Question

Sql Query

Asked by: manjuravi

Hello Everyone!

How to resolve the cartasion in SQL Query.

Eg. If a master  in joined to 2 detailed record and further 2 more detail record.

For all suggesstion/help, I thank in advance.

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Asked On
2002-11-10 at 21:58:06ID20395009
Tags

cartasion

Topic

Oracle Database

Participating Experts
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Answers

 

by: osbjmgPosted on 2002-11-10 at 22:23:42ID: 7432438

I am not sure about what you are asking, but a cartesian product is made whenever you add relations(tables) into the FROM clause;

SELECT A.stagename, F.filmtitle
FROM actors a, films f, casts c
WHERE a.actorid=c.actorid AND
      c.filmid=f.filmid AND
      F.filmtitle="Top Gun";

this query joins three tables, ACTORS, FILMS, and CASTS in the FROM clause.  CASTS contains imformation about a specific set of actors and the movie they acted in, this query should return all actors names that were in the Top Gun cast (assuming you have this huge movie database).  

Think of a cartesian product as multiplying the rows(tuples) by the size of the other table's rows.  a table that has 10 rows and is joined with a table also containing 10 rows, the resulting cartesian product is 100 rows.  

In short, the more tables in the FROM clause, the slower the query will be; almost exponentially.  Every added table is multiplying the previous resulting table by its number of rows.

Table1=20 rows
Table2=20 rows
Table3=20 rows
Table4=20 rows

joining Table1, Table2, Table3, Table4 = 160,000rows

now your WHERE conditions must go through and do 160,000 comparisons for each WHERE condition (i.e.-a.actorid=c.actorid)

The WHERE conditions select only the resulting rows where one of the WHERE conditions is true.

Hope that helps, if not please clarify so I might help.

John Gill

 

by: AlbertYouPosted on 2002-11-10 at 22:36:22ID: 7432454


Hi,
Can you explain your question better ?
Thanks.

 

by: manjuraviPosted on 2002-11-11 at 03:38:47ID: 7433160

Hello John & Albert,


Thanks for your comments, yes I think i was not descriptive in my question sorry for that, actually the follwing sql

Select e.eqpt_id,
       e.eqpt_name,
       t.tech_name,
       s.part_name
from   equipment_master e,
       tech_master t,
       spare_parts s
where  e.eqpt_id = t.eqpt_id and
       e.eqpt_id = s.eqpt_id
where I want to avoid cartesian.

The scenario is like this, One equipment is maintained by two technician and they have used two spare parts.

but the query result show that the spare used are four instead two only (repeating the same two spares). How to avoid this ?

Thanks once again for your time.

 

by: osbjmgPosted on 2002-11-11 at 05:44:49ID: 7433496

first of all you might try the select statement:

SELECT DISTINCT e.eqpt_id, e.eqpt_name, t.tech_name, s.part_name

tell me if this works

 

by: griffmPosted on 2002-11-11 at 07:46:16ID: 7434012

Hi

Sorry, but I disagree with the use of the DISTINCT clause "osbjmq".  It might give you what you want IN THIS CASE, but it masks a more fundamental problem with the data or in the design of the tables.

Taking a quick look at the comments without having access to the structures of the 3 tables involved, I would hazard a guess that the SPARE_PARTS table might have a composite primary key which contains BOTH the key of EQUIP_MASTER and TECH_MASTER ?

Please post the table structures (significant columns only if you like) and show the primary keys on each table.

I think this might help shed more light on the problem.

Cheers

 

by: manjuraviPosted on 2002-11-12 at 03:01:30ID: 7437563

Hello!!
Pls find the table structures
Table 1
Job_order_Number         PK
Eqpt_id
Eqpt_name
Maintenance_date


Record

M10001,EQP-1002,GENERATOR,10-NOV-2002

Table 2
Job_order_number    FK
Tech_id
Tech_name
Man_hours
Labor_rate

EX. DATA
M10001,1020,VVVVVVV,20,45
M10001,1022,TTTTTTT,20,45



Table 3 [detail table]
Job_order_number    FK
Spare_id
Spare_name
Qty
unit_cost

EX. DATA
M10001,DE12304,UUUUUUUUUUUUUU,2,345.00
M10001,DF12349,JJJJJJJJJJJJJJ,2,524.00


The expected result should be as  follows;

M10001,VVVVVVV,900,UUUUUUUUUUUUUU,690.00
M10001,TTTTTTT,900,JJJJJJJJJJJJJJ,1048.00

But the result we get is
M10001,VVVVVVV,1800,UUUUUUUUUUUUUU,690.00
M10001,TTTTTTT,1800,JJJJJJJJJJJJJJ,1048.00


Hope this is would be much clearer in my question.

Thanks once again for all valuable suggestion.

Regards


 

by: griffmPosted on 2002-11-12 at 05:19:33ID: 7437952

Hi

The reason you are getting twice as many records as you want is because there are actually 2 separate parts to the question you are trying to answer as 1 question.

1 - Who has worked on this equipment and how many hours have they spent and what is their total cost?
2 - How many spare parts have been used for this equipment and what is the total cost?

