[x]
Posted via EE Mobile

Search, ask, and monitor your questions on the go with EE Mobile. Visit Experts Exchange from your mobile device and never be out of touch again.

11/05/2009 at 04:03PM PST, ID: 24876616
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!

7.6

update records using linking table

Asked by yamya in MySQL Server, PHP and Databases

Tags: php mysql

:
In my db are three tables:
products, properties and productPropertyLink

the Link table manages the <strong>many to many relationships</strong>.

the key fields are:
products.productsUID
properties.productUID
productPropertyLink.productUID
productPropertyLink.propertyUID

the workflow is:
select productUID on page 1
pass as $breadcrumb1 to page 2
query WHERE productsUID =$breadcrumb1
set $var for form fields
echo $var into form fields
pass name="name" to page 3
set $var=$_POST['name'];
update  properties record
update products record
insert propertyLink record

THe goal is to update the existing property and product records, and to insert a new link record.

First: this query accurately populates the form fields, and displays as many forms as are needed to match all the records to the $_POST['$var']:

$query="SELECT products.productsUID, products.productName, products.productSKU, products.agrossi_LabID, products.ProdNextStep, products.yourName, properties.propertiesUID, properties.length, properties.width, properties.diameter, properties.cureTime, properties.viscosity, properties.handleTime, properties.fixtureTime, properties.gapFill, properties.batchNumber, properties.batchNotes, properties.tempC, properties.tempF, properties.tensile, properties.shear, properties.peel
FROM products, properties
WHERE products.productsUID = '$breadcrumb1'";

No update or insert query works correctly.

When the update to properties takes place, all the property record with a matching productsUID get updated.
SO far I either get all records with the same duplicated data, or nothing at all.
the 'nothing at all' code is attached for your review and comment. this includes all the code i've tried along the way commented out for troubleshooting.

thanks for the help.

amy
1:
2:
3:
4:
5:
6:
7:
8:
9:
10:
11:
12:
13:
14:
15:
16:
17:
18:
19:
20:
21:
22:
23:
24:
25:
26:
27:
28:
29:
30:
31:
32:
33:
34:
35:
36:
37:
38:
39:
40:
41:
42:
43:
44:
45:
46:
47:
48:
49:
50:
51:
52:
53:
54:
55:
56:
57:
58:
59:
60:
61:
62:
63:
64:
65:
66:
67:
68:
69:
70:
71:
72:
73:
<?php
//this page collects the POST variables from projectDataColl.php as $var for INSERT nad UPDATE  queries
$breadcrumb1=$_POST['breadcrumb1'];
$productName=$_POST['productName'];
$productSKU=$_POST['productSKU'];
$cureTime=$_POST['cureTime'];
$viscosity=$_POST['viscosity'];
$handleTime=$_POST['handleTime'];
$fixtureTime=$_POST['fixtureTime'];
$gapFill=$_POST['gapFill'];
$tempC=$_POST['tempC'];
$tempF=$_POST['tempF'];
$tensile=$_POST['tensile'];
$shear=$_POST['shear'];
$peel=$_POST['peel'];
$adhType=$_POST['adhType'];
$gradeClass=$_POST['gradeClass'];
$appDescrip=$_POST['appDescrip'];
$batchNumber=$_POST['batchNumber'];
$batchNotes=$_POST['batchNotes'];
$length=$_POST['length'];
$width=$_POST['width'];
$diameter=$_POST['diameter'];
$prodNextStep=$_POST['prodNextStep'];
$propertiesUID=$_POST['propertiesUID']; 
//clean up any carriage returns etc from text areas 
$var = preg_replace("/[\n\r]*/","",$var);
$ISR_notes = preg_replace("/[\n\r]*/","",$ISR_notes); 
 
//Connecting to MYSQL
MySQL_connect("$host","$login_name","$password"); 
//Select the database we want to use
mysql_select_db("ps2009") or die("Could not select database"); 
mysql_query("UPDATE properties
SET length='$length', width='$width', diameter='$diameter', cureTime='$cureTime', viscosity='$viscosity', handleTime='$handleTime', fixtureTime='$fixtureTime', gapFill='$gapFill', batchNumber='$batchNumber', batchNotes='$batchNotes'
WHERE productUID='$breadcrumb1' AND batchNumber='$batchNumber'"); 
/*mysql_query("UPDATE productPropertyLink
SET propertiesUID='$propertiesUID'
WHERE productUID='$breadcrumb1'");
*/
mysql_query("UPDATE products
SET ProdNextStep='$prodNextStep'
WHERE productsUID='$breadcrumb1'"); 
/*mysql_query("INSERT INTO properties (propertiesUID,batchNumber, batchNotes,length,width,diameter,cureTime,viscosity,handleTime,fixtureTime,gapFill,tempC,tempF,tensile,shear,peel)
    VALUES(NULL, '$batchNumber', '$batchNotes', '$length','$width','$diameter','$cureTime','$viscosity','$handleTime','$fixtureTime','$gapFill','$tempC','$tempF','$tensile','$shear','$peel')");       # generate ID by inserting NULL
*/ 
	
/*mysql_query("UPDATE productPropertyLink 
 SET propertiesUID=LAST_INSERT_ID() WHERE productsUID='$breadcrumb1'");  
*/
mysql_query("INSERT INTO productPropertyLink (productPropLinkUID, productsUID, propertiesUID)
 VALUES(NULL, '$breadcrumb1', LAST_INSERT_ID())");  # use ID in second table 
printf("Product-property Linking record has been created, with an id %d\n", mysql_insert_id());
/*
mysql_query(" UPDATE products 
SET  productName='$productName', productSKU='$productSKU' WHERE productsUID='$breadcrumb1'");
*/
echo "<BR />Record ID $breadcrumb1 <-- Updated<BR /><BR />"; 
 

?>
[+][-]11/05/09 06:56 PM, ID: 25756277

View this solution now by starting your 30-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

 

About this solution

Zones: MySQL Server, PHP and Databases
Tags: php mysql
Sign Up Now!
Solution Provided By: yauhing
Participating Experts: 1
Solution Grade: B
 
 
[+][-]11/05/09 10:49 PM, ID: 25757118

Experts Exchange has a courteous staff of administrators who help members get the most out of the website by means of administrative comments like this one.

Start your 30-day free trial to view this Administrative Comment or ask the Experts your question.

 
[+][-]11/06/09 06:46 AM, ID: 25759494

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 30-day free trial to view this Author Comment or ask the Experts your question.

 
 
Loading Advertisement...
20091111-EE-VQP-91 - Hierarchy / EE_QW_3_20080625