Question

ORACLE SQL - please explain OVER PARTITION BY

Asked by: joekeri

What does the OVER PARTITION BY do? I don't understand this SELECT statement and the OVER PARTITION BY.


SELECT                          
    Field1, field2,
    100 * field3/
        SUM(field3)
OVER ( PARTITION BY NULL) field4
FROM

This Question has been solved and asker verified All Experts Exchange premium technology solutions are available to subscription members.

Subscribe now for full access to Experts Exchange and get

Instant Access to this Solution

  • Plus...
  • 30 Day FREE access, no risk, no obligation
  • Collaborate with the world's top tech experts
  • Unlimited access to our exclusive solution database
  • Never be left without tech help again

Subscribe Now

Asked On
2006-03-29 at 06:11:43ID21793507
Tags

over

,

oracle

,

partition

,

sql

Topic

Oracle Database

Participating Experts
2
Points
50
Comments
7

Trusted by hundreds of thousands everyday for fast, accurate and reliable tech support.

  • "The time we save is the biggest benefit of Experts Exchange to Warner Bros. What could take multiple guys 2 hours or more each to find is accessed in around 15 minutes on Experts Exchange." Mike Kapnisakis, Warner Bros.
  • "Our team likes having a resource that is more secure than just using Google and most experts using this service really know their stuff. It's nice to look here first versus using Google." Dayna Sellner, Lockheed Martin
  • "Anytime that I've been stumped with a problem, 9 out of 10 times Experts Exchange has either the accepted solution or an open discussion of the potential solution to the problem." Kenny Red, eBay Inc.

See what Experts Exchange can do for you.

Got a question?

We've got the answer.

Experts Exchange has been collecting answers to technology questions since 1996…3 million and counting! If you have a question, chances are we already have your answer.

Screenshot of Experts Exchange Knowledgebase

Need individual assistance?

Our experts are ready to help.

If you can't find the exact answer you're looking for, ask our exclusive community of 50,000 experts. You’ll get a personalized answer from a trusted professional.

Screenshot of Experts Exchange Knowledgebase

Want to learn from the best?

Read articles from industry experts.

Thousands of free tech tips, tricks, how-to’s and tutorials are available in our peer reviewed articles section. See for yourself how smart our experts are, no login required.

Screenshot of an Article

Working on a long term project?

Store your work and research.

Save solutions to your questions, answers you’ve discovered through searching plus helpful articles in your personal knowledgebase for easy future access.

Screenshot of Experts Exchange Knowledgebase

Access the answers to your technology questions today.

Subscribe Now

30-day free trial. Register in 60 seconds.

What Makes Experts Exchange Unique?

Members of the expert community talk about why the experience at Experts Exchange is different than what you will find anywhere else.

Trusted by the world's most respected brands.

image of each brand's logo

Faithfully serving IT professionals since 1996.

Experts Exchange Logo

Try it out and discover for yourself.

Subscribe Now

30-day free trial. Register in 60 seconds.

Related Solutions

  1. Partitioning strategy Help
    I will have several tables with 6,000,000 rows in my database. As an example, this is one of the tables: TABLE_BIG FIELD1_PK NUMBER(10) FIELD2 NUMBER(10) FIELD3 VARCHAR2(256) CERATEDATE DATE Our queries are going to be over the field FIELD1_PK on the where clause and that nu...
  2. Difference Between using Field1 + Field2 and Field1 & F…
    This is a two part question. First, when concating two strings together, if I use Field1 + " " + Field2 + " " + Field3, and ANY of the fields are NULL, the whole expression returns NULL. When I use & instead, it comes back fine. What is the real diff...

Free Tech Articles

  1. WARNING: 5 Reasons why you should NEVER fix a computer for free.
    It is in our nature to love the puzzle. We are obsessed. The lot of us. We love puzzles. We love the challenge. We thrive on finding the answer. We hate disarray. It bothers us deep in our soul. W...
  2. SCCM OSD Basic troubleshooting
    SCCM 2007 OSD is a fantastic way to deploy operating systems, however, like most things SCCM issues can sometimes be difficult to resolve due to the sheer volume of logs to sift through and the dispe...
  3. Migrate Small Business Server 2003 to Exchange 2010 and Windows 2008 R2
    This guide is intended to provide step by step instructions on how to migrate from Small Business Server 2003 to Windows 2008 R2 with Exchange 2010. For this migration to work you will need the fo...
  4. Create a Win7 Gadget
    This article shows you how to create a simple "Gadget" -- a sort of mini-application supported by Windows 7 and Vista. Gadgets can be dropped anywhere on the desktop to provide instant information, ...
  5. Outlook continually prompting for username and password
    There have been a lot of questions recently regarding Outlook prompting for a username and password whilst using Exchange 2007. There are a few reasons why this would happen and I will try to cover t...
  6. Backup Exchange 2010 Information Store using Windows Backup
    There seems to be quite a lot of confusion around the ability to backup Exchange 2010 using the built in Windows Backup feature. This stems from the omission of this feature prior to Exchange 2007 s...

