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I'm assuming first and last are determined by order of the action type itself.<br />
<br />
select * from <br />
(select mdn, first_value(action_type) over (partition by mdn order by action_type) first_action,<br />
last_value(action_type) over(partition by mdn over action_type) last_action,<br />
count(*) over (partition by mdn) cnt<br />
from cnam_load<br />
) where cnt &gt;&nbsp;1
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I'm assuming first and last are determined by order of the action type itself.

select * from
(select mdn, first_value(action_type) over (partition by mdn order by action_type) first_action,
last_value(action_type) over(partition by mdn over action_type) last_action,
count(*) over (partition by mdn) cnt
from cnam_load
) where cnt > 1

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<div class="content wysiwyg-content">
Hi Folks,<br />
<br />
I have a table cnam_load which is Oracle table and the columns of the table are :-<br />
<br />
mdn<br />
action_type<br />
<br />
I have to use the over partition by command to get the first value and the last value of the action_type and it should be grouped by mdn and count(*) &gt;&nbsp;1. I never used over partition by command and I am not sure how to build this query. I would appreciate your advice. <br />
<br />
Thanks
</div>
</div>


Hi Folks,

I have a table cnam_load which is Oracle table and the columns of the table are :-

mdn
action_type

I have to use the over partition by command to get the first value and the last value of the action_type and it should be grouped by mdn and count(*) > 1. I never used over partition by command and I am not sure how to build this query. I would appreciate your advice. 

Thanks

ORACLE SQL - to get the first_value and the last_value using OVER PARTITION BY

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