Question

mysql select concat selection

Asked by: yarekGmail

Hello:
I have already posted my question at:
http://www.experts-exchange.com/Database/MySQL/Q_24340456.html
I thought I found the solution there but there is a problem:

solution (that does not woirk correctly)
SELECT CONCAT('pix1/', LEFT(username,1),'/',LEFT(username,2), '/', username , '-1.jpg')

It makes a kind of recurrent selection that make the result growing all the rime !

here is my request again


I have in my database users, fields name username who contains for instance the value dialogoo
I need to write a simple select function that selects:
pix1/d/di/dialogoo-1.jpg

pix1 is FIXED
d is the first letter
di are the first 2 letters
-1.jpg is fixed

so it it something like
SELECT "pix1/"+{firstLetter(username)+"/"+{first2Letters(username)}+"/"+{username}+"-1.jpg"
Any clue ?


regards

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Asked On
2009-05-01 at 08:49:17ID24372902
Tags

mysql select concat selection

Topics

MySQL Server

,

SQL Query Syntax

,

PHP and Databases

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Answers

 

by: racekPosted on 2009-05-01 at 09:22:55ID: 24280951

SELECT CONCAT('pix1/', LEFT(username,1),'/',LEFT(username,2), '/', TRIM(username) , '-1.jpg')

 

by: mwvisa1Posted on 2009-05-01 at 10:31:31ID: 24281599

The syntax looks correct how you had it; therefore, as racek is suggesting, check if there are extra spaces.  If there are, you will probably want to do TRIM on every occurrence of the username to ensure you don't have spaces in front since building directories out of first 1-2 characters.

 

by: racekPosted on 2009-05-01 at 11:09:09ID: 24281923

maybe

SELECT CONCAT(
'pix1/',
LEFT(TRIM(username,1)),'/',
LEFT(TRIM(username,2)), '/',
TRIM(username) , '-1.jpg')

 

by: yarekGmailPosted on 2009-05-01 at 12:36:37ID: 24282733

the original table has these values:
bel01
CcC01
CcC02
CcF01
CcF02
CcH01
...

here is the result I got:
pix1/b/be/bel01-1.jpg
pix1/b/C/Cc/CcC01-1.jpg
pix1/b/C/Cc/C/Cc/CcC02-1.jpg
pix1/b/C/Cc/C/Cc/CcC02C/Cc/CcF01-1.jpg
pix1/b/C/Cc/C/Cc/CcC02C/Cc/CcF01-1.jpgC/Cc/CcF02-1...
etc...

You see ? It keeps on growing !

The result keeps on GROWING ! ! !

 

by: racekPosted on 2009-05-01 at 12:50:46ID: 24282840

show me the whole query ...

 

by: yarekGmailPosted on 2009-05-01 at 13:23:56ID: 24283106

SELECT CONCAT('pix1/', LEFT(username,1),'/',LEFT(username,2), '/', TRIM(username) , '-1.jpg')  from inscrits

That's all !

 

by: Sharath_123Posted on 2009-05-01 at 14:06:46ID: 24283439

What do you mean by keep on growing.


Whats the result are you getting and what is your expected result?

I am getting correct result for the query suggested here.

mysql> create table inscrits(username varchar(1000));
Query OK, 0 rows affected (0.06 sec)
 
mysql> insert into inscrits values('bel01');
Query OK, 1 row affected (0.00 sec)
 
mysql> insert into inscrits values('CcC01');
Query OK, 1 row affected (0.00 sec)
 
mysql> insert into inscrits values('CcC02');
Query OK, 1 row affected (0.00 sec)
 
mysql> insert into inscrits values('CcF01');
Query OK, 1 row affected (0.00 sec)
 
mysql> insert into inscrits values('CcF02');
Query OK, 1 row affected (0.00 sec)
 
mysql> insert into inscrits values('CcH01');
Query OK, 1 row affected (0.00 sec)
 
mysql>
mysql> SELECT username,CONCAT('pix1/', LEFT(username,1),'/',LEFT(username,2), '/
', TRIM(username) , '-1.jpg') as complete_username
    ->   from inscrits;
+----------+-----------------------+
| username | complete_username     |
+----------+-----------------------+
| bel01    | pix1/b/be/bel01-1.jpg |
| CcC01    | pix1/C/Cc/CcC01-1.jpg |
| CcC02    | pix1/C/Cc/CcC02-1.jpg |
| CcF01    | pix1/C/Cc/CcF01-1.jpg |
| CcF02    | pix1/C/Cc/CcF02-1.jpg |
| CcH01    | pix1/C/Cc/CcH01-1.jpg |
+----------+-----------------------+
6 rows in set (0.00 sec)

                                              
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by: yarekGmailPosted on 2009-05-02 at 01:25:05ID: 24285322

WHEN I run step by step your SQLs (in a new database),
create table inscrits(username varchar(1000));
insert into inscrits values('bel01');
etc...

