http://home.capecod.net/~p
http://home.capecod.net/~p
Some good algorithms there.
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Could someone tell me how what the syntax is to convert a Julian date to a regular date format in SQL? Thanks.
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http://home.capecod.net/~p
http://home.capecod.net/~p
Some good algorithms there.
Are you sure it's a Julian date and not Julian Date number? Most people easily confuse the two. If it is a Julian Day Number, then this formula will always work;
dateadd(dd, (JDN-2415021), convert(datetime, '1900-01-01',103)), where JDN is the Julian Day Number you're trying to convert.
For 27 Aug 2003, you have a JDN of 2452879;
dateadd(dd, (2452879-2415021), convert(datetime, '1900-01-01',103)) will return 27 Aug 2003
If you need a number of years before 1900, simply subtract the number of DAYS to the year you want your data from 2415021, which I've used as a constant for the date 01 Jan 1900. For example, if your base date was 01-01-1890, then your formula would look like;
dateadd(dd, (JDN-2411369), convert(datetime, '1890-01-01',103)), where 3652 days have been subtracted from 2415021. (1 Jan 1890 occurred 3652 days before 01 Jan 1900, including leap years)
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by: bruintjePosted on 2003-08-26 at 08:03:16ID: 9224620
if you're juliandates are like 2003200 then you could try something like
select NormalDate = dateadd ( dd , ( 2003200 % 1000 ) - 1 , convert ( datetime ,convert( char(4) , 2003200 / 1000 ) + '/01/01') )