` (`SpotId`),
  KEY `WidgetUUID_idx` (`WidgetUUID`(8))
) ENGINE=InnoDB DEFAULT CHARSET=latin1 COMMENT='';


This query returns rows:

select spotId from spots
where spots.Active = 1
and spots.WidgetUUID IN(select distinct WidgetUUID from widgets where widgets.StayAlive = 'monthly')
and datediff(current_date, spots.LastModified) > 30;

However, this update statement affects 0 rows where I'd expect it would return the same count as above:

update spots set spots.Active = 0
where      spots.Active = 1
and spots.WidgetUUID IN(select distinct WidgetUUID from widgets where widgets.StayAlive = 'monthly')
and datediff(current_date, spots.LastModified) > 30;


Can someone tell me what is wrong and why?
Thanks in advance.Start Free Trial
[+][-]08.12.2008 at 07:38AM PDT, ID: 22213518

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[+][-]08.13.2008 at 10:52AM PDT, ID: 22223991

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About this solution

Zone: MySQL Server
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Solution Provided By: bglodde
Participating Experts: 1
Solution Grade: A
 
 
 
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