You can get the remainder like this:
(([Field1]/[Field2])*100 -(Int([Field1]/[Field2])*1
Then just do a where check for = 0 on that.
JimD.
I have a query that has a column which is a formula that divides one field into another field to get a result. The result column is formated as a number 0.00 and what I'm trying to do is show only the values that are not whole numbers such as 2.50, 2.26 and not show whole numbers like 2.00, 5.00 and so forth
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by: sdstuberPosted on 2009-10-14 at 08:02:06ID: 25571316
select * from your_table
where your_column != floor(your_column)