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04.18.2008 at 10:22AM PDT, ID: 23334898 | Points: 50
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Attachment Details

Math Riddle

Tags: Puzzle/Riddle
A friend gave me a puzzle that he is trying to solve and I haven't even began to figure it out and neither has he.  It's going to drive me crazy not knowing what the solution is so if anybody has any clues that would be great.  I tried to google the answer after trying to solve it for a while but only found a website where they ask the question.  So....

How would you get this
   To be or not to be
From this
   3 7 25438 819 7 158

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Question Stats
Zone: Gamers
Question Asked By: tim_cs
Question Asked On: 04.18.2008
Participating Experts: 4
Points: 50
Views: 0
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04.18.2008 at 11:53AM PDT, ID: 21388611

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04.18.2008 at 01:06PM PDT, ID: 21389178

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04.18.2008 at 01:13PM PDT, ID: 21389232

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04.18.2008 at 01:34PM PDT, ID: 21389419

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04.19.2008 at 07:33PM PDT, ID: 21394831

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04.20.2008 at 12:18AM PDT, ID: 21395257

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04.20.2008 at 01:26AM PDT, ID: 21395355

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04.20.2008 at 02:23AM PDT, ID: 21395458

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04.20.2008 at 02:25AM PDT, ID: 21395462

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04.20.2008 at 08:41AM PDT, ID: 21396431

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04.20.2008 at 10:28AM PDT, ID: 21396856

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04.20.2008 at 11:32AM PDT, ID: 21397119

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04.20.2008 at 11:45AM PDT, ID: 21397173

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04.20.2008 at 12:24PM PDT, ID: 21397289

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04.20.2008 at 03:34PM PDT, ID: 21397827

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04.20.2008 at 04:26PM PDT, ID: 21397972

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04.20.2008 at 04:46PM PDT, ID: 21398010

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04.18.2008 at 11:53AM PDT, ID: 21388611
looks like fun, the site I found was presumably the same as the one you had where only a handful of people seem to have solved it.
So as not to spoil other peoples fun I wonder if a solution was found here that it could be hinted at but not posted directly?

The first thing I thought of was that I had seen it written as '2b||!2b', not sure if that has anything to do with it though.
 
04.18.2008 at 01:06PM PDT, ID: 21389178
I see 13 letters in 'to be or not to be' but only 6 symbols used. The code has 6 groups of letters although it is a bit of a staller that 25438 won't divide by 4...
 
04.18.2008 at 01:13PM PDT, ID: 21389232

Rank: Master

Suppose that more than 26 groups of numbers were to occur......
 
04.18.2008 at 01:34PM PDT, ID: 21389419
>Suppose...

I did wonder, and the site that offers this problem has a code to be solved with 54 groups of numbers.
Must be something else then... I'm trying to squeeze some prime numbers in there at the moment.
 
04.19.2008 at 07:33PM PDT, ID: 21394831

Rank: Genius

If you let
t=3
o=7
b=2
e=79
r=23
n=13
then
t   o   b*e*o*r   n*o*t*t   o  b*e
=
3 7 25438 819 7 158
But that also works if
b=79 and e=2
 
04.20.2008 at 12:18AM PDT, ID: 21395257

Rank: Genius

I'd guesss that e=2 and b=79,  that letters appearing more frequently in english are assigned to smaller primes, and that letters in each number are presented in alphabetical order
 
04.20.2008 at 01:26AM PDT, ID: 21395355

Rank: Genius

It looks like the letter order used was close to linotype order with a few minor changes.
It may be easier to recognize the solution if you speak Bantu
 
04.20.2008 at 02:23AM PDT, ID: 21395458
ozo,

for the code given here http://www.scouting.org.za/codes/prize.html:

3 2261 86 133 19 365 6 23 365 1922 2 70499 259 3 19 6095 11 41 325 493 61 78 17 7 47 6 517 286 3053 505 37 1147 13 15 7285 11 3819 19 365 146 187 33 2 87 19 146 4805 118 7 53 4147 1111 37 1147

factorizing the numbers and using the code you proposed appears to produces unintelligible text.
for example "365 6 23 365" and "87"  has an awful lot of t's clustered together. but ofcourse i could be wrong.

since the lesser primes are most common i imagine 2,3 and 7 to be the most commonly used alphabets.  
 
04.20.2008 at 02:25AM PDT, ID: 21395462
> since the lesser primes are most common i imagine 2,3 and 7 to be the most commonly used alphabets.

on second thought this needn't apply here.
 
04.20.2008 at 08:41AM PDT, ID: 21396431

Rank: Genius

if t=3, the only factor of 3 in 365 6 23 365" and "87" is  2*3
 
04.20.2008 at 10:28AM PDT, ID: 21396856
aarh! sorry about that, i was scribbling on a used piece of paper and lost track.

 
04.20.2008 at 11:32AM PDT, ID: 21397119

Rank: Genius

there is a factor of 3 in "87" but it's not in a cluster
 
04.20.2008 at 11:45AM PDT, ID: 21397173
ozo,

> there is a factor of 3 in "87" but it's not in a cluster

sure. anyway, the caculation i had done earlier was totally messed up. :-)

I thought it might help so here's what the code the decomposition and alphabet subtitution (done with a script and double-checked):

(T)  (O,17,19)  (E,43)  (O,19)  (19)  (5,73)  (E,T)  (R)  (5,73)  (E,31,31)  (E)  (11,N,17,29)  (O,37)  (T)  (19)  (5,R,53)  (11)  (41)  (5,5,N)  (17,29)  (61)  (E,T,N)  (17)  (O)  (47)  (E,T)  (11,47)  (E,11,N)  (43,71)  (5,101)  (37)  (31,37)  (N)  (T,5)  (5,31,47)  (11)  (T,19,67)  (19)  (5,73)  (E,73)  (11,17)  (T,11)  (E)  (T,29)  (19)  (E,73)  (5,31,31)  (E,59)  (O)  (53)  (11,N,29)  (11,101)  (37)  (31,37)

note that B(=79) doesn't appear at all. and also there are precious little text substitutions to go on with.
 
04.20.2008 at 12:24PM PDT, ID: 21397289

Rank: Genius

This is not the exact order
http://en.wikipedia.org/wiki/ETAOIN_SHRDLU
but it may be close enough to figure out when you realize where scouting.org.za is located
 
04.20.2008 at 03:34PM PDT, ID: 21397827
thanks for the tip.

one has to guess the correct order (http://deafandblind.com/word_frequency.htm) so its still tricky.

spotted the word scout so looks like c=29.



 
04.20.2008 at 04:26PM PDT, ID: 21397972

Rank: Genius

None of those is the exact order used, but some may be close enough so you can adjust the rest.

I don't believe that c=29 is correct
the solution I get does not contain the word "scout"
 
04.20.2008 at 04:46PM PDT, ID: 21398010

Rank: Genius

If you thought c=29 produced the word "scout", you may have missed what I said about alphabetical order
 
 
20080236-EE-VQP-29 / EE_QW_2_20070628