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01.15.2007 at 07:22AM PST, ID: 22122982
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7.8

How to split a sentence, and display results based on the words

Asked by mousemat24 in MS SQL Server

Tags:

Hi there,

Wonder if you can help me?

I have the following Stored procedure:

@GUID            varchar(16),
@LOS            varchar(16),
@CostCentre      varchar(16),
@BusinessUnit      varchar(16),
@Grade      varchar(16),
@Search      varchar(300)

select *,
ISNULL(MNU_Menu.MNU_CNT_ID + '&id=' + CONVERT(VARCHAR,MNU_Menu.MNU_ID),CONVERT(VARCHAR(100),con.CNT_ID) + '&id=1') AS ID
from cnt_content con
    CROSS JOIN MNU_Menu
where  convert(varchar(800),con.cnt_id) in (SELECT SUBSTRING (dbo.MNU_Menu.MNU_URL, CHARINDEX('{',dbo.MNU_Menu.MNU_URL)+1, 36)
FROM         dbo.MNU_Menu INNER JOIN
                      dbo.ACL_AccessControl ON dbo.MNU_Menu.MNU_ID = dbo.ACL_AccessControl.ACL_MNU_ID INNER JOIN
                      dbo.ROL_Roles ON dbo.ACL_AccessControl.ACL_ROL_ID = dbo.ROL_Roles.ROL_ID INNER JOIN
                      dbo.USR_Users ON dbo.ROL_Roles.ROL_ID = dbo.USR_Users.USR_ROL_ID INNER JOIN
                      dbo.UST_UserType ON dbo.USR_Users.USR_UST_ID = dbo.UST_UserType.UST_ID CROSS JOIN
                      dbo.CNT_Content
WHERE     dbo.USR_Users.USR_Name = @GUID) and con.cnt_body like ('%'+@Search+'%') and MNU_Menu.MNU_CNT_ID like '%'+CONVERT(VARCHAR(100),con.CNT_ID)+'%'
ORDER BY con.cnt_title ASC
GO


What this does it will search based on what ever the user enters i.e. @Search. It all works ok, so if the user entered

apple orange

It will bring back all records that have the sentence "apple orange"

Can someone please help me in changing this, so that if a user enters

apple orange

it will display all records that have a "apple" OR "orange"

and of course, the user can type x amonunt of words

Hope that  makes sense?
Thanks
Mosuemat24Start Free Trial
 
Keywords: How to split a sentence, and display r…
Title
1 Sentence
2 Regex: Extract sentences from parag…
3 SQL sentence
4 SQL sentence
5 Find a sentence
6 Join sentence...
 
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[+][-]01.15.2007 at 08:01AM PST, ID: 18316892

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About this solution

Zone: MS SQL Server
Tags: split
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Solution Provided By: PFrog
Participating Experts: 2
Solution Grade: A
 
 
[+][-]01.15.2007 at 09:53AM PST, ID: 18317792

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