i want to do something simple, but using 9.2 (no regexp)
select from myTable
where
first character of myStringCol = 'a' and second character is a number
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i mean, something other than:
select myCol from myTable
where
((substr(upper(myCol),1,1)
(substr(myCol,2,1)='0' or
substr(myCol,2,1)='1' or
substr(myCol,2,1)='2' or
substr(myCol,2,1)='3' or
substr(myCol,2,1)='4' or
substr(myCol,2,1)='5' or
substr(myCol,2,1)='6' or
substr(myCol,2,1)='7' or
substr(myCol,2,1)='8' or
substr(myCol,2,1)='9'
))
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by: actonwangPosted on 2006-06-05 at 12:18:27ID: 16835966
select * from myTable
where ...
and chr(substr(myStringcol,2,1
/