Question

Nested If Statement in SQL

Asked by: BG33

I am trying to query a database whereby two variables are met, however the two variables are from the same field eg:

SELECT rotas.day_of_week, staff.staff_name, rotas.bk_date, rotas.short_name, , rotas.description,
FROM rotas, staff
WHERE (((rotas.short_name)=[enter name]) AND ((rotas.description) AND ((rotas.year_number)=[enter year]) AND ((rotas.week_number)=[enter weeks]) AND
           rotas.description In (select rotas.description
            from rotas                                        
            where ((rotas.description)="PDO")) And (rotas.description)
            rotas.description In (select rotas.description                                        
            from rotas                                      
            where ((rotas.description)="UDO")))
ORDER BY rotas.bk_date;

Basically I am searhing for a rota where the person has the weekend off (PDO or UDO denote this) There for I am trying to query the database whereby Saturday is either UDO or PDO and Sunday is either UDO or PDO.

thanks
B

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Asked On
2003-05-08 at 03:38:51ID20609686
Topic

MS SQL Server

Participating Experts
6
Points
500
Comments
10

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Answers

 

by: xnmbPosted on 2003-05-08 at 04:32:16ID: 8487488

i'm sorry couldn't quite understand your current query. could you possibly post the definitions of table(s) concerned?

xnmb

 

by: KelvinYPosted on 2003-05-08 at 05:29:27ID: 8487891

It sounds like you need something like

SELECT rotas.day_of_week, staff.staff_name, rotas.bk_date, rotas.short_name, rotas.description,
FROM rotas INNER JOIN staff ON rotas.short_name = staff.short_name
WHERE (((rotas.short_name)=[enter name]) AND ((rotas.year_number)=[enter year]) AND ((rotas.week_number)=[enter week]) AND           rotas.description In ("PDO", "UDO")
ORDER BY rotas.bk_date;

I'm taking a bit of a guess at some things because you haven't provided any information about your tables, so I'm assuming you have a common field in your staff and rotas tables that identifies the staff member. In this case I've assumed the field is called short_name. If your using an ID field instead then your query would become something like;

SELECT rotas.day_of_week, staff.staff_name, rotas.bk_date, rotas.short_name, rotas.description,
FROM rotas INNER JOIN staff ON rotas.staff_id = staff.staff_id
WHERE (((rotas.short_name)=[enter name]) AND ((rotas.year_number)=[enter year]) AND ((rotas.week_number)=[enter week]) AND           rotas.description In ("PDO", "UDO")
ORDER BY rotas.bk_date;

 

by: lauszPosted on 2003-05-08 at 07:24:30ID: 8488858

I cant' understand this part ...

(rotas.short_name)=[enter name])

???? AND ((rotas.description) AND ????


 

by: hollerithPosted on 2003-05-08 at 07:42:08ID: 8489010

select * from staff s inner join rotas r on r.staff_name = s.staff_name and r.description in ('PDO','UDO') and (r.day_of_week = 6 or r.day_of_week = 7)

or
The set of all staff who have rotas with PDO or UDO on day 6 or 7

Or perhaps we don't understand the question...

 

by: BG33Posted on 2003-05-09 at 03:36:18ID: 8494526

Apologies but I don't think I have explained this very well. The code below extracts the Saturdays or Sundays an employee has off in a year. Days off are marked in the rotas.description field as 'UDO' or 'PDO'. What I need is SQL to run in MS Access that will allow me to group Saturday and Sunday together ie: Weekend, and search the database for all the weekends a member of staff has off in 1 year, ie: an employee has both Saturday and Sunday off not Saturday or Sunday. Therefore the day of the week is 1 and 2 and the rota.description is UDO and PDO.

SELECT rotas.day_of_week, staff.staff_name, rotas.bk_date, rotas.short_name, DayDescriptiontbl.DayFullName, rotas.description, rotas.year_number, rotas.week_number
FROM DayDescriptiontbl INNER JOIN (staff INNER JOIN rotas ON staff.short_name = rotas.short_name) ON DayDescriptiontbl.DayNumber = rotas.day_of_week
WHERE (((rotas.day_of_week)=1 Or (rotas.day_of_week)=2) AND ((rotas.short_name)=[enter name]) AND ((rotas.description)="UDO" Or (rotas.description)="PDO") AND ((rotas.year_number)=[enter year]) AND ((rotas.rota_status)<>"X"))
ORDER BY rotas.bk_date;

thanks
B

 

by: higginspiPosted on 2003-05-09 at 13:12:46ID: 8497103

How is your data structured?
I.E., post some sample data from DayDescriptiontbl, rotas, staff, etc.

 

by: higginspiPosted on 2003-05-09 at 13:53:53ID: 8497236

If I had some sample data I could make a better query specific for your needs. But, it lookes like you might have a date that they took off and a hard coded weekday number.  It looks like 1=Saturday and 2=Sunday.  If this is not true, then Change "1" in the query to saturday's number on both lines.

The reasoning behind the query is that for a person to have a weekend off they must have Saturday (1) off.  So first the Saturday people are selected, and then only the ones that also have a record for the very next day are select (OffDate+1).

SELECT ID, OffDate, OffDate+1
FROM YourTable as A
where [Day of Week]=1
and exists (select [Day of Week], OffDate
from YourTable as B
where A.[Day of Week]=1
and B.OffDate=A.OffDate+1
and A.ID=B.ID);

This will select the person's ID and weekend they were off; one for each weekend.

If you want to count the weekends then:
SELECT A.ID, Count(*) AS Expr1
FROM YourTable AS A
WHERE (((A.[Day of Week])=1) AND ((Exists (select [Day of Week], OffDate
from YourTable as B
where A.[Day of Week]=1
and B.OffDate=A.OffDate+1
and A.ID=B.ID))<>False))
GROUP BY A.ID;

If you want to select for a certain date range, you can add that range to the where clause(s).
For example, if you specify where year(DateOff)=2002 in the main clause, it might pick up Jan 1, 2003 if Dec31 and Jan1 were on a week end if it is absent from the subquery's where clause.  So you might want to put the date restrictions in both places, or one or the other depending on what you need.

I hope that helps you modify your existing query into something that will work.  If you want to post some sample data I will try to look at it Monday and make a better query.
Have a great weekend! :-)

 

by: CleanupPingPosted on 2003-09-03 at 04:14:00ID: 9274500

BG33:
This old question needs to be finalized -- accept an answer, split points, or get a refund.  For information on your options, please click here-> http:/help/closing.jsp#1
EXPERTS:
Post your closing recommendations!  No comment means you don't care.

20120131-EE-VQP-002

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