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5.8

how to join to queries

Asked by ammartahir1978 in PL / SQL, SQL Query Syntax, SQL Server 2005

Tags: microsoft, sql server

hi everyone,

i have two queries one gives me the stock units available and the other one give me the sales of the products, what i want is to join them so that i can see the following

the total of a product sold and the free stock available for that
/*STOCK AVAILABLE*/
select b.branch_desc,pm.alt_code1,c.colour_code,s.sizes_desc, Sum(ph.stock_units_free) FREE_STOCK,
Sum(ph.stock_units_it) IT_STOCK,Sum(ph.stock_units_qc) QC_STOCK
from product_history ph, product_master pm, product_detail pd,sizes s, colour c,branch b
where ph.week_selector = '1100250'
and ph.sku_id = pd.sku_id
and pd.product_id = pm.prod_id
and s.sizes_id = pd.sizes_id
and c.colour_id = pd.colour_id
and pm.alt_code1 like '01Q03'
and b.branch_id = ph.branch_id
group by pm.alt_code1,c.colour_code,s.sizes_desc,b.branch_desc
order by b.branch_desc,pm.alt_code1

/*STOCK SOLD*/

Select b.branch_desc,pm.alt_code1,c.colour_code,s.sizes_desc,sum(ptsd.units) as SOLD_UNITS
from anal_level al,pm_trans_header pth, pm_trans_sku_details ptsd,branch b,sizes s,colour c,product_detail pd, product_master pm
where pth.txn_date_time between '06-01-2008 00:00:00.000'and '09-01-2008 23:59:59.999'
and pth.receipt_id = ptsd.receipt_id
and pth.branch_id = b.branch_id
and ptsd.sku_id = pd.sku_id
and pd.product_id = pm.prod_id
and al.j_code = pm.j_code_link
and al.level_no = 4
and pd.colour_id = c.colour_id
and pd.sizes_id = s.sizes_id
and pth.flag = 1
and pth.transaction_void = 0
and ptsd.flag = 1
group by pm.alt_code1,c.colour_code,s.sizes_desc,b.branch_desc
order by b.branch_desc,pm.alt_code1

how can i merge these both queries to get the results, please help
 
Related Solutions
Keywords: how to join to queries
Title
1 how to join two queries
 
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[+][-]01/10/08 08:02 AM, ID: 20628146Accepted Solution

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Zones: PL / SQL, SQL Query Syntax, SQL Server 2005
Tags: microsoft, sql server
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Solution Provided By: sonicefu
Participating Experts: 2
Solution Grade: A
 
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