Cloud Class Webinars

  1. Avoiding Bugs in Microsoft Access
    Alison Balter takes and in-depth look at avoiding bugs in Access. In this webinar you will learn about using the immediate window to debug your applications, invoking the debugger, using breakpoints to troubleshoot, stepping through code, setting the next statement to execute, ...
  2. Top 10 Best New Features in Visio 2010
    Scott Helmers gives live demonstrations of the top 10 new features in Visio 2010. This webinar will teach you how to create compelling diagrams by adding shapes to the page with a single click, linking the shapes in a diagram to data in Excel (or SQL Server, or SharePoint), ...
  3. IT Consultant Business Secrets Revealed
    Michael Munger, Experts Exchange tech pro and IT consultant, pulls back the curtain on his very successful businesses and answers question on every IT consultant and business owner should know about. He shares secrets on what he did to solve the 5 most common problems in IT, ...
  4. Disaster Recovery and Business Continuity
    Quest CTO, Mike Billon, gives an overview of the steps involved in building a dunamic disaster recovery plan. Through case studies and an examination of software/hardware tooles for monitoring and testing, you'll gain a better understandin of where you are, where you want ...
  5. Organize Your Visio Diagrams with Containers and Lists
    Scott Helmers uses cross functional flowcharts, wireframe diagrams, data graphic legends and seating charts to teach you: how to ustilize all three new structured diagram components in Visio 2010, the best practices for organizeing shapes in previous version of Visio, how to organize ...
  6. How to Us Objects, Properties, Events and Methods in Microsoft Access
    Alison Dalter gives an in-depbth look at objects, properties, events and methods in Microsoft Access. In this webinar you will learn about using the object browser, referring to objects, working with properties and methods, working with object variables, understanding the ...

Join the Community

Give a Little. Get a Lot.

Join the community of experts here and help other tech pros by answering question in your area of expertise. You can earn FREE access to all Experts Exchange's premium features and resources.

Join the Community

Answers

 

by: paquicubaPosted on 2006-03-29 at 06:20:03ID: 16321847

In the above case PARTITION is useless ( SUM(field3) OVER () field4 --The same) . Field4 is getting populated with the total sum of field3 all way across, see the following example:

SCOTT@PROD > select empno, ename, sum(sal) over ( partition by null) as total_sal from emp;

     EMPNO ENAME       TOTAL_SAL
---------- ---------- ----------
      7369 SMITH           29025
      7499 ALLEN           29025
      7521 WARD            29025
      7566 JONES           29025
      7654 MARTIN          29025
      7698 BLAKE           29025
      7934 MILLER          29025
      7788 SCOTT           29025
      7839 KING            29025
      7844 TURNER          29025
      7876 ADAMS           29025
      7900 JAMES           29025
      7902 FORD            29025
      7782 CLARK           29025

14 rows selected.

Elapsed: 00:00:00.04
SCOTT@PROD > select empno, ename, sum(sal) over () as total_sal from emp;          

     EMPNO ENAME       TOTAL_SAL
---------- ---------- ----------
      7369 SMITH           29025
      7499 ALLEN           29025
      7521 WARD            29025
      7566 JONES           29025
      7654 MARTIN          29025
      7698 BLAKE           29025
      7782 CLARK           29025
      7788 SCOTT           29025
      7839 KING            29025
      7844 TURNER          29025
      7876 ADAMS           29025
      7900 JAMES           29025
      7902 FORD            29025
      7934 MILLER          29025

14 rows selected.

