ANSWER:
You are using 4218 Watts which is 14397 BTU/hr.
Your APC has a load of (208.2 * 28.14) * 0.72 Watts = 4218.3 Watts.
One Watt is 3.413 BTU/hr.
4218.3 Watts = 14397 BTU/hr.
Watt and BTU/hr is a rate of energy, and BTU is an amount of energy.
NOTES:
You APC has a load of (208.2 * 28.14) = 5858.7 VA (Volt Amps).
"58.0 %VA" is the percent of the maximum VA that your APC can deliver.
(5858.7 / 0.58) is about 10000, so your APC is probably rated a maximum of 10000 VA.
VA is also called "apparent power". Watt is real power.
Power Factor = Watts / VA
Watts = VA * Power Factor
"072.0 % Watts" means that the power factor is 0.72.
This means that the actual heat energy being dissipated by the load (and what the power company is billing you for) is 72% of the VA.
The load is using (0.72 * 5858.7) = 4218.2 Watts.
Why is the power factor not 1.0?
Because the load probably contains inductors or capacitors (causing a phase shift) or a non-linear (voltage and current waveform are different) load.
If the load was resistive (like a space heater) then the power factor would be about 1.0.
The difference between the input and output voltage (210.2 - 208.2) = 2.0V is probably just a voltage drop in the APC electronics and connectors.
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by: oobaylyPosted on 2009-03-30 at 16:49:49ID: 24024574
Well, assuming that it's drawing 28.14A (Load Current), the power is:
P = VA = 210.2V * 28.14A = 5.915kW
In one hour, it will use 5.915kWhr (units) of electricity.
1kWhr = 3413BTU
So in one hour it's using 20.2 * 10^6 BTU
This has to be one hefty ups as the a big current it's drawing.
Though it may be using 72% of a load current of 28.14A, so (only) 14.54 * 10^6 BTU