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9.0

ORA-00937: not a single-group group function

Asked by billprew in Oracle Database, SQL Query Syntax

Tags: ORACLE, SQL

I can't seem to find a way to fashion a query to do something that feels pretty simple.  I have created some test data and queries in the attached code that demonstrate the problem.  In this simple case, I have a table with a KEY column, and a VAL column.  I want to build a query that returns a single row showing the KEY that has the smallest SUM of it's VAL's.

When I took my first shot at it I got the ORA-00937 error.  So I tried to work around that with two nested queries, but that returns more than one row.  My desired result would be a single row showing the a KEY of "A" and having a total VAL of 30.

~bp
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-- Create table for testing
CREATE TABLE T1
(
  KEY  VARCHAR2(10 CHAR),
  VAL  INTEGER
);
 
Table created.
 
 
-- Add some test data
INSERT INTO T1 (KEY, VAL) VALUES ('A', 10);
1 row created.
INSERT INTO T1 (KEY, VAL) VALUES ('A', 20);
1 row created.
INSERT INTO T1 (KEY, VAL) VALUES ('B', 30);
1 row created.
INSERT INTO T1 (KEY, VAL) VALUES ('B', 40);
1 row created.
COMMIT;
Commit complete.
 
 
-- Display all data in table
SELECT * FROM T1;
 
KEY               VAL
---------- ----------
A                  10
A                  20
B                  30
B                  40
4 rows selected.
 
 
-- Display sums of VAL by KEY
SELECT KEY, SUM(VAL) FROM T1 GROUP BY KEY;
 
KEY          SUM(VAL)
---------- ----------
A                  30
B                  70
 
 
-- Try to find KEY with smallest SUM
SELECT KEY, MIN(SUM(VAL)) FROM T1 GROUP BY KEY;
 
SELECT KEY, MIN(SUM(VAL)) FROM T1 GROUP BY KEY
       *
Error at line 1
ORA-00937: not a single-group group function
 
 
-- Alternative nested query approach
SELECT T2.KEY, MIN(T2.TOT) MIN FROM (SELECT KEY, SUM(VAL) TOT FROM T1 GROUP BY KEY) T2 GROUP BY T2.KEY;
 
KEY               MIN
---------- ----------
A                  30
B                  70
2 rows selected.
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About this solution

Zones: Oracle Database, SQL Query Syntax
Tags: ORACLE, SQL
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Solution Provided By: awking00
Participating Experts: 4
Solution Grade: A
 
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