If you are using SQL then simly use substring as below
Substring('1482~0022~000~4
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Browse All TopicsI want to scan the string from right to left and fetch the string that is before the last delimiter.
Consider the strings
1482~0022~000~4346~1
1700~3421~000~7811~8
I need to fetch 4346 and 7811 from the above strings.
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by: mlmccPosted on 2008-09-24 at 19:15:55ID: 22565810
What are you programming in?
') ',FirstTil de) dTilde,Fir stTilde-Se condTilde)
VB has a InStrReverse function you could use.
InStrRev(string1, string2 [, start] [, compare])
Something like
Dim FirstTilde As Integer
Dim SecondTilde As Integer
Dim ReturnString as String
FirstTilde = InStrRev(StringToSearch,'~
If FirstTilde > 0 then
SecondTilde = InStrRev(StringToSearch,'~
ReturnString = MidStr(StringToSearch,Secn
else
ReturnString = ''
end if
mlmcc