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9.0

MySQL Function Problem

Asked by djcheeky in MySQL Server

Tags: MySQL

Hi

I have created a function called GetContentCategories which gets a list of categories that are linked to a content record.

For example, if I run the following SQL:

SELECT *,GetContentCategories(contentId) from content
where '2' in (GetContentCategories(contentId))

As you can see, I am returning all content items that have a categoryList that contains category 2.

So far so good.

If I try and run that SQL when there is only ONE category returned by GetContentCategories(contentId) then this query works fine.
For example:
SELECT *,GetContentCategories(contentId) from content
where 2 in (2)        

But, if there are more than one categories linked to the content item and more than one category id is returned by calling GetContentCategories(contentId), then the query returns no records. For example:
SELECT *,GetContentCategories(contentId) from content
where 2 in (2,3,6)        

As you can see, there are 3 integer values returned by the function. 2 is clearly in the list, yet the query returns no records??

BUT - and here's the strange part, if i manually type in the values for the IN statement, then it works. In other words:

WORKS:
SELECT *,GetContentCategories(contentId) from content
where 2 in (2,3,6)      

DOESN'T WORK:
SELECT *,GetContentCategories(contentId) from content
where 2 in (GetContentCategories(contentId))

(where GetContentCategories(contentId) returns 2,3,6

What am I missing here. Manually typing in the values works, but using a function to generate the values does not. Yet the value returned by the function is EXACTLY the same as that typed manually - I have double checked!
1:
2:
3:
4:
5:
6:
CREATE DEFINER=`root`@`%` FUNCTION `GetContentCategories`(in_contentId BIGINT) RETURNS varchar(1024) CHARSET latin1
BEGIN
  DECLARE out_categoryList VARCHAR(1024);
  SET out_categoryList = (SELECT (CAST(GROUP_CONCAT(categoryId) AS CHAR(10000) CHARACTER SET utf8)) AS contentCategories FROM contentToCategory where contentId = in_contentId);
  RETURN out_categoryList;
END
 
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Keywords: MySQL Function Problem
 
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[+][-]08/26/09 12:58 PM, ID: 25191595Expert Comment

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About this solution

Zone: MySQL Server
Tags: MySQL
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Solution Provided By: nemws1
Participating Experts: 1
Solution Grade: A
 
[+][-]08/26/09 01:45 PM, ID: 25192080Expert Comment

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