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10.14.2007 at 08:28AM PDT, ID: 22892165
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7.0

SQL to get first and last records from the recordset

Asked by cutie_smily in Oracle 10.x, Databases Miscellaneous, Oracle Database

Tags: , , , ,

I need some quick help in writing the query. This should be strictly done in SQL and cannot be done in PL/SQL or cannot create sequence number (Only select access).

The query should be order by
- AUDIT_NBR
- CLAIM_TYPE descending
- DETAIL_NBR
- DATE_PAID

After the data is sorted/ordered base on the above, summarize the financial fields:
GROUP BY:
- AUDIT_NBR
- DETAIL_NBR
- SUM(paid_AMT)
- SUM(CLM_AMT)

For the below records, use the values in the LAST record within the unique key for the following fields:
- DATE_PAID
- ITSTG_CREAT_DT      

For the remaining non-Financial fields, use the values in the FIRST record within the unique key.  These fields include:
- GROUP_NUMBER
- SUBS_NBR
- SERVICE_DATE
- FORMAT
- TYPE_OF_BILL
- PATIENT_STATUS
- PRIMARY_CODE
--SECOND_CODE

Below is the initial query to get the exact totals:
SELECT
   AUDIT_NBR,
   DETAIL_NBR,
   SUM(PAID_AMT) SUM_PAID,
   SUM(CLM_AMT) SUM_CLM
FROM CL_WRK
GROUP BY AUDIT_NBR, DETAIL_NBR)

The final select statement should include all the above mentioned columns.
Please let me know if anything is not clear or need additional information.

I am giving the maximum points.
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[+][-]10.14.2007 at 12:24PM PDT, ID: 20074627

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[+][-]10.15.2007 at 07:39AM PDT, ID: 20078610

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[+][-]10.15.2007 at 10:05AM PDT, ID: 20079678

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[+][-]10.15.2007 at 11:57AM PDT, ID: 20080571

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[+][-]10.15.2007 at 12:07PM PDT, ID: 20080662

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[+][-]10.16.2007 at 07:45AM PDT, ID: 20085981

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About this solution

Zones: Oracle 10.x, Databases Miscellaneous, Oracle Database
Tags: record, last, get, sql, first
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Solution Provided By: awking00
Participating Experts: 2
Solution Grade: A
 
 
[+][-]10.16.2007 at 01:19PM PDT, ID: 20088693

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[+][-]10.16.2007 at 09:30PM PDT, ID: 20090832

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[+][-]10.20.2007 at 10:00AM PDT, ID: 20115413

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