Question

Group by Month and Year

Asked by: TrystHughes

Hi all, I have a table that holds log data. It has a date column. What I want to do is to be able to group this data by month (I can do this), but also by year. So I get something like the following

Jan 2006 - 100
Feb 2006 - 120
Mar 2006 - 109
Jan 2007 - 101
Feb 2007 - 111
Mar 2007 - 98
etc.....

I have the following query which does it by month, but doesn't include the grouping by year...

SELECT  TO_CHAR(DATO, 'MON'), COUNT(*)
FROM    KUNDE_LOG_GET_COMPANY
WHERE   (KUNDE_NR = 245041)
GROUP BY (TO_CHAR(DATO, 'MON'))

Would be greatful if you could help me on this.

Thanks

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Asked On
2007-07-13 at 03:24:27ID22694074
Tags

group

,

month

,

year

Topics

PL / SQL

,

Oracle Database

Participating Experts
5
Points
50
Comments
8

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Answers

 

by: angelIIIPosted on 2007-07-13 at 03:25:19ID: 19479393

SELECT  TO_CHAR(DATO, 'MON YYYY'), COUNT(*)
FROM    KUNDE_LOG_GET_COMPANY
WHERE   (KUNDE_NR = 245041)
GROUP BY (TO_CHAR(DATO, 'MON YYYY'))

 

by: YANN0SPosted on 2007-07-13 at 03:28:18ID: 19479408

SELECT  TRUNC(DATO, 'MONTH'), COUNT(*)
FROM    KUNDE_LOG_GET_COMPANY
WHERE   (KUNDE_NR = 245041)
GROUP BY TRUNC(DATO, 'MONTH')

 

by: jwahlPosted on 2007-07-13 at 06:37:23ID: 19480689

SELECT my_month || ' ' || my_year || '-' || my_cnt
FROM (
 SELECT  
    TO_CHAR(DATO, 'MM') my_sort,
    TO_CHAR(DATO, 'MON') my_month,
    TO_CHAR(DATE, 'YYYY') my_year,
    COUNT(*) my_cnt
 FROM    KUNDE_LOG_GET_COMPANY
 WHERE   KUNDE_NR = 245041
 GROUP BY
    TO_CHAR(DATO, 'MM'),
    TO_CHAR(DATO, 'MON'),
    TO_CHAR(DATE, 'YYYY')
 ORDER BY 3,1
 );

 

by: TrystHughesPosted on 2007-07-13 at 06:56:31ID: 19480884

Thanks for the swift replies guys! :)

But what if I wanted to sort the returned results from current month down to oldest month?

If I put in 'ORDER BY (TO_CHAR(DATO, 'MON YYYY'))' then it orders it alphabetically because it converts it to char. Using ORDER BY DATO throws an error.

Thanks

 

by: SJT2003APosted on 2007-07-13 at 07:00:10ID: 19480926

Try ORDER BY (TO_CHAR(DATO, 'YYYYMMDD')) DESC  .
The DESC is added for descending from to start with highest (current)  to lowest (oldest)

 

by: angelIIIPosted on 2007-07-13 at 07:01:46ID: 19480945

here we go:

SELECT  TO_CHAR(DATO, 'MON YYYY'), COUNT(*)
FROM    KUNDE_LOG_GET_COMPANY
WHERE   (KUNDE_NR = 245041)
GROUP BY TO_CHAR(DATO, 'MON YYYY'), TO_CHAR(DATO, 'YYYYMM')
ORDER BY TO_CHAR(DATO, 'YYYYMM')

 

by: sujit_kumarPosted on 2007-07-13 at 07:02:50ID: 19480950

Tryu the below one,

 ORDER BY  to_char(DATO, 'YYYY-MM') DESC;

 

by: YANN0SPosted on 2007-07-13 at 07:06:05ID: 19480981

SELECT  TRUNC(DATO, 'MONTH'), COUNT(*)
FROM    KUNDE_LOG_GET_COMPANY
WHERE   (KUNDE_NR = 245041)
GROUP BY TRUNC(DATO, 'MONTH')
order by TRUNC(DATO, 'MONTH') desc;

20120131-EE-VQP-002

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