I think I understand the connectivity rule with Ethernet: 10Base2, 10Base5 and 10Base-T...
There are only maximum 5 segments between any two terminal nodes.
There are only maximum 4 repeaters between any two terminal nodes.
There are only three segments could be used to connect nodes.
There are two inter-hub segments could not be used to connect nodes.
There forms one collision domain that could contain maximum 1024 nodes.
How does this apply with Class I and Class II Repeaters and switches along with 100 base-TX? Is there even another newer class? Are the rules the same?
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Keep in mind that 5-4-3 was originally a rule of thumb for dealing with 10Base2 networks. Given the amount of variance in bit times with 100/1000 megabit Ethernets, as well as the difference in propagation with TP and fiber versus coax, the rule's practical use degrades rapidly.
If you throw a bridge/switch port (...and a dual-speed hub generally includes a bridge - if you traverse the two speeds, of course) then you can pretty much keep cascading.
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thanks,
lrmoore
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by: contrazoomPosted on 2001-10-22 at 07:03:29ID: 6554532
Suppose we talk about copper only (UTP)
Class I repeaters you cannot cascade (or daisychain)so
PC -- 100m UTP -- class I rep --100m UTP -- PC
Class II repeaters you can connect two but your network diameter may not be larger than 205m so
PC --100m UTP--Class II--5m UTP--Class II--100m UTP--PC
Switches are a different story: since they can work full duplex collisions do no longer play. You can for instance cascade 7 switches or even more. The rule in IEEE 802.1D
(spanning tree) states that you cannot have more than 7 switches in a ring topology.
Have a look here:
http://wwwhost.ots.utexas.
Cisco also has some good info:
http://www.cisco.com/unive
enjoy
contrazoom