Question

Select top n records by categories (group by)

Asked by: geotiger

I have a table with many columns, and here are the relevant ones:

group_id
user_name
task_id
task_type
action_dt_tm
caller_id
...

Each user will perform many tasks in a day. What I need to know is the most recent tasks (the most recent 2, 3, or 4 tasks) performed by each user in each group with all the other information along with the tasks. So what I need to get is top n records sorted by action_dt_tm desc by group_id and user_name.

T-SQL offers 'top n' but does not allow group by. The following SQL statement does not work since many columns are not in group by clauses

Select * from all_action
group by group_id, user_name
order by group_id, user_name, action_dt_tm

I am looking for solution in t-sql and also willing to accept solution in PL/SQL.

Thanks.

GT

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Asked On
2003-12-19 at 08:32:22ID20830651
Tags

top

,

group

,

select

,

n

Topic

MS SQL Server

Participating Experts
4
Points
250
Comments
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Answers

 

by: shivsaPosted on 2003-12-19 at 08:35:04ID: 9973156

Select * from all_action
group by group_id, user_name
order by group_id, user_name, action_dt_tm limit n

where n could be your number for top record like 10/20..

 

by: geotigerPosted on 2003-12-19 at 08:47:08ID: 9973247

Shivsa,

First of all, t-sql does not offer 'limit' in order by clause. Secondly, there are columns not in group by such as task_type and caller_id.

Thanks for your quick response.

GT

 

by: ScottPletcherPosted on 2003-12-19 at 08:52:18ID: 9973289

What is the unique key for this table?

Is task_id unique or is it by group_id?

 

by: ScottPletcherPosted on 2003-12-19 at 08:53:18ID: 9973293

That is, is task_id unique or can the the same task_id appear for each group_id?

 

by: ScottPletcherPosted on 2003-12-19 at 08:59:57ID: 9973331

At any rate, try something like this:


SELECT *
FROM yourTable yt1
WHERE action_dt_tm IN (
      SELECT TOP 4 action_dt_tm
      FROM yourTable yt2
      WHERE yt1.[user_name] = yt2.[user_name]
      AND yt2.group_id = yt2.group_id
      ORDER BY action_dt_tm DESC )
ORDER BY group_id, user_name, action_dt_tm

 

by: shivsaPosted on 2003-12-19 at 09:19:42ID: 9973445

will this work.
-----------
Select * from all_action
group by group_id, user_name
order by group_id, user_name, action_dt_tm  HAVING COUNT(*) = n

 

by: vc01778Posted on 2003-12-19 at 09:45:05ID: 9973661

geotiger,

Given the table T1,

the query will look like this:

select t1.*
from t1 join
  (select a.group_id, a.user_name,  a.action_dt_tm from
    (select group_id, user_name, action_dt_tm from t1) a
    join
    (select group_id, user_name, action_dt_tm from t1) b
    on a.group_id=b.group_id and a.user_name=b.user_name and a.action_dt_tm <= b.action_dt_tm
    group by a.group_id, a.user_name,  a.action_dt_tm having count(*) <= 1)  x
    on x.group_id=t1.group_id and x.user_name=t1.user_name and x.action_dt_tm=t1.action_dt_tm
order by t1.group_id, t1.user_name, t1.action_dt_tm desc


Rgds.

VC

 

by: vc01778Posted on 2003-12-19 at 09:49:20ID: 9973693

geotiger,

Sorry pressed 'Send'  too fast...

The parameter for the top records should be specified in the 'having  count(*)'  clause.

E.g.  having count(*) <= 4/8/etc.  for the first four and eight records.   The big subquery determines a combination of (user_name,  group_id and action_dt_tm) for the first N records and the result is joined with the original T1 table getting you all the columns from T1.  N is the parameter for 'having count(*)<= N.


Rgds.

