Question

Select distinct

Asked by: autoknowledge

Hi experts,

Here is my table (file_location):

file_id       location_id      entity_id      template_id
100333    1255               1028            331
100333    1301               1025            331
100333    1322               1025            332
100333    1325               1025            332
100333    1326               1025            332
100335    1388               1028            331

My desired output:
100333    1301               1025            331
100333    1322               1025            332

I want to query the table to get entries with entity_id = 1025 AND unique template_id.

Thanks,

Stephen

This Question has been solved and asker verified All Experts Exchange premium technology solutions are available to subscription members.

Subscribe now for full access to Experts Exchange and get

Instant Access to this Solution

  • Plus...
  • 30 Day FREE access, no risk, no obligation
  • Collaborate with the world's top tech experts
  • Unlimited access to our exclusive solution database
  • Never be left without tech help again

Subscribe Now

Asked On
2008-04-23 at 08:17:04ID23346919
Tags

SQL, Oracle 9i

Topics

Oracle Database

,

SQL Query Syntax

Participating Experts
4
Points
350
Comments
16

Trusted by hundreds of thousands everyday for fast, accurate and reliable tech support.

  • "The time we save is the biggest benefit of Experts Exchange to Warner Bros. What could take multiple guys 2 hours or more each to find is accessed in around 15 minutes on Experts Exchange." Mike Kapnisakis, Warner Bros.
  • "Our team likes having a resource that is more secure than just using Google and most experts using this service really know their stuff. It's nice to look here first versus using Google." Dayna Sellner, Lockheed Martin
  • "Anytime that I've been stumped with a problem, 9 out of 10 times Experts Exchange has either the accepted solution or an open discussion of the potential solution to the problem." Kenny Red, eBay Inc.

See what Experts Exchange can do for you.

Got a question?

We've got the answer.

Experts Exchange has been collecting answers to technology questions since 1996…3 million and counting! If you have a question, chances are we already have your answer.

Screenshot of Experts Exchange Knowledgebase

Need individual assistance?

Our experts are ready to help.

If you can't find the exact answer you're looking for, ask our exclusive community of 50,000 experts. You’ll get a personalized answer from a trusted professional.

Screenshot of Experts Exchange Knowledgebase

Want to learn from the best?

Read articles from industry experts.

Thousands of free tech tips, tricks, how-to’s and tutorials are available in our peer reviewed articles section. See for yourself how smart our experts are, no login required.

Screenshot of an Article

Working on a long term project?

Store your work and research.

Save solutions to your questions, answers you’ve discovered through searching plus helpful articles in your personal knowledgebase for easy future access.

Screenshot of Experts Exchange Knowledgebase

Access the answers to your technology questions today.

Subscribe Now

30-day free trial. Register in 60 seconds.

What Makes Experts Exchange Unique?

Members of the expert community talk about why the experience at Experts Exchange is different than what you will find anywhere else.

Trusted by the world's most respected brands.

image of each brand's logo

Faithfully serving IT professionals since 1996.

Experts Exchange Logo

Try it out and discover for yourself.

Subscribe Now

30-day free trial. Register in 60 seconds.

Related Solutions

  1. distinct
    Hi, How can we show distinct values from cell A1:A100 and place all the distinct value to B1 ? Thanks.
  2. Finding Unique(Distinct) <field1> ORDER BY <field2>
    Hi All, I have a table in which I want- Unique <field1> Order By <field2>, both in the table. I wrote- SELECT DISTINCT <field1>,<field2> from <MYTABLE> ORDER BY <field2> Though I dont need <field2> in my resultset, I need to add it...
  3. Selecting Distinct
    I have this statement: Select j.JobId as ID, r.run as [Name], j.Route as Parent from jobs as j, run as r where r.runid = j.run Which gives me: 63 D1 1 58 D1 1 64 D1 1 71 D1 1 57 D1 1 70 D1 1 65 D2 1 66 D2 2 67 D2 5 68 D2 2 69 D2 2 59 D2 1 60 D...

Free Tech Articles

  1. WARNING: 5 Reasons why you should NEVER fix a computer for free.
    It is in our nature to love the puzzle. We are obsessed. The lot of us. We love puzzles. We love the challenge. We thrive on finding the answer. We hate disarray. It bothers us deep in our soul. W...
  2. SCCM OSD Basic troubleshooting
    SCCM 2007 OSD is a fantastic way to deploy operating systems, however, like most things SCCM issues can sometimes be difficult to resolve due to the sheer volume of logs to sift through and the dispe...
  3. Migrate Small Business Server 2003 to Exchange 2010 and Windows 2008 R2
    This guide is intended to provide step by step instructions on how to migrate from Small Business Server 2003 to Windows 2008 R2 with Exchange 2010. For this migration to work you will need the fo...
  4. Create a Win7 Gadget
    This article shows you how to create a simple "Gadget" -- a sort of mini-application supported by Windows 7 and Vista. Gadgets can be dropped anywhere on the desktop to provide instant information, ...
  5. Outlook continually prompting for username and password
    There have been a lot of questions recently regarding Outlook prompting for a username and password whilst using Exchange 2007. There are a few reasons why this would happen and I will try to cover t...
  6. Backup Exchange 2010 Information Store using Windows Backup
    There seems to be quite a lot of confusion around the ability to backup Exchange 2010 using the built in Windows Backup feature. This stems from the omission of this feature prior to Exchange 2007 s...

