try this:
select employee,code,sum(anount)
from Table_data
group by employee, code
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Question
combining rows with select statement
Dtl_table
---------
employee
date
type
code
amount
DATA:
1234,01-01-03,ME,SETOPT,4
1234,01-01-03,LE,SETOPT,2.
1234,01-01-03,M ,SETOPT,3.20
1234,01-01-03,X ,SETOPT,1
Sum_table
---------
employee
code
YTD_amount
DATA:
1234,SETOPT,10.75
I need a report that looks like
Employee Date ME LE M X YTD
-------- -------- ---- ---- ---- ---- -----
1234 01-01-03 4.00 2.55 3.20 1.00 10.75
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Answers
Try this:
select employee, date, sum(TA.me) as sum_me,
sum(TA.le) as sum_le,
sum(TA.m) as sum_m,
sum(TA.x) as sum_x,
sum(TA.ytd) as sum_ytd
from (
select employee, date, code
decode(type,'ME',amount,0)
decode(type,'LE',amount,0)
decode(type,'M',amount,0) as m,
decode(type,'X',amount,0) as x,
amount as ytd
from dtl_table
) TA
group by TA.employee, TA.date,TA.code
The output you are asking for is a classic "matrix" or "cross-tab" report. Standard SQL does not produce this kind of output by default. Oracle Reports (and other third-party reporting tools) can do this quite easily. Your other option is to use "decode" like others have already suggested. The disadvantage of the "decode" approach is that you have to know (and code for) all of the possible values in advance. The reporting tools can do this dynamically.
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by: andrewstPosted on 2003-03-26 at 13:39:28ID: 8213551
select employee, date,
sum(decode(type,'ME',amoun
sum(decode(type,'LE',amoun
sum(decode(type,'M',amount
sum(decode(type,'X',amount
sum(amount) ytd
from dtl_table
where code='SETOPT'
group by employee, date;
2 comments:
1) sum_table is redundant, you don't need it
2) you can't have columns called DATE or TYPE in Oracle, as they are reserved words