Question

Crystal Report Logon Failed

Asked by: Lefarfadais

Good day

I've been browsing for at least a week to find a solution at my problem.
I have a Crystal Report into a Window Application coded in c#. This report is directly connected to a SQL Database. When I run it on local computer, where the program is coded and built, but when I try it on a client machine, it gives me the "LOGON FAILED" Error.

Down Below is a snippet code of where I create the report and add the login information. I assured myself that the file does exist.

P.S. Database logon information aren't the one showed. I assured myself that is has been replaced to their proper value.

Please help.
Thank you in advance!
 
Lefarfadais

ReportDocument doc;
        string path = Environment.CurrentDirectory + "\\report\\";
        public ReportViewer(string fileName)
        {
            InitializeComponent();
 
            doc = new ReportDocument();
            doc.Load(path + fileName);
            
            
            //ShortCarReport doc = new ShortCarReport();
            
            
            //doc.DataSourceConnections[0].SetConnection("ServerName", "DataBaseName", "UserName", "Password");
            
            ConnectionInfo info = new ConnectionInfo();
            info.UserID = "UserName";
            info.Password = "Password";
            info.ServerName = "ServerName";
            info.DatabaseName = "DatabaseName";
            info.IntegratedSecurity = false;
            info.Type = ConnectionInfoType.SQL;
 
            Tables myTables = doc.Database.Tables;
            foreach (Table myTable in myTables)
            {
                TableLogOnInfo myTableLogonInfo = myTable.LogOnInfo;
                myTableLogonInfo.ConnectionInfo = info;
                myTable.ApplyLogOnInfo(myTableLogonInfo);
            }
            //doc.SetDatabaseLogon("ServerName", "DataBaseName", "UserName", "Password");
            
 
            this.crystalReportViewer1.ReportSource = doc;
 
            //this.crystalReportViewer1.LogOnInfo[0].ConnectionInfo = info;
            this.crystalReportViewer1.Refresh();
            
        }
                                  
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Asked On
2009-10-07 at 10:00:37ID24793099
Tags

Crystal Report

,

c#

,

.Net

,

Windows form

Topics

Crystal Reports Software

,

C# Programming Language

,

.NET

Participating Experts
2
Points
250
Comments
13

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Answers

 

by: mlmccPosted on 2009-10-07 at 10:26:47ID: 25517751

Try commenting out the refresh line.  Refresh causes you to lose the logon information you changed.

mlmcc

 

by: LefarfadaisPosted on 2009-10-07 at 10:31:35ID: 25517798

thank you for answering

sadly, it's still showing me the login window with the Logon Failure

 

by: LefarfadaisPosted on 2009-10-07 at 11:13:35ID: 25518212

I figured out that I'm not able to anymore on my local machine.

I guess Refresh simply reset to default settings which is using Integrated security on my account and allow login.

Any way to solve this problem is welcome. Thank you

 

by: PCIIainPosted on 2009-10-08 at 01:09:42ID: 25523043

This is what we have to do in VB. I don't think you can block apply the connectioninfo.... 

            TableLogOnInfo logOnInfo = (TableLogOnInfo )table.LogOnInfo.Clone()  ;
            table.LogOnInfo.ConnectionInfo.AllowCustomConnection = true ;
 
            logOnInfo.ConnectionInfo.ServerName = connection.ServerName;//strConnection;
            logOnInfo.ConnectionInfo.LogonProperties.Clear ();
              
            logOnInfo.ConnectionInfo.LogonProperties.Add(new NameValuePair2("UserID", connection.UserID  ));
            logOnInfo.ConnectionInfo.LogonProperties.Add(new NameValuePair2("Database", connection.DatabaseName));
            logOnInfo.ConnectionInfo.DatabaseName = connection.DatabaseName;
            logOnInfo.ConnectionInfo.LogonProperties.Add(new NameValuePair2("Password", connection.Password ));
            logOnInfo.ConnectionInfo.LogonProperties.Add(new NameValuePair2("DSN", connection.ServerName ));
            logOnInfo.ConnectionInfo.LogonProperties.Add(new NameValuePair2("UseDSNProperties", 0));
                 
             table.ApplyLogOnInfo(logOnInfo);
 

                                              
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by: LefarfadaisPosted on 2009-10-08 at 06:42:37ID: 25525222

I tweaked a bit the thing you gave because I don't have the LogonProperties Property available in VS2008 Framework 3.5. I explicitly gave the information to every tables like I wrote below.