VC

 

by: ScottPletcherPosted on 2003-12-19 at 09:49:45ID: 9973698

CORRECTION (in subquery WHERE clause, the first yt2.group_id should be yt1.group_id):

SELECT *
FROM yourTable yt1
WHERE action_dt_tm IN (
     SELECT TOP 4 action_dt_tm
     FROM yourTable yt2
     WHERE yt1.[user_name] = yt2.[user_name]
     AND yt1.group_id = yt2.group_id  
     ORDER BY action_dt_tm DESC )
ORDER BY group_id, user_name, action_dt_tm


VC:
Won't the query above work?
Isn't the "having count(*) <= 1" going to prevent your query from returning results?

 

by: vc01778Posted on 2003-12-19 at 09:54:10ID: 9973732

geotiger,

An alternative is:

select * from (
  select x.*,
       (select count(*) from t1 where group_id=x.group_id and user_name=x.user_name and action_dt_tm <= x.action_dt_tm) cnt
  from t1 x) y
where cnt <=  N,  where N is 2/4/6/..etc


But it may be slower than my first version.

VC

 

by: vc01778Posted on 2003-12-19 at 09:55:39ID: 9973741

ScottPletcher,

It will work;  it will return the first most recent record.  I explained how it works in my second message.

VC

 

by: vc01778Posted on 2003-12-19 at 10:11:14ID: 9973869

geotiger,

Sorry ,  I reversed the comparison in my secnd version.  It should be like this:

select * from (
  select x.*,
       (select count(*) from t1 where group_id=x.group_id and user_name=x.user_name and action_dt_tm >= x.action_dt_tm) cnt
      
  from t1 x)
where cnt <= 1


@ScottPletcher,

Your query is also fine... It will work.

VC

 

by: vc01778Posted on 2003-12-19 at 10:14:29ID: 9973886

ScottFetcher,

Your query as well as my second version will be less performant on big data volumes then the 'ugly' join version as they run a correlated subquery for every row -- yours in the where part and mine in the select clause.

That's why I prefer the join version.

Rgds.

VC

 

by: ScottPletcherPosted on 2003-12-19 at 11:39:36ID: 9974533

But your subquery is doing essentially the same comparison, so I don't think there'd be a noticeable performance difference.  In fact, I'm almost certain that a method with a derived table also will be slower than my method.

 

by: vc01778Posted on 2003-12-19 at 11:53:17ID: 9974637

I actually checked ;)

The merge join (my first query with a derived table)  is faster than the correlated subquery(mine  and yours) for about 1000 rows.  I analyzed the table.

VC

 

by: geotigerPosted on 2003-12-19 at 13:00:54ID: 9975058

Thanks, VC and SP!

I will test on my system to see which one works better.

GT

 

by: vavjeevaPosted on 2009-11-02 at 23:29:32ID: 25726668

we could use RANK() Partiion By for Selecting TOP N rows by group..

Returns the rank of each row within the partition of a result set. The rank of a row is one plus the number of ranks that come before the row in question.

Definition from Microsoft
Returns the rank of each row within the partition of a result set. The rank of a row is one plus the number of ranks that come before the row in question.

Syntax
CODE
RANK ( )    OVER ( [ < partition_by_clause > ] < order_by_clause > )


Example
CODE
USE AdventureWorks;
GO
SELECT i.ProductID, p.Name, i.LocationID, i.Quantity
    ,RANK() OVER
    (PARTITION BY i.LocationID ORDER BY i.Quantity DESC) AS 'RANK'
FROM Production.ProductInventory i
    INNER JOIN Production.Product p
        ON i.ProductID = p.ProductID
ORDER BY p.Name;


We also have DENSE_RANK method which is almost similar to RANK but it does not provide the GAPS between the Rank whereas other one does.
Example
http://www.sqlservercurry.com/2009/04/rank...mple-using.html

One of the best example for Rank is here

http://weblogs.sqlteam.com/jeffs/archive/2...3/28/60146.aspx

http://forum.only4gurus.org/index.php?automodule=blog&blogid=1&showentry=369

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