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06.22.2007 at 03:52PM PDT, ID: 22652515
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9.4

Identify Duplicate Records with SQL

Asked by vitoto in Oracle Database

Tags: , , ,

Hi, i am have SQL Stament and need identify the duplicated records using TOAD SQL.

This is SQL :

SELECT to_char(sysdate, 'yyyymmdd') as fec, afi_asegurados.no_afiliacion,
afi_asegurados.sexo, pfd_detalle.numpat,
afi_asegurados.cod_unidad_medica || afi_asegurados.cod_clinica as centro_medico,
afi_asegurados.afi_status_asegurado, to_char(max(pfd_fechas.fechcert), 'yyyymmdd') as fecvenc, to_char(fecha_nacimiento, 'yyyymmdd') as fecha_naci,
to_char(fecha_inscripcion, 'yyyymmdd') as fecha_insc, afi_asegurados.status_registro, afi_asegurados.estado_civil,
afi_asegurados.depto_direcc || afi_asegurados.munic_direcc as depto_muni_resi, to_char(afi_asegurados.fecha_muerte, 'yyyymmdd') as fecha_muerte, RTRIM(afi_asegurados.cod_usuario) as u_systema, 'X'
FROM sgcuser.afi_asegurados, sgcuser.pat_patronos, sgcuser.pfd_detalle, sgcuser.pfd_fechas
WHERE ( (pat_patronos.no_patronal = afi_asegurados.no_patronal)
AND (afi_asegurados.no_afiliacion = pfd_detalle.numafil)
AND (pfd_detalle.periodo = pfd_fechas.periodo)
AND (to_char(pfd_fechas.fechcert, 'yyyymm') >= to_char(sysdate, 'yyyymm'))
AND (afi_asegurados.no_afiliacion <> '000000000')
AND ((afi_asegurados.afi_status_asegurado <> '5')
AND (afi_asegurados.afi_status_asegurado <> '6')
AND (afi_asegurados.afi_status_asegurado <> '13')
AND (afi_asegurados.afi_status_asegurado <> '14')
AND (afi_asegurados.afi_status_asegurado <> '15')
AND (afi_asegurados.afi_status_asegurado <> '16')
AND (afi_asegurados.afi_status_asegurado <> '17')
AND (afi_asegurados.afi_status_asegurado <> '18')
AND (afi_asegurados.afi_status_asegurado <> '7')
AND (afi_asegurados.afi_status_asegurado <> '21')
AND (afi_asegurados.afi_status_asegurado <> '22')
AND (afi_asegurados.afi_status_asegurado <> '23')
AND (afi_asegurados.afi_status_asegurado <> '24')
AND (afi_asegurados.afi_status_asegurado <> '25')
AND (afi_asegurados.afi_status_asegurado <> '31')
AND (afi_asegurados.afi_status_asegurado <> '32')
AND (afi_asegurados.afi_status_asegurado <> '33')
AND (afi_asegurados.afi_status_asegurado <> '34')
AND (afi_asegurados.afi_status_asegurado <> '35')))
Group by afi_asegurados.no_afiliacion,
afi_asegurados.sexo, pfd_detalle.numpat,
afi_asegurados.cod_unidad_medica, afi_asegurados.cod_clinica,
afi_asegurados.afi_status_asegurado, afi_asegurados.fecha_nacimiento,
afi_asegurados.fecha_inscripcion, afi_asegurados.status_registro,
afi_asegurados.estado_civil, afi_asegurados.depto_direcc, afi_asegurados.munic_direcc,
afi_asegurados.fecha_muerte, afi_asegurados.cod_usuario

KEY Values is :
afi_asegurados.no_afiliacion
pfd_detalle.numpat

Sample result :

afi_asegurados.no_afiliacion   |   pfd_detalle.numpat
000000001                               |    44555444455
000000001                               |    44555444333
000000002                               |    34343444333
000000002                               |    34343444377
000000002                               |    34343444311

I need identify the records 000000001 and 000000002

Look Result after IDENTIFY :

afi_asegurados.no_afiliacion   |   pfd_detalle.numpat      |  flag
000000001                               |    44555444455              |    x
000000001                               |    44555444333              |    
000000002                               |    34343444333              |    x
000000002                               |    34343444377              |    
000000002                               |    34343444311              |    

This Result is ok for me too :

afi_asegurados.no_afiliacion   |   pfd_detalle.numpat      |  flag
000000001                               |    44555444455              |    
000000001                               |    44555444333              |    x
000000002                               |    34343444333              |    
000000002                               |    34343444377              |    x
000000002                               |    34343444311              |    x

Any idea, thank you.



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[+][-]06.22.2007 at 06:35PM PDT, ID: 19346099

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[+][-]06.22.2007 at 10:32PM PDT, ID: 19346612

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[+][-]06.24.2007 at 10:01AM PDT, ID: 19351665

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[+][-]06.24.2007 at 12:10PM PDT, ID: 19352111

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About this solution

Zone: Oracle Database
Tags: duplicate, records, sql, identify
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Solution Provided By: sathyagiri
Participating Experts: 3
Solution Grade: A
 
 
[+][-]06.24.2007 at 02:10PM PDT, ID: 19352373

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[+][-]06.24.2007 at 05:34PM PDT, ID: 19352765

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