Advertisement

08.26.2007 at 07:43PM PDT, ID: 22788370
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!

9.0

UDF SubtractWorkingDays not working properly...

Asked by Enflow in MS SQL Server

SQL Server: UDF Subtract Working Days not working properly... going back one too many weekends from what i can see...

If you call this function from the Query Analyser using

Select dbo.subtractworkingdays('20070828',20) as FirstDateToUse

you get 07-27-2007, instead of 07-30-2007.  We expect to see 07-30-2007.

CREATE FUNCTION dbo.SubtractWorkingDays
( @StartDate DATETIME,
@Days INT )

RETURNS DATETIME

AS

BEGIN
DECLARE @EndDate DATETIME
DECLARE @FirstPart INT
DECLARE @RealNumerOfDays INT

SELECT @FirstPart = CASE DATENAME(weekday, @StartDate)
WHEN 'Sunday' THEN 0
WHEN 'Monday' THEN 0
WHEN 'Tuesday' THEN 1
WHEN 'Wednesday' THEN 2
WHEN 'Thursday' THEN 3
WHEN 'Friday' THEN 4
WHEN 'Saturday' THEN 5
END


IF ((@FirstPart - @Days) >= 0)
BEGIN
--
-- If the number of days to subtract does not go over a weekend
then
-- just do the subtraction
--
SELECT @EndDate = DATEADD( DAY, @Days *-1, @StartDate )
END
ELSE
BEGIN
--
-- If the number of days to subtract does go over a weekend
then
-- work out the number of weekend days to remove
--
SELECT @RealNumerOfDays = (((@Days) / 5) + 1) * 2

SELECT @EndDate = DATEADD( DAY, (@Days + @RealNumerOfDays) *-1,
@StartDate )
END

RETURN ( @EndDate )
ENDStart Free Trial
[+][-]08.26.2007 at 08:29PM PDT, ID: 19773580

View this solution now by starting your 7-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

 

About this solution

Zone: MS SQL Server
Sign Up Now!
Solution Provided By: StephenCairns
Participating Experts: 1
Solution Grade: A
 
 
[+][-]08.27.2007 at 09:39AM PDT, ID: 19776577

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 7-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]09.03.2008 at 02:11AM PDT, ID: 22375221

Experts Exchange has a courteous staff of administrators who help members get the most out of the website by means of administrative comments like this one.

Start your 7-day free trial to view this Administrative Comment or ask the Experts your question.

 
[+][-]09.08.2008 at 04:58PM PDT, ID: 22422851

Experts Exchange has a courteous staff of administrators who help members get the most out of the website by means of administrative comments like this one.

Start your 7-day free trial to view this Administrative Comment or ask the Experts your question.

 
 
Loading Advertisement...
20080716-EE-VQP-32 / EE_QW_1_20070628