I GOT SOMETHING DIFFERENT ! ! !
 
username  complete_username  
bel01 pix1/b/be/bel01-1.jpg
CcC01 pix1/b/C/Cc/CcC01-1.jpg
CcC02 pix1/b/C/Cc/C/Cc/CcC02-1.jpg
CcF01 pix1/b/C/Cc/C/Cc/CcC02C/Cc/CcF01-1.jpg
CcF02 pix1/b/C/Cc/C/Cc/CcC02C/Cc/CcF01-1.jpgC/Cc/CcF02-1...
CcH01 pix1/b/C/Cc/C/Cc/CcC02C/Cc/CcF01-1.jpgC/Cc/CcF02-1...
Here is the screenshot ! ! ! !


 

by: yarekGmailPosted on 2009-05-02 at 01:27:34ID: 24285327

here is the screenshot !

 

by: Sharath_123Posted on 2009-05-02 at 01:30:11ID: 24285334

What is you MySQL version? I don't understand what is the problem. Can you try concatinating one string at a time and see the result.

 

by: yarekGmailPosted on 2009-05-02 at 03:28:19ID: 24285634

mysql 3.23.49

 

by: Sharath_123Posted on 2009-05-02 at 11:51:12ID: 24287130

can you try this?

SELECT username,CONCAT('pix1/', LEFT(username,1),'/',LEFT(username,2), '/', TRIM(username) , '-1.jpg') as complete_username
  FROM inscrits
 GROUP BY username;

                                              
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by: yarekGmailPosted on 2009-05-02 at 13:38:12ID: 24287484

Not better !

 

by: Sharath_123Posted on 2009-05-02 at 15:09:09ID: 24287831

its a simple CONCAT and not sure why its functioning like that. Can you run this and chek whats the output?

SELECT username,CONCAT(username) as complete_username
  FROM inscrits;
                                              
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by: yarekGmailPosted on 2009-05-03 at 00:42:36ID: 24289007

SELECT username,CONCAT(username) as complete_username   FROM inscrits;

it works normally !

 

by: Sharath_123Posted on 2009-05-03 at 00:51:15ID: 24289031

please try all combinations and check the resutl.

SELECT username,CONCAT('pix1/',username) as complete_username FROM inscrits;
SELECT username,CONCAT('pix1/',LEFT(username,1)) as complete_username FROM inscrits;
SELECT username,CONCAT('pix1/',LEFT(username,1),'/') as complete_username FROM inscrits;
SELECT username,CONCAT('pix1/',LEFT(username,1),'/',LEFT(username,2)) as complete_username FROM inscrits;
SELECT username,CONCAT('pix1/',LEFT(username,1),'/',LEFT(username,2),'/') as complete_username FROM inscrits;
SELECT username,CONCAT('pix1/',LEFT(username,1),'/',LEFT(username,2),'/',TRIM(username)) as complete_username FROM inscrits;
SELECT username,CONCAT('pix1/',LEFT(username,1),'/',LEFT(username,2),'/',TRIM(username),'-1.jpg') as complete_username FROM inscrits;
                                              
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by: yarekGmailPosted on 2009-05-03 at 05:24:57ID: 24289692

1) SELECT pseudo,CONCAT('pix1/',pseudo) as complete_pseudo FROM inscrits
OK

2) SELECT pseudo,CONCAT('pix1/',LEFT(pseudo,1)) as complete_pseudo FROM inscrits;
NOT OK

3) SELECT pseudo,CONCAT('pix1/',LEFT(pseudo,1),'/') as complete_pseudo FROM inscrits;
NOT OK

4) SELECT pseudo,CONCAT('pix1/',LEFT(pseudo,1),'/',LEFT(pseudo,2)) as complete_pseudo FROM inscrits;
NOT OK

5) SELECT pseudo,CONCAT('pix1/',LEFT(pseudo,1),'/',LEFT(pseudo,2),'/') as complete_pseudo FROM inscrits;
NOT OK

6) SELECT pseudo,CONCAT('pix1/',LEFT(pseudo,1),'/',LEFT(pseudo,2),'/',TRIM(pseudo)) as complete_pseudo FROM inscrits;

NOT OK
SELECT pseudo,CONCAT('pix1/',LEFT(pseudo,1),'/',LEFT(pseudo,2),'/',TRIM(pseudo),'-1.jpg') as complete_pseudo FROM inscrits


Infact only 1) works normally

Then other results keeps on growing more and more !
I have re-installed mySQL  3.23.49

 

by: psadacPosted on 2009-05-06 at 02:43:16ID: 24312653

"I have re-installed mySQL  3.23.49"
is there a good reason to stay with this very old version ?
there must be a bug with LEFT() with this version, try to replace it with SUBSTRING()

SELECT pseudo,CONCAT('pix1/',SUBSTRING(pseudo,1,1),'/',SUBSTRING(pseudo,1,2),'/',TRIM(pseudo),'-1.jpg') as complete_pseudo FROM inscrits

                                              
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