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03/17/2009 at 04:00AM PDT, ID: 24237063
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6.8

How to find the duplicate records in oracle SQL?

Asked by Suriyaraj_Sudalaiappan in Oracle 9.x

Tags: Oracle, SQL, PL/SQL

Hi,
   I have table which contains huge number of data. Attached is the sample data for my scenario. If you see the sample data file,  the column name ( NAME, FACTOR_ATTR_CONTEXT, FACTOR_ATTRIBUTE, ATTR_VALUE, START_DATE_ACTIVE, END_DATE_ACTIVE) which is contains the same data. It is only differ in ADJUSTMENT_FACTOR. Thing is, all the columns except ADJUSTMENT_FACTOR should not repeat again, if the ADJUSTMENT_FACTOR value is different also. See the LINE_INDEX 1,2 data. I want to get the combination of column data which are not present again with different ADJUSTMENT_FACTOR value. If it comes again both the combination are duplicate. For identifying the combination we can use the LINE_INDEX column. For example LINE_INDEX 1 is one combination, 2 is another combination like that. Another thing is the ADJUSTMENT_FACTOR value is same for different combination also. If it is there, that is unique data. See the line_index value 3. Here the ADJUSTMENT_FACTOR value is same 0.4. But it is differ in ATTR_VALUE. So this is unique record. I want to write a SQL Query to achieve that. I tried so many times. Below is my query. can any one share with your thoughts?

Thanks
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SELECT a.* FROM 
    FACTOR_STG_SAM a
WHERE 
   NOT EXISTS (SELECT 
                    'x'
                FROM 
                    FACTOR_STG_SAM b
                WHERE 
                   a.NAME = b.NAME
                    AND a.FACTOR_ATTR_CONTEXT = b.FACTOR_ATTR_CONTEXT
                    AND a.FACTOR_ATTRIBUTE = b.FACTOR_ATTRIBUTE
                    AND a.ATTR_VALUE = b.ATTR_VALUE
                    AND NVL(a.ADJUSTMENT_FACTOR,0) <> NVL(b.ADJUSTMENT_FACTOR,0)
                    AND a.START_DATE_ACTIVE = b.START_DATE_ACTIVE
                    AND a.END_DATE_ACTIVE = b.END_DATE_ACTIVE
                );
Attachments:
 
Sample data for duplicate data
 
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Zone: Oracle 9.x
Tags: Oracle, SQL, PL/SQL
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Solution Provided By: sdstuber
Participating Experts: 3
Solution Grade: B
 
 
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