Cloud Class Webinars

  1. Avoiding Bugs in Microsoft Access
    Alison Balter takes and in-depth look at avoiding bugs in Access. In this webinar you will learn about using the immediate window to debug your applications, invoking the debugger, using breakpoints to troubleshoot, stepping through code, setting the next statement to execute, ...
  2. Top 10 Best New Features in Visio 2010
    Scott Helmers gives live demonstrations of the top 10 new features in Visio 2010. This webinar will teach you how to create compelling diagrams by adding shapes to the page with a single click, linking the shapes in a diagram to data in Excel (or SQL Server, or SharePoint), ...
  3. IT Consultant Business Secrets Revealed
    Michael Munger, Experts Exchange tech pro and IT consultant, pulls back the curtain on his very successful businesses and answers question on every IT consultant and business owner should know about. He shares secrets on what he did to solve the 5 most common problems in IT, ...
  4. Disaster Recovery and Business Continuity
    Quest CTO, Mike Billon, gives an overview of the steps involved in building a dunamic disaster recovery plan. Through case studies and an examination of software/hardware tooles for monitoring and testing, you'll gain a better understandin of where you are, where you want ...
  5. Organize Your Visio Diagrams with Containers and Lists
    Scott Helmers uses cross functional flowcharts, wireframe diagrams, data graphic legends and seating charts to teach you: how to ustilize all three new structured diagram components in Visio 2010, the best practices for organizeing shapes in previous version of Visio, how to organize ...
  6. How to Us Objects, Properties, Events and Methods in Microsoft Access
    Alison Dalter gives an in-depbth look at objects, properties, events and methods in Microsoft Access. In this webinar you will learn about using the object browser, referring to objects, working with properties and methods, working with object variables, understanding the ...

Join the Community

Give a Little. Get a Lot.

Join the community of experts here and help other tech pros by answering question in your area of expertise. You can earn FREE access to all Experts Exchange's premium features and resources.

Join the Community

Answers

 

by: ee_rleePosted on 2008-04-23 at 08:21:34ID: 21421657

hi, try this

SELECT *
FROM file_location f
WHERE entity_id=1025 AND
      location_id = (SELECT MIN(location_id) FROM file_location WHERE entity_id=f.entity_id AND template_id=f.template_id)

                                              
1:
2:
3:
4:

Select allOpen in new window

 

by: angelIIIPosted on 2008-04-23 at 08:21:38ID: 21421659

which one of the rows do you want to take, per template_id?

 

by: MilleniumairePosted on 2008-04-23 at 08:22:28ID: 21421674

Why these particular rows?  What is significant about location id 1301 and 1322?  Is it because these appear first in the list or because these are the lowest value locations for each template_id?

 

by: autoknowledgePosted on 2008-04-23 at 08:26:55ID: 21421737

> which one of the rows do you want to take, per template_id?

>Why these particular rows?  What is significant about location id 1301 and 1322?  Is it because these >appear first in the list or because these are the lowest value locations for each template_id?

Because they appear the first. I just want one copy for each template_id

 

by: ee_rleePosted on 2008-04-23 at 08:33:36ID: 21421824

Have you tried the query I posted? Btw, is location_id? If its not, try this

SELECT DISTINCT file_id,location_id,entity_id,template_id
FROM file_location f
WHERE entity_id=1025 AND
      file_id = (SELECT TOP 1 file_id FROM file_location WHERE entity_id=f.entity_id AND template_id=f.template_id ORDER BY file_id,location_id) AND
      location_id = (SELECT TOP 1 location_id FROM file_location WHERE entity_id=f.entity_id AND template_id=f.template_id ORDER BY file_id,location_id)

                                              
1:
2:
3:
4:
5:

Select allOpen in new window

 

by: autoknowledgePosted on 2008-04-23 at 08:49:16ID: 21422028

Yes I tried it but it's not producing the result I want, let me explain more here

file_id       location_id      entity_id      template_id
100333    1255               1028            331
100333    1301               1025            331
100333    1322               1025            332
100333    1325               1025            332     <-- for the same file_id, i just want one row per template_id
100333    1326               1025            332     <-- for the same file_id, i just want one row per template_id
100335    1388               1028            331
100334    1328               1025            332     <--- I want this because the file_id is different

My desired output:
100333    1301               1025            331
100333    1322               1025            332
100334    1328               1025            332    

And the table is actually generated by 2 different tables, joined by file_id. The location_id the assoc_image table is just for quick reference, although it's value should be the same as the corresponding entry in the file_location table. See below:

file_location:
+ file_id
+ location_id
+ entity_id

assoc_image
+ file_id
+ location_id
+ template_id

Thanks,

Stephen

 

by: ee_rleePosted on 2008-04-23 at 08:50:53ID: 21422046

try

SELECT *
FROM file_location f
WHERE entity_id=1025 AND
      location_id = (SELECT MIN(location_id) FROM file_location WHERE entity_id=f.entity_id AND template_id=f.template_id AND file_id=f.file_id)