 

by: paquicubaPosted on 2006-03-29 at 06:21:59ID: 16321868

Now, if I want to create windows and run totals for different jobs I would PARTITION BY job:

SCOTT@PROD > select job, empno, ename, sum(sal) over (partition by job) as total_sal from emp;

JOB            EMPNO ENAME       TOTAL_SAL
--------- ---------- ---------- ----------
ANALYST         7788 SCOTT            6000
ANALYST         7902 FORD             6000
CLERK           7934 MILLER           4150
CLERK           7900 JAMES            4150
CLERK           7369 SMITH            4150
CLERK           7876 ADAMS            4150
MANAGER         7698 BLAKE            8275
MANAGER         7566 JONES            8275
MANAGER         7782 CLARK            8275
PRESIDENT       7839 KING             5000
SALESMAN        7844 TURNER           5600
SALESMAN        7654 MARTIN           5600
SALESMAN        7521 WARD             5600
SALESMAN        7499 ALLEN            5600

14 rows selected.

Elapsed: 00:00:00.03

 

by: joekeriPosted on 2006-03-29 at 06:25:34ID: 16321906

So,, from what you are saying is that OVER PARTITION BY I get that it is similar to GROUP BY... Is that correct?

 

by: paquicubaPosted on 2006-03-29 at 06:40:23ID: 16322054

Kind of, but No.

In the example below, when you group by JOB, you have to limit the number of columns and restrict the number of rows displayed in order to obtain the TOTAL SAL for the different jobs:

SCOTT@PROD > select job, sum(sal) as total_sal from emp group by job order by 1;

JOB        TOTAL_SAL
--------- ----------
ANALYST         6000
CLERK           4150
MANAGER         8275
PRESIDENT       5000
SALESMAN        5600


On the other hand, using partition allows me to display all columns and rows and still obtain a TOTAL SAL:

SCOTT@PROD > select job, empno, ename, sum(sal) over (partition by job) as total_sal from emp;

JOB            EMPNO ENAME       TOTAL_SAL
--------- ---------- ---------- ----------
ANALYST         7788 SCOTT            6000
ANALYST         7902 FORD             6000
CLERK           7934 MILLER           4150
CLERK           7900 JAMES            4150
CLERK           7369 SMITH            4150
CLERK           7876 ADAMS            4150
MANAGER         7698 BLAKE            8275
MANAGER         7566 JONES            8275
MANAGER         7782 CLARK            8275
PRESIDENT       7839 KING             5000
SALESMAN        7844 TURNER           5600
SALESMAN        7654 MARTIN           5600
SALESMAN        7521 WARD             5600
SALESMAN        7499 ALLEN            5600


I can add as many columns I want without affecting the result:

SCOTT@PROD > select job, empno, ename, sum(sal) over (partition by job) as total_sal, deptno from emp;

JOB            EMPNO ENAME       TOTAL_SAL     DEPTNO
--------- ---------- ---------- ---------- ----------
ANALYST         7788 SCOTT            6000         20
ANALYST         7902 FORD             6000         20
CLERK           7934 MILLER           4150         10
CLERK           7900 JAMES            4150         30
CLERK           7369 SMITH            4150         20
CLERK           7876 ADAMS            4150         20
MANAGER         7698 BLAKE            8275         30
MANAGER         7566 JONES            8275         20
MANAGER         7782 CLARK            8275         10
PRESIDENT       7839 KING             5000         10
SALESMAN        7844 TURNER           5600         30
SALESMAN        7654 MARTIN           5600         30
SALESMAN        7521 WARD             5600         30
SALESMAN        7499 ALLEN            5600         30

14 rows selected.

Elapsed: 00:00:00.00

 

by: RCorfmanPosted on 2006-03-29 at 06:43:02ID: 16322090

This is the syntax for Oracle Analytics.

Basically, a normal query is run and the results are retrieves intanally by the Database Engine, then the Analytics are applied to the results set and the Analytic function columns are computed.
There are several functions, Sum, Min, Max, Rank, Dense_rank, count, etc.

They sound similar to the agregate functions, but agregate function are either applied to every record in the results (without group by clause), or to groups or records. In eihter case, they reduce the number or rows returned with a normal aggregate function.

With the analytic functions, the number of rows returned is not reduced.  You can tell is is an analytic function, not a group by function, by the OVER keyword.  Over is followed by a 'windowing clause'. This is what is included inside the ( ).  The 'partition by' portion of a windowing clause works similar to the group by, it determines what portion of the result set to apply each analytic function to.  For some analytic function, the windowing clause must have an order by also.

Here are a couple examples:
SQL> select * from udttest;

IP           DEST             LINENO
------------ ------------ ----------
AAA          BBB                   1
AAA          CCC                   2
AAA          DDD                   3
AAA          EEE                   4
AAA          DDD                  -1
AAA          DDD                  -3
AAA          HHH

7 rows selected.

