Question

how to synchronize two block's data in two related blocks

Asked by: wasabi3689

how to synchronize two block's data.

I have related two blocks. block B and block A are on the same canvas. One block A is based on view, and block B 's data is from block A's post-query trigger.

 I want to see when I press each current record indicator for each record in block A, corresponding record in block B will be shown.

Now the problem is I cannot synchronize two block's data. For example,  I input an ID in search block to bring up the block A, there are two records. There are also supposed two records in block B. But, in block B, there is only one record, always the last record from the post-query trigger.

Block A
ID            DESC
123         ABC
246         HGJ

Block B
ID          JOBS
123         ALEX   (This line is missing)
246         BILL     (only show this line)

I ever debug the post-query trigger and put the message statement to display the ID. The message can pop up both ID 123 and 246

Any ideas how to fix it?

I am using Oracle 8i database and application 11.0.3

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Asked On
2009-10-09 at 13:58:43ID24800602
Topics

PL / SQL

,

Oracle 8.x

,

SQL Query Syntax

Participating Experts
1
Points
100
Comments
15

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Answers

 

by: wasabi3689Posted on 2009-10-11 at 12:47:35ID: 25547088

I ever tried to create a new relation between Block A and Block B by it common ID but, I got a compiler error

Compiling ON-CHECK-DELETE-MASTER trigger on XX_DOWNLOADS_V block...
Compilation error on ON-CHECK-DELETE-MASTER trigger on XX_DOWNLOADS_V block:
PL/SQL ERROR 103 at line 10, column 19
Encountered the symbol "(" when expecting one of the following:
        a PL/SQL variable or double-quoted string
        an expanded name
        an expanded name link
        a table reference expression
        a key word
Resuming parse at line 12, column 52.

 

by: HenkaPosted on 2009-10-11 at 22:57:35ID: 25548819

Is the relation you have created OK ? What are its properties ?

You can use also this - in a trigger when pressing "current record indicator" simply use:
Go_Block ('B');
execute_query;
and you will see records.

 

by: wasabi3689Posted on 2009-10-12 at 08:23:34ID: 25552020

I created the relation OK, but cannot pass the compiling. Error I mentioned above.

I tried your code. But, it doesn't work.

I use when-mouse-down trigger, i don't see the records changed when I go to first record. One thing is strange. In block B,  always shown the last record when the form opened. When I use upper arrow or down arrow for the record, it only show the last record. But when I put a debug message to show record, I can see 2 records from the popped up message

 

by: wasabi3689Posted on 2009-10-12 at 09:31:18ID: 25552623

here is more information.

My block B (product) doesn't have a canvas, all its items go to block A (download)'s canvas.

 

by: HenkaPosted on 2009-10-12 at 22:24:46ID: 25557121

Your block B - I think that there is Number of Record property set to 1. It doesn't matter that block B is on the same canvas as block A is.
Also you ought to see what is the Default Where property of block B. Maybe it is changed somewhere - Pre-Query trigger etc.

 

by: wasabi3689Posted on 2009-10-13 at 19:37:13ID: 25566816

I changed  Number of Record property set to 2 or 3. It still only picks up one record also the last record. Block B doesn't have trigger at all.  the Default Where property of block B is nothing there. Block A has Pre-Query trigger but it seems it doesn't say any data for Block B.

Any other suggestions to debug this problem?

 

by: HenkaPosted on 2009-10-13 at 22:54:38ID: 25567641

I have read your first post:
"I have related two blocks. block B and block A are on the same canvas. One block A is based on view, and block B 's data is from block A's post-query trigger."

This is wrong - ... block B 's data is from block A's post-query trigger -> that is why there is only 1 last record. Post-Query trigger fires for each record so if there are 5 records in block A then in block B there will be record(s) for 5th record of block A.

You ought to set relation between block A and B and remove part corresponding part from Post-Query trigger of block A.

If there will be some compilation errors in ON-CHECK-DELETE-MASTER then you ougt to correct it (or post this trigger here and not only that there is an error).

 

by: wasabi3689Posted on 2009-10-16 at 13:17:13ID: 25592973

I completely remove the post-query trigger in block A and copy everything from Block A's post-query trigger to Block B's post-query trigger. But, it seems nothing happened. Nothing displayed on the form for block B, block A's data is fine.

Even I put a debugging message on the top of the post-query trigger like below

message ('this is beginning');
declare
.......

the message is never shown up.

 

by: HenkaPosted on 2009-10-18 at 22:39:48ID: 25602782

It seems that there is no relation between blocks A and B.
I don't understand the problem -> blocks A and B are based on table (view) -> block A has record(s) and in block B there must be corresponding record(s) => simply create relation between block A=master and B=child. I think that there is no need of post-Query trigger of block B because the relation will populate block B. Post-Query trigger of block B is needed only if there are some items not based on table columns you want to fill.

 

by: wasabi3689Posted on 2009-10-19 at 07:51:09ID: 25605649

No, block B is not based on table and view but a  post-query trigger.

 

by: wasabi3689Posted on 2009-10-19 at 15:53:57ID: 25609684

Yes, block A and block B are not completely related. Some data in block B cannot be linked to block A.

 

by: HenkaPosted on 2009-10-19 at 22:40:18ID: 25611266

Now I understand. A Database Block Property of block B is set to NO.
In this case Post-Query trigger in block A is not a good option for populating block B. Also Post-Query trigger of block B will do nothing because this block is not a database block.
I would create a procedure for filling block B. This procedure can be called in a When-New-Record-Instance trigger of block A. In such scenario after going to another record in block A a corresponding records of block B will appear.

 

by: wasabi3689Posted on 2009-10-23 at 11:02:57ID: 25646797

I am still working on it, hopefully, next week I will continue to discuss this ticket.

 

by: wasabi3689Posted on 2009-11-14 at 11:01:18ID: 25821904

Please let this question remain open. I haven't had time to work on it yet.

 

by: wasabi3689Posted on 2009-12-01 at 08:25:21ID: 31639473

I have found a solution by myself. I have to create a master/detail block relation. But your responses provide  me a good hint. Thanks.

20120131-EE-VQP-002

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