October 13, 2008 12:36am pdt

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5. logudotcom 335,451
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7. Squinky 256,490
8. RQuadling 250,798
9. glcummins 247,535
10. ddrudik 234,574
11. routinet 229,492
12. nplib 221,264
13. bportlock 154,021
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18. darron_c... 126,316
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1. hernst42 2,408,793
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3. hielo 1,668,774
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7. angelIII 938,569
8. RQuadling 792,500
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13. Batalf 452,611
14. nizsmo 437,234
15. Zyloch 433,586
16. routinet 393,304
17. yodercm 393,022
18. Ray_Pas... 392,771
19. nicholass... 391,903
20. b0lsc0tt 366,871
21. logudotcom 360,163
22. gamebits 343,571
23. MasonWolf 331,658
24. nplib 326,749
25. dr_dedo 326,740

04.19.2008 at 01:13PM PDT, ID: 23336986

	[x] Attachment Details

[x]

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8.0

display images from directory in PHP loop

Asked by satmanuk in PHP Scripting Language

hi all,

i have a dynamic form where i am trying to show images from a directory in the last column of my table.

My table is dynamic because it has as many records as there are images within a chosen directory.

Something i want to add is showing each image in the last column of the table.

If you look at my code in the loop you will see i am echo'ing a fixed image at the moment. So naturally this same image is displayed on each row.

This image needs to be different on each row and in total all images in the chosen folder($dir) will be listed.

Hope im making senseStart Free Trial

         
           
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             <?php
 
// declare what url to look in and count each file within that directory
$dir = "images/temp/member/";
$count = count(glob($dir . "*"));
 
 
// test if count has found the files in the temp image dir.
echo "count is";
echo $count;
 
 
// Open the folder for display
$dir_handle = @opendir($dir) or die("Unable to open $dir");
 
 
 
// asign the amount of files in the temp dir above to the variable $nFish
$nFish = $count;
 
echo "<form id=\"form1\" name=\"form1\" method=\"post\" action=\"array3.php\">\n";
echo "  <table width=\"600\" border=\"0\">\n";
echo "    <tr>\n";
echo "      <td><p>Amount of Fish (" . $nFish . ")</p>\n";
echo "      <p>&nbsp; </p></td>\n";
echo "      <td>fish_type</td>\n";
echo "      <td>bait</td>\n";
echo "      <td>notes</td>\n";
echo "      <td>Date</td>\n";
echo "      <td>Image Preview</td>\n";
echo "    </tr>\n";
 
 
 
for ($i = 1; $i <= $nFish; $i++) {
  echo "    <tr>\n";
  echo "      <td><div align=\"center\">" . $i . "</div></td>\n";
  echo "      <td><input name=\"fish_type_$i\" type=\"text\" id=\"fish_type_$i\" /></td>\n";
  echo "      <td><input name=\"bait_$i\" type=\"text\" id=\"bait_$i\" /></td>\n";
  echo "      <td><input name=\"notes_$i\" type=\"text\" id=\"notes_$i\" /></td>\n";
  echo "	  <td><input type=\"text\" id=\"date$i\" name=\"date$i\" /></td>\n";
  echo "	  <td><button id=\"trigger\">Click here for Calendar</button></td>";
  echo "	  <td><img src=\"images/bart_logo.jpg\" width=\"264\" height=\"102\" /></td><br>";
  echo "    </tr>\n";
?>
<script type="text/javascript">
  Calendar.setup(
    {
      inputField  : "date<?php echo $i; ?>",         // ID of the input field
      ifFormat    : "%Y-%m-%d",    // the date format
      button      : "trigger"       // ID of the button
    }
  );
</script>
 
<?php  
  echo "    </tr>\n";
}
 
echo "    <tr>\n";
echo "      <td colspan=\"4\"><div align=\"center\">\n";
echo "        <input type=\"submit\" name=\"Submit\" value=\"Submit\" />\n";
echo "      </div></td>\n";
echo "    </tr>\n";
echo "  </table>\n";
echo "</form>\n";
 
?>

           
         

Keywords: display images from directory in PHP loop

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3	remove duplicate data within a row (n…
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5	How do you loop through the columns …
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display images from directory in PHP loop

Asked by satmanuk in PHP Scripting Language

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