Results of queries:

1 - M10001,VVVVVVV,900
    M10001,TTTTTTT,900

2 - M10001,UUUUUUUUUUUUUU,690.00
    M10001,JJJJJJJJJJJJJJ,1048.00

If you combine them as you seem to want to, you get the output as follows:

M10001,VVVVVVV,900,UUUUUUUUUUUUUU,690.00
M10001,TTTTTTT,900,UUUUUUUUUUUUUU,690.00
M10001,VVVVVVV,900,JJJJJJJJJJJJJJ,1048.00
M10001,TTTTTTT,900,JJJJJJJJJJJJJJ,1048.00

The output you want to achieve is as follows:

M10001,VVVVVVV,900,UUUUUUUUUUUUUU,690.00
M10001,TTTTTTT,900,JJJJJJJJJJJJJJ,1048.00

If I was asked to interpret this output I would say that Technician VVVVVVV has worked on equipment M10001 and has used (or fitted) spare part UUUUUUUUUUUUUU to it, and that Technician TTTTTTT has worked on equipment M10001 and has used (or fitted) spare part JJJJJJJJJJJJJJ to it.

In other words there is an implied relationship between the Technician and the spare part in the output.  There may be a way to get the output you want in the way you want it but I would doubt the usefulness of the data output in this way.

If I was asked to provide this kind of information using a single query, the only way in which I can think of trying to provide a meaningful answer would be to provide the following information:

Equip Id Equip Name Total Labour Cost Total Parts Cost
-------- ---------- ----------------- ----------------
M10001   GENERATOR               1800          1738.00

If you need to find out which parts or which technician had worked on the equipment, this could be provided as 2 separate queries.

I think that you should re-analyse your requirement to display the data in this way and try to come up with a more meaningful way of showing the relationships between the 3 tables.

HTH

Mark

 

by: griffmPosted on 2002-11-12 at 05:24:58ID: 7437972

Hi

The reason you are getting twice as many records as you want is because there are actually 2 separate parts to the question you are trying to answer as 1 question.

1 - Who has worked on this equipment and how many hours have they spent and what is their total cost?
2 - How many spare parts have been used for this equipment and what is the total cost?

Results of queries:

1 - M10001,VVVVVVV,900
    M10001,TTTTTTT,900

2 - M10001,UUUUUUUUUUUUUU,690.00
    M10001,JJJJJJJJJJJJJJ,1048.00

If you combine them as you seem to want to, you get the output as follows:

M10001,VVVVVVV,900,UUUUUUUUUUUUUU,690.00
M10001,TTTTTTT,900,UUUUUUUUUUUUUU,690.00
M10001,VVVVVVV,900,JJJJJJJJJJJJJJ,1048.00
M10001,TTTTTTT,900,JJJJJJJJJJJJJJ,1048.00

The output you want to achieve is as follows:

M10001,VVVVVVV,900,UUUUUUUUUUUUUU,690.00
M10001,TTTTTTT,900,JJJJJJJJJJJJJJ,1048.00

If I was asked to interpret this output I would say that Technician VVVVVVV has worked on equipment M10001 and has used (or fitted) spare part UUUUUUUUUUUUUU to it, and that Technician TTTTTTT has worked on equipment M10001 and has used (or fitted) spare part JJJJJJJJJJJJJJ to it.

In other words there is an implied relationship between the Technician and the spare part in the output.  There may be a way to get the output you want in the way you want it but I would doubt the usefulness of the data output in this way.

If I was asked to provide this kind of information using a single query, the only way in which I can think of trying to provide a meaningful answer would be to provide the following information:

Equip Id Equip Name Total Labour Cost Total Parts Cost
-------- ---------- ----------------- ----------------
M10001   GENERATOR               1800          1738.00

If you need to find out which parts or which technician had worked on the equipment, this could be provided as 2 separate queries.

I think that you should re-analyse your requirement to display the data in this way and try to come up with a more meaningful way of showing the relationships between the 3 tables.

HTH

Mark

 

by: csarPosted on 2002-11-12 at 08:02:08ID: 7438742

I understand that you like to create something like a BOM (bill of material), right.

You have no reference store which spare part has been used by which technician, so it doesn't make any sense to look for a query that combines a technician and a spare part in a single row. What should happen for example if more spare parts than technicians involed (or vice versa) have used?

For a BOM you should query independantly spares and technicians and merge the results using a UNION ALL. You can also define a view that does this job.

For a two-column report you can go like this (I warn you it is really ugly)
with bom as (select rownum mr from
tech
where ic='generator'
union
select rownum mr from
spare where ic='generator' ),
spares as
( select rownum sr, name, u*p up from spare
where ic='generator')
, techs as
( select rownum sr, name, h*p hp from tech
where ic='generator')
select 'generator', spares.name, spares.up, techs.name, techs.hp
from  bom left join spares on (mr=sr) left join techs on (mr=sr)
/

 

by: manjuraviPosted on 2002-11-12 at 21:53:18ID: 7441650

Hi Csar,

Thanks for your valuable input in regard to achieve the said result and thanks once again. Keep it up

regards

20120131-EE-VQP-002

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