SQL> -- normal aggregate function
SQL> select DEST,count(*) from udttest group by DEST;

DEST           COUNT(*)
------------ ----------
BBB                   1
CCC                   1
DDD                   3
EEE                   1
HHH                   1

SQL> --- analytic count function - notice all rows are returned still
SQL> select DEST,count(*) over (partition by DEST) from udttest;

DEST         COUNT(*)OVER(PARTITIONBYDEST)
------------ -----------------------------
BBB                                      1
CCC                                      1
DDD                                      3
DDD                                      3
DDD                                      3
EEE                                      1
HHH                                      1

7 rows selected.

SQL> -- analytic sum function
SQL> select ip,dest,lineno,sum(lineno) over (partition by dest) sum_line,
  2                        sum(lineno) over (partition by ip) sum_ip
  3    from udttest;

IP           DEST             LINENO   SUM_LINE     SUM_IP
------------ ------------ ---------- ---------- ----------
AAA          BBB                   1          1          6
AAA          CCC                   2          2          6
AAA          DDD                   3         -1          6
AAA          DDD                  -3         -1          6
AAA          DDD                  -1         -1          6
AAA          EEE                   4          4          6
AAA          HHH                                         6

7 rows selected.

SQL> -- another example is using rank
SQL> select ip, dest,lineno,
  2     rank() over (partition by dest order by lineno) dest_rank_line
  3*   from udttest;

IP           DEST             LINENO DEST_RANK_LINE
------------ ------------ ---------- --------------
AAA          BBB                   1              1
AAA          CCC                   2              1
AAA          DDD                  -3              1
AAA          DDD                  -1              2
AAA          DDD                   3              3
AAA          EEE                   4              1
AAA          HHH                                  1

7 rows selected.

SQL> -- and the same, but we will order by lineno...
SQL> ---   notice the column values don't change, just the order as expected
SQL> select ip, dest,lineno,
  2     rank() over (partition by dest order by lineno) dest_rank_line
  3    from udttest order by lineno;

IP           DEST             LINENO DEST_RANK_LINE
------------ ------------ ---------- --------------
AAA          DDD                  -3              1
AAA          DDD                  -1              2
AAA          BBB                   1              1
AAA          CCC                   2              1
AAA          DDD                   3              3
AAA          EEE                   4              1
AAA          HHH                                  1

7 rows selected.

SQL>
SQL> -- this can be good for 'top N' queries
SQL> -- For instance, to get the top 3 records by lineno, we use a nested query
SQL> select * from (
  2    select ip,dest,lineno,
  3       rank() over (partition by ip order by lineno desc nulls last) rank
  4      from udttest
  5*  ) where rank <= 3;

IP           DEST             LINENO       RANK
------------ ------------ ---------- ----------
AAA          EEE                   4          1
AAA          DDD                   3          2
AAA          CCC                   2          3

SQL>

 

by: joekeriPosted on 2006-03-29 at 06:48:13ID: 16322137

thanks for the information. it clarified it for me...

 

by: RCorfmanPosted on 2006-03-29 at 09:14:55ID: 16323721

paquicuba, sorry, we cross-posted to some extent. I had typed my explanation and was running scripts to show the example. I didn't see that you'd already covered some of what I did by the time I actually posted...

20120131-EE-VQP-002

3 Ways to Join

30-Day Free Trial

The Experts

98% positive feedback on 31,087 answers since March 2000. angeliii is a Microsoft Most Valuable Professional for his work with MS SQL Server & Develoment.

He has also proven his knowledge of Visual Basic Programming, PHP Scripting and Oracle Databases.

The Experts

97% positive feedback on 10,752 answers since July 2000. lrmoore has more than 18 years experience in the networking industry.

The six-time Mircosoft MVPs specialties include firewalls, virtual private networking, and network management.

Testimonials

"...and excellent source for support... Kind of like having your very own IT dept." Electriciansnet

Testimonials

"I was apprehensive at signing up at first. However... it has already made my life as an IT administrator much easier." JaCrews

Testimonials

"WOW! You guys have great, active, and knowledgeable people on here." moore50

Business Clients

Business Clients

In the Press

"If you’ve got a question... Experts Exchange can supply an answer.”

In the Press

"...an invaluable aid for both IT professionals and those who require tech support."

In the Press

"where IT professionals provide quick answers on just about any topic"

Business Account Plans

Loading Advertisement...