Question

Historical table query

Asked by: sunilbains

Can anyone please assist me, how can i implement following logic in stored procedure which will be executed on daily basis. -

-Step1-Insert sysdate-2weeks data to historical table from regular table A
-Step2- Once step2 execute successfully, then count number of rows loaded into historical table with number of rows from regular table A for sysdate-2weeks. If count matches, then, drop the partition which belong to sysdate-2 weeks from regular table. And if does not match then email the alert to team. Also, if any of the step fail, then raise alert alarm to team by sending email.
Thanks in advance

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Asked On
2009-11-02 at 18:35:40ID24865963
Topic

Oracle Database

Participating Experts
3
Points
500
Comments
6

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Answers

 

by: Sharath_123Posted on 2009-11-02 at 20:03:45ID: 25725961

Can you try to write code for your requirement? From there, the experts can assist you.

 

by: ppinonPosted on 2009-11-03 at 00:24:48ID: 25726910

If I understand the question, this code should be helpful.

First procedure does what you ask, second is a procedure to send email using UTL_SMTP.

CREATE OR REPLACE PROCEDURE AS
  v_x INTEGER;
  v_y INTEGER;
  v_email VARCHAR2(100);
BEGIN
  INSERT INTO TABLEA_HIST SELECT t.*, TRUNC(SYSDATE)-14 AS DATE_HIST FROM TABLEA t;
  --
  SELECT COUNT(*) INTO v_x FROM TABLE_HIST WHERE DATE_HIST = TRUNC(SYSDATE)-14 AND ID = t.ID;
  SELECT COUNT(*) INTO v_y FROM TABLEA;
  IF v_x = v_y THEN
    DELETE FROM TABLEA;
  ELSE
    SENDMAIL(v_email,v_email,'Alert','No matching');
  END IF;
END;
/
 
create or replace procedure sendmail(sender varchar2,recipient varchar2,subject varchar2, text varchar2) 
IS 
mailhost    VARCHAR2(64) := '192.168.1.32'; 
port constant number(2):=25; 
timeout number :=180; 
mail_conn  utl_smtp.connection; 
BEGIN 
mail_conn := utl_smtp.open_connection(mailhost, port,timeout); 
utl_smtp.helo(mail_conn, mailhost); 
utl_smtp.mail(mail_conn, sender); 
utl_smtp.rcpt(mail_conn, recipient); 
utl_smtp.open_data(mail_conn); 
utl_smtp.write_data(mail_conn,'From'||':'|| Sender || UTL_TCP.CRLF); 
utl_smtp.write_data(mail_conn,'To'||':'|| recipient || UTL_TCP.CRLF); 
utl_smtp.write_data(mail_conn,'Subject' ||':'|| subject || UTL_TCP.CRLF); 
utl_smtp.write_data(mail_conn, text); 
utl_smtp.close_data(mail_conn); 
utl_smtp.quit(mail_conn); 
EXCEPTION 
WHEN UTL_SMTP.PERMANENT_ERROR THEN 
  BEGIN 
    utl_smtp.quit(mail_conn); 
  END; 
RAISE_APPLICATION_ERROR(-20101,'This id has Permanent Error'); 
WHEN UTL_SMTP.TRANSIENT_ERROR THEN 
  BEGIN 
    utl_smtp.quit(mail_conn); 
  END; 
RAISE_APPLICATION_ERROR(-20102,'SMTP transient error:'); 
WHEN UTL_SMTP.INVALID_OPERATION THEN 
  BEGIN 
    utl_smtp.quit(mail_conn); 
  END; 
RAISE_APPLICATION_ERROR(-20103,'Invalid Operation in Mail using UTL_SMTP.'); 
WHEN OTHERS THEN 
RAISE_APPLICATION_ERROR(-20104,'Some other Error ...!'); 
end; 
/ 

                                              
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by: ppinonPosted on 2009-11-03 at 00:33:19ID: 25726959

With a small correction (name of the procedure missing), and the exception to send an alert to the team.

CREATE OR REPLACE PROCEDURE MYPROC AS
  v_x INTEGER;
  v_y INTEGER;
  v_email VARCHAR2(100) := 'me@mycompany.com';
  v_team VARCHAR2(100) := 'myteam@mycompany.com';
BEGIN
  INSERT INTO TABLEA_HIST SELECT t.*, TRUNC(SYSDATE)-14 AS DATE_HIST FROM TABLEA t;
  --
  SELECT COUNT(*) INTO v_x FROM TABLE_HIST WHERE DATE_HIST = TRUNC(SYSDATE)-14 AND ID = t.ID;
  SELECT COUNT(*) INTO v_y FROM TABLEA;
  IF v_x = v_y THEN
    DELETE FROM TABLEA;
  ELSE
    SENDMAIL(v_email,v_email,'Alert','No matching');
  END IF;
EXCEPTION
  WHEN OTHERS THEN
    SENDMAIL(v_team,v_team,'Alert','Error encountered in the procedure MyProc');
END;
/
                                              
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by: markgeerPosted on 2009-11-03 at 05:42:09ID: 25728791

This part of your requirement is not clear: "stored procedure which will be executed on daily basis. -
-Step1-Insert sysdate-2weeks data to historical table from regular table A"

You want the procedure to run every day, but gather data for two weeks?  Or, should it only gather data from the date that is exactly two weeks ago?

Then, if you really want to "drop the partition" in a PL\SQL procedure, you should be aware that DDL statements like this are not directly supported in PL\SQL.  You can use them, either in "execute immediate('DDL command')" or in the more complex procedures of the DBMS_SQL package that you can use if you want to.  So, it is possible to do DDL commands in PL\SQL but there are some restrictions.  Also, you will need to use a query to determine the name of the partition that you want to drop.  We don't know your table partitioning details, so we cannot write that query for you based on the data you have given us so far.

 

by: sunilbainsPosted on 2009-11-03 at 13:29:07ID: 25733954

Mark-
Below are my responses
-should it only gather data from the date that is exactly two weeks ago?
- am aware that DDL need to be used.
-need to determine query to drop whihc partition name. The table is partitoned by range on createdate column. The partition is created daily based on sysdate and two weeks older partition need to be dropped daily for which can you let me know how can i extract partition for date create -sysdate-2weeks.

 

by: markgeerPosted on 2009-11-03 at 13:45:54ID: 25734152

Can your partition names be used to determine the oldest partition?  Maybe yes, or maybe no.  You haven't told us what mechanism creates these partitions and how it determines a name for the partition.  If the partition name cannot be used, then you need a more-complex query to extract the "high_value" (which is in a "long" data type) and convert that to varchar2 so that you can compare them and find the partition with the minumum values.

Here is a query that I use to get table partition information, but this works in our system because the mechanism I use to create new partitions always includes the current date in the partition name, so I can easily identify the partitions with the highest values (which is what this query looks for).  It would be just as easy in our system to select the "min" instead of the "max" partition name to find the earliest partition for a table.

select substr(tp.TABLE_OWNER,1,10) "Owner",
substr(tp.TABLE_NAME,1,27) "Table",
substr(tp.PARTITION_NAME,1,24) "Partition name",
tp.HIGH_VALUE,
substr(tp.TABLESPACE_NAME,1,10) "Tablespace",
pc.column_name
from dba_tab_partitions tp, dba_part_key_columns pc
where tp.PARTITION_NAME = (select max(x.partition_name) from dba_tab_partitions x
  where x.table_owner = tp.table_owner and x.table_name = tp.table_name)
and tp.table_owner not in ('SYS','SYSTEM')
and tp.table_name not like 'BIN$%'
order by table_owner, table_name;

20120131-EE-VQP-002

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