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08.05.2008 at 03:48AM PDT, ID: 23621733 | Points: 250
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How to get a part of string | quicker

Asked by deepak_tyco in Oracle 10.x

Tags: oracle, sql

Hi,
I have a varchar2 column which stores strings like '0974-1000-681000-1000-0000'  or 0974-1000-10000-681000-1000-0000' or '0974-1000-681000-1000'
I need a query which fetches which fetches the first part of it i.e. 0974 which is working fine

The second part of the query should fetch me the 3 or 4 part which will of 6 digits and the number of divisions can be 5 or 6 i meant it can be like 0974-1000-10000-681000-1000-0000' or '0974-1000-681000-1000-0000'

I was able to do this with reqular expression but it is taking long time.

Can any one help me with a query which runs faster

Thanks in advance
Regards,
deepakStart Free Trial 
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SELECT SUBSTR('0974-1000-681000-1000-0000',1,INSTR('0974-1000-681000-1000-0000','-',1)-1) FROM DUAL
 
 
REGEXP_REPLACE(REGEXP_REPLACE(pdt.GL_EXPENSE, '-[a-zA-Z0-9]+-[a-zA-Z0-9]+$', ''), '[a-zA-Z0-9]+-', '')
[+][-]08.05.2008 at 03:55AM PDT, ID: 22159682

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[+][-]08.05.2008 at 03:58AM PDT, ID: 22159701

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[+][-]08.05.2008 at 04:33AM PDT, ID: 22159885

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[+][-]08.05.2008 at 06:51AM PDT, ID: 22160841

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[+][-]08.05.2008 at 06:56AM PDT, ID: 22160885

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[+][-]08.05.2008 at 07:00AM PDT, ID: 22160939

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[+][-]08.05.2008 at 07:08AM PDT, ID: 22161013

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[+][-]08.05.2008 at 07:17AM PDT, ID: 22161101

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[+][-]08.05.2008 at 11:17PM PDT, ID: 22167506

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