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08.23.2008 at 01:07AM PDT, ID: 23672111
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9.7

Function return type

Asked by MacroLand in C++ Programming Language, C Programming Language, Microsoft Visual C++

Tags:

Dear All,

I have a simple question but I am really confused on this. Assume a class,

class Matrice
{
// some code
}

and a function which is declared as friend to this class.

template <class T> CMatrice<T> operator+(const CMatrice<T>& a, const CMatrice<T>& b)
{
      //some code
      CMatrice<T> addition(row,col);
      //some code

      return addition; //this part confuses me
}

The addition variable inside the function is declared on the stack. When this function returns it should go out of the scope. To my understanding a code such as;

CMatrice<T> c=Class_a+Class_b;  

assuming both a and b are matrix class should not work. Because when this function ends the destructor for the addition will be called and everything belong to it will be destroyed. However, the code below works fine.

My other simple question will be;

Assume a function

CColVector and CRowVector are subclasses of CMatrice

template<typename T> CRowVector<T>& CColVector<T>::Transpose()
{
      CRowVector<T>* r=new CRowVector<T>(this->row);
      //some code

      return *r;
}

The r variable will be on the heap and I am returning a reference to it. How should I delete the r variable from the heap. Or is it automatically deleted when the variable assigned to function goes out of scope?


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[+][-]08.23.2008 at 01:16AM PDT, ID: 22296198

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[+][-]08.23.2008 at 01:19AM PDT, ID: 22296202

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[+][-]08.23.2008 at 01:27AM PDT, ID: 22296219

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[+][-]08.23.2008 at 05:43AM PDT, ID: 22296695

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Zones: C++ Programming Language, C Programming Language, Microsoft Visual C++
Tags: C++
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Solution Provided By: itsmeandnobodyelse
Participating Experts: 2
Solution Grade: A
 
 
[+][-]08.23.2008 at 04:22PM PDT, ID: 22298883

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[+][-]08.23.2008 at 04:52PM PDT, ID: 22298961

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