Also, I don't have a definition to NameValuePair2 so I didn't used it sorry.

            ConnectionInfo info = new ConnectionInfo();
            info.UserID = "UserId";
            info.Password = "Password";
            info.ServerName = "ServerName";
            info.DatabaseName = "DatabaseName";
            info.IntegratedSecurity = false;
            info.Type = ConnectionInfoType.SQL;
 
            Tables myTables = doc.Database.Tables;
            foreach (Table myTable in myTables)
            {
                TableLogOnInfo myTableLogonInfo = (TableLogOnInfo)myTable.LogOnInfo.Clone();
                myTableLogonInfo.ConnectionInfo.AllowCustomConnection = true;
 
                myTableLogonInfo.ConnectionInfo.DatabaseName = info.DatabaseName;
                myTableLogonInfo.ConnectionInfo.ServerName = info.ServerName;
                myTableLogonInfo.ConnectionInfo.UserID = info.UserID;
                myTableLogonInfo.ConnectionInfo.Password = info.Password;
                myTableLogonInfo.ConnectionInfo.IntegratedSecurity = info.IntegratedSecurity;
                myTableLogonInfo.ConnectionInfo.Type = info.Type;
                
                myTable.ApplyLogOnInfo(myTableLogonInfo);
            }
                                              
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by: LefarfadaisPosted on 2009-10-08 at 06:43:26ID: 25525230

It didn't solved the problem sorry, forgot to tell in last comment :S

 

by: PCIIainPosted on 2009-10-08 at 06:50:13ID: 25525321

Ummm, do you have a subreport, and if so have you found that one and changed all it's tables as well?

 

by: LefarfadaisPosted on 2009-10-08 at 06:51:46ID: 25525337

I only have 1 report, and it's the main. Unless i'm mistaken, I have formulas but it shouldn't affect anything else, shouldn't it?

 

by: PCIIainPosted on 2009-10-08 at 07:08:52ID: 25525565

Nope, just sub-reports.

 

by: LefarfadaisPosted on 2009-10-08 at 08:14:23ID: 25526358

I wanna also say the it's working on my local Machine but not on the client, and when I'm trying it on the client, the field "Database Name" and "Password" seems empty according to what I see..

I changed my code to test it out, and made sure that my SubReports, if any, receives the logon information

        ReportDocument doc;
        string path = Environment.CurrentDirectory + "\\report\\";
        public ReportViewer(string fileName)
        {
            InitializeComponent();
 
            doc = new ReportDocument();
            doc.Load(path + fileName);
            
            ConnectionInfo info = new ConnectionInfo();
            info.UserID = "UserId";
            info.Password = "Password";
            info.ServerName = "ServerName";
            info.DatabaseName = "DatabaseName";
            info.IntegratedSecurity = false;
            info.Type = ConnectionInfoType.SQL;
 
            SetLogonTables(doc.Database.Tables, info);
 
            Subreports mySubReports = doc.Subreports;
            foreach (SubreportObject s in mySubReports)
            {
                ReportDocument subDoc = s.OpenSubreport(s.SubreportName);
                SetLogonTables(subDoc.Database.Tables,info);
                
            }
            this.crystalReportViewer1.ReportSource = doc;
        }
        private void SetLogonTables(Tables myTables, ConnectionInfo info)
        {
            foreach (Table myTable in myTables)
            {
                TableLogOnInfo myTableLogonInfo = (TableLogOnInfo)myTable.LogOnInfo.Clone();
                myTableLogonInfo.ConnectionInfo.AllowCustomConnection = true;
 
                myTableLogonInfo.ConnectionInfo.DatabaseName = info.DatabaseName;
                myTableLogonInfo.ConnectionInfo.ServerName = info.ServerName;
                myTableLogonInfo.ConnectionInfo.UserID = info.UserID;
                myTableLogonInfo.ConnectionInfo.Password = info.Password;
                myTableLogonInfo.ConnectionInfo.IntegratedSecurity = info.IntegratedSecurity;
                myTableLogonInfo.ConnectionInfo.Type = info.Type;
 
                myTable.ApplyLogOnInfo(myTableLogonInfo);
            }
        }
                                              
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by: LefarfadaisPosted on 2009-10-13 at 08:13:07ID: 25560844

Good day

After further searches, I finally found an answer to my question.

The code was right, I was doing ok all the time. Only 1 exception.

When building your Crystal Report, make sure you build it using an SQL security account. If you use Integrated Security  while building the report, any changes will be applying the Integrated security.

20120131-EE-VQP-002

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