Question

ORA-01003: no statement parsed

Asked by: DwayneZandbergen

Getting an oracle error message when a SQL is executed from a C application running in Unix.  The odd thing is that that it works fine until the OR portion of the SQL is utilized.

Here's the SQL:
          EXEC SQL
               SELECT count(*)
               INTO   :number_of_rows_found
               FROM   vgsm.formulation_header@alpha
               WHERE  formulation_id = rtrim(substr(:sales_code,1,8))
               OR     (substr(formulation_id,1,6) = rtrim(substr(:sales_code,1,6))
                       and rtrim(exl_blnd_machine) = rtrim(:source));

Where it returns and works fine when run from the sql cmd line.  Additionally, when the first part of the SQL runs and is satisfied by the where clause prior to the "OR" no problems are returned.  When the SQL requires that the portion following the "OR" clause ( (substr(formulation_id,1,6) = rtrim(substr(:sales_code,1,6)) and rtrim(exl_blnd_machine) = rtrim(:source) ), Oracle returns the following message:

ORA-01003: no statement parsed

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Asked On
2008-09-16 at 07:03:51ID23735094
Tags

Oracle

,

7.3.4

,

C code in unix connected to 7.3.4 database

,

C

Topics

Oracle 7.x

,

Sun Solaris

,

C Programming Language

Participating Experts
2
Points
500
Comments
4

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Answers

 

by: yuzhPosted on 2008-09-16 at 17:58:40ID: 22494650

Please have a look at the following doc:

http://www.error-code.org.uk/view.asp?e=ORACLE-ORA-01003

 

by: DwayneZandbergenPosted on 2008-09-17 at 12:54:34ID: 22502929

This just restates the Oracle Messages manual.

What I don't understand is when the SQL runs and is satisified with the following:
EXEC SQL
               SELECT count(*)
               INTO   :number_of_rows_found
               FROM   vgsm.formulation_header@alpha
               WHERE  formulation_id = rtrim(substr(:sales_code,1,8))

It works fine but when it needs to dip into the OR section of the where clause, it fails.

 

by: sdstuberPosted on 2008-09-24 at 22:33:49ID: 22566451

What happens if you split the query into two parts?

Just to confirm: is exl_blnd_machine a column in your table or a plsql function?  I assume a column, but want to be sure about the error.

Also, what does the generated c look like from this pro*c?  Is it an error in the pro*c precompiler?

 SELECT count(*)
               INTO   :number_of_rows_found
from (
           select 1 
               FROM   vgsm.formulation_header@alpha
               WHERE  formulation_id = rtrim(substr(:sales_code,1,8))
 union
          select 1
               FROM   vgsm.formulation_header@alpha
               WHERE      (substr(formulation_id,1,6) = rtrim(substr(:sales_code,1,6))
                       and rtrim(exl_blnd_machine) = rtrim(:source))
);

                                              
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by: DwayneZandbergenPosted on 2008-09-25 at 07:12:31ID: 22569316

I'll try splitting the query out with your suggestion, thanks.

And yes, exl_blnd_machine is a column, not a plsql function.  The compiled C code looks like this (see code snippet)

There are no errors in the pro*c precompiler.

        sqlstm.stmt = "select count(*)  into :b0  from formulation_header@al\
pha where (formulation_id=rtrim(substr(:b1,1,8)) or (substr(formulation_id,1,6\
)=rtrim(substr(:b1,1,6)) and rtrim(exl_blnd_machine)=rtrim(:b3)))";
                                              
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