                                              
1:
2:
3:
4:

Select allOpen in new window

 

by: ee_rleePosted on 2008-04-23 at 08:58:10ID: 21422132

sorry, ignore my last post. try

SELECT f.file_id, f.location_id, f.entity_id, MIN(a.template_id) template_id
FROM file_location f INNER JOIN assoc_image a ON f.file_id=a.file_id AND f.location_id=a.location_id
WHERE f.entity_id=1025
GROUP BY f.file_id, f.location_id, f.entity_id

                                              
1:
2:
3:
4:

Select allOpen in new window

 

by: MilleniumairePosted on 2008-04-23 at 09:24:11ID: 21422442

You say you only want one row per template_id for the same file_id.  That's fine but which row do you want to retrieve as they have different values for location_id.

e.g. there are 3 possible rows for file_id 100333, entity_id 1025 and template_id 332.  Does it matter which location_id is retrieved or don't you care?

file_id       location_id      entity_id      template_id
100333    1322               1025            332
100333    1325               1025            332    
100333    1326               1025            332

You show the following row as the one being retrieved:
100333    1322               1025            332

Why this one with location_id 1322?  Is it because this is the lowest location_id?  Does it matter which location_id is retrieved?

In the code ee_rlee has supplied he has assumed the row with the lowest location_id is retrieved but you haven't made it clear that this is your requirement.

 

by: MilleniumairePosted on 2008-04-23 at 09:25:10ID: 21422455

Scrap my previous comment, just noticed you answered the question earlier - Because it appears first.

 

by: MilleniumairePosted on 2008-04-23 at 09:27:32ID: 21422486

The SQL required is:

select file_id, min(location_id) location_id, entity_id, template_id
from file_location
where entity_id = 1025
group by file_id, entity_id, template_id

                                              
1:
2:
3:
4:

Select allOpen in new window

 

by: ee_rleePosted on 2008-04-23 at 09:34:34ID: 21422591

@Milleniumaire: I noticed that I grouped the wrong fields after I read your comment. :)

This is my modified query:

SELECT f.file_id, MIN(f.location_id) location_id, f.entity_id, a.template_id
FROM file_location f INNER JOIN assoc_image a ON f.file_id=a.file_id AND f.location_id=a.location_id
WHERE f.entity_id=1025
GROUP BY f.file_id, f.entity_id, a.template_id

                                              
1:
2:
3:
4:

Select allOpen in new window

 

by: sdstuberPosted on 2008-04-23 at 09:41:03ID: 21422658

SELECT file_id, location_id, entity_id, template_id
  FROM (SELECT file_id, location_id, entity_id, template_id,
               ROW_NUMBER () OVER (PARTITION BY template_id ORDER BY location_id)
                                                                            r
          FROM file_location
         WHERE entity_id = 1025)
 WHERE r = 1

 

by: autoknowledgePosted on 2008-04-23 at 11:25:15ID: 21423721

ee_rlee,

Your last SQL statement works, but how do I find out the number of rows it returns?

Thanks,
Stephen

 

by: sdstuberPosted on 2008-04-23 at 12:06:27ID: 21424143

try this, it will return the total number of rows and additional column on each row.


SELECT file_id, location_id, entity_id, template_id,count(*) over() cnt
  FROM (SELECT file_id, location_id, entity_id, template_id,
               ROW_NUMBER () OVER (PARTITION BY template_id ORDER BY location_id)
                                                                            r
          FROM file_location
         WHERE entity_id = 1025)
 WHERE r = 1

 

by: autoknowledgePosted on 2008-04-23 at 13:43:43ID: 21425150

Thanks for all your responses. I splited the points among the 3 of you who contributed to this question. Since ee_rlee was the first one that gave me the answer, I allocated more more points for him. Thanks again all the answers.

20120131-EE-VQP-002

3 Ways to Join

30-Day Free Trial

The Experts

98% positive feedback on 31,087 answers since March 2000. angeliii is a Microsoft Most Valuable Professional for his work with MS SQL Server & Develoment.

He has also proven his knowledge of Visual Basic Programming, PHP Scripting and Oracle Databases.

The Experts

97% positive feedback on 10,752 answers since July 2000. lrmoore has more than 18 years experience in the networking industry.

The six-time Mircosoft MVPs specialties include firewalls, virtual private networking, and network management.

Testimonials

"...and excellent source for support... Kind of like having your very own IT dept." Electriciansnet

Testimonials

"I was apprehensive at signing up at first. However... it has already made my life as an IT administrator much easier." JaCrews

Testimonials

"WOW! You guys have great, active, and knowledgeable people on here." moore50

Business Clients

Business Clients

In the Press

"If you’ve got a question... Experts Exchange can supply an answer.”

In the Press

"...an invaluable aid for both IT professionals and those who require tech support."

In the Press

"where IT professionals provide quick answers on just about any topic"

Business Account Plans

Loading Advertisement...