This is what I have:
CREATE OR REPLACE FUNCTION WEEKEND_DATE
(DATEIN IN DATE)
RETURN DATE AS
DATE_RESULT DATE;
BEGIN
DATE_RESULT := trunc(DATEIN) - 7;
RETURN DATE_RESULT;
END WEEKEND_DATE;
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Question
Getting the first day of the week using a pl/sql function
I would like to create a function to get the first day of the week(Sunday) by using the sysdate and if the value return is Sunday, I would like to get the previous Sunday's date.
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Answers
You have to consider the default language used in your Oracle data base. I think the following will be work best:
CREATE OR REPLACE FUNCTION WEEKEND_DATE (DATEIN IN DATE)
RETURN DATE AS
DATE_RESULT DATE;
BEGIN
select DATEIN - num_of_days + 1
into date_result;
from (
select decode(to_number(to_char(D
from dual);
RETURN DATE_RESULT;
END WEEKEND_DATE;
you can do this in many ways.. i have used your function to make it return date of last sunday if the date you are passing is a sunday.
If you are passing a date which is not a sunday, then that date itself returned as it is.
We can even do this in one sql itself,
select case when to_char(datein,'D') = 1 then datein - 7 else datein end my_date_val
from dual;
-- you can change the dual to your tablename and also you can change datein field name to a column which is there in your table.
Thanks
This function will return the date of the Sunday prior to the date passed in and, if that date is a Sunday will return the date of the previous Sunday.
create or replace function return_1st_day(date_in in date)
return date is
v_day pls_integer;
v_1st date;
begin
v_day := to_number(to_char(date_in,
if v_day = 1 then
v_1st := date_in - 7;
else v_1st := date_in - v_day + 1;
end if;
return v_1st;
end;
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by: awking00Posted on 2007-11-06 at 11:14:18ID: 20226626
create or replace function return_date
return date is
v_date date := sysdate;
begin
if to_char(v_date,'D') = '1'
then v_date := sysdate - 7;
end if;
return v_date;
end;
/