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7.9

after deleting a field in one of my tables, I get an error message

Asked by digigirl1124 in MySQL Server, PHP and Databases

Tags: MySQL / PHP and Windows Server

I was almost finished with a project and after testing realized I didnot need one of the fields in one of the tables.  So I truncated all of the tables (fresh start) except the one with users email and passwords.  Then, I deleted the field I no longer needed from one of the tables.  Then I got interrupted and forgot to delete the field name in my INSERT INTO statement for that form.  So, I received an error message.  Then, I deleted the field name from my INSERT INTO statement, but I continue to get the error message (see below). I have checked the syntax to see if I deleted anything other than the field name, but it looks fine.  Two eyes are always better than one!!!

Is there something I messed up by not deleting the field name first??
Should I do something else to correct it?
Thanks so much!
-digi 
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ERROR MESSAGE:
 
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\Hosting\######\html\processRegister2.php on line 141
 
MY CODE SHOWING line 141
 
$result = mysql_query("INSERT INTO dealers (dealer_name, dealer_address, dealer_address2, dealer_city, dealer_state, dealer_country, dealer_zipcode,  dealer_Acode, dealer_phone, dealer_AcodeCell, dealer_cell, dealer_AcodeFax, dealer_fax, dealer_contact, dealer_salesContact, dealer_serviceContact, dealer_partsContact, trackerID) VALUES ('".$_POST['dealer_name']."', '".$_POST['dealer_address']."', '".$_POST['dealer_address2']."', '".$_POST['dealer_city']."', '".$_POST['dealer_state']."', '".$_POST['dealer_country']."','".$_POST['dealer_zipcode']."', '".$_POST['dealer_Acode']."', '".$_POST['dealer_phone']."', '".$_POST['dealer_AcodeCell']."', '".$_POST['dealer_cell']."', '".$_POST['dealer_AcodeFax']."', '".$_POST['dealer_fax']."', '".$_POST['dealer_contact']."', '".$_POST['dealer_salesContact']."', '".$_POST['dealer_serviceContact']."', '".$_POST['dealer_partsContact']."', '".$_SESSION['trackerID']."')");
//LINE 141 IS BELOW:
$new = mysql_fetch_array($result);      
if(!$new) 
		{
            echo "There has been an error creating your account. 
            Please contact the webmaster." . mysql_error();
		}
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[+][-]07/08/09 11:36 PM, ID: 24811120Accepted Solution

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Zones: MySQL Server, PHP and Databases
Tags: MySQL / PHP and Windows Server
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Solution Provided By: ingwa
Participating Experts: 2
Solution Grade: A
 
[+][-]07/09/09 12:13 AM, ID: 24811256Author Comment

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[+][-]07/09/09 12:35 AM, ID: 24811343Expert Comment

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[+][-]07/09/09 10:39 AM, ID: 24816061Expert Comment

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