ASP.net Issue Tracker starter kit, IssueTracker_IssuesView function is needed SQL or Convert a function from access to SQL : Microsoft, .net framework, asp 2.0

May 9, 2008 09:43am pdt

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03.26.2008 at 06:19PM PDT, ID: 23272691

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ASP.net Issue Tracker starter kit, IssueTracker_IssuesView function is needed SQL or Convert a function from access to SQL

Zones: MS SQL Server, Microsoft Access Database, SQL Query Syntax

Tags: Microsoft, .net framework, asp 2.0

Hello Experts,

I have downloaded code from ASP.net which is called as Issue starter kit. Unfortunately I was not able to install it as SQL backend so I had to adjust with their default Access DB(IssueTracker.mdb). But in anycase I tried to convert all the stored procedures listed in access DB to SQL manually. Which was ofcourse a terribly painful job. Everything ran smoothly except this one, where this procedure involves calling an other function. I am unable to implement this.

In the code snippet is the procedure and the function that I am trying to convert to SQL from Access

It would be of immense help if I can convert the "IssueTracker_IssuesView" to its corresponding function in SQL.

Thanks in advance,
Anusha

         
             IssueTracker_Issue_GetIssuesByRelevancy
 
SELECT *
FROM IssueTracker_IssuesView
WHERE (((IssueTracker_Issues.IssueCreatorId)=[@UserId]) AND ((IssueTracker_Issues.ProjectId)=[@ProjectId]) AND ((IssueTracker_Issues.Disabled)=0)) OR (((IssueTracker_Issues.ProjectId)=[@ProjectId]) AND ((IssueTracker_Issues.Disabled)=0) AND ((IssueTracker_Issues.IssueAssignedId)=[@UserId])) OR (((IssueTracker_Issues.ProjectId)=[@ProjectId]) AND ((IssueTracker_Issues.Disabled)=0) AND ((IssueTracker_Issues.IssueOwnerId)=[@UserId]))
ORDER BY IssueTracker_Issues.IssueId DESC;
 
In the above code IssueTracker_IssuesView is mentioned, now in access it is listed as just an other query, and IssueTracker_IssuesView is defined as follows:
SELECT IssueTracker_Issues.*, IIf(IsNull(IssueTracker_ProjectStatus.StatusName),'none',IssueTracker_ProjectStatus.StatusName) AS StatusName, IIf(IsNull(IssueTracker_ProjectStatus.StatusImageUrl),'',IssueTracker_ProjectStatus.StatusImageUrl) AS StatusImageUrl, IIf(IsNull(IssueTracker_ProjectPriorities.PriorityName),'none',IssueTracker_ProjectPriorities.PriorityName) AS PriorityName, IIf(IsNull(IssueTracker_ProjectPriorities.PriorityImageUrl),'',IssueTracker_ProjectPriorities.PriorityImageUrl) AS PriorityImageUrl, IIf(IsNull(IssueTracker_ProjectMilestones.MilestoneName),'none',IssueTracker_ProjectMilestones.MilestoneName) AS MilestoneName, IIf(IsNull(IssueTracker_ProjectMilestones.MilestoneImageUrl),'',IssueTracker_ProjectMilestones.MilestoneImageUrl) AS MilestoneImageUrl, IIf(IsNull(AssignedUsers.DisplayName),'none',AssignedUsers.DisplayName) AS AssignedDisplayName, IIf(IsNull(OwnerUsers.DisplayName),'none',OwnerUsers.DisplayName) AS OwnerDisplayName, IIf(IsNull(CreatorUsers.DisplayName),'none',CreatorUsers.DisplayName) AS CreatorDisplayName, IIf(IsNull(CreatorUsers.Username),'none',CreatorUsers.DisplayName) AS CreatorUsername, IssueTracker_ProjectCategories.CategoryName
FROM ((((((IssueTracker_Issues LEFT JOIN IssueTracker_ProjectStatus ON IssueTracker_Issues.IssueStatusId=IssueTracker_ProjectStatus.StatusId) LEFT JOIN IssueTracker_ProjectPriorities ON IssueTracker_Issues.IssuePriorityId=IssueTracker_ProjectPriorities.PriorityId) LEFT JOIN IssueTracker_ProjectMilestones ON IssueTracker_Issues.IssueMilestoneId=IssueTracker_ProjectMilestones.MilestoneId) LEFT JOIN IssueTracker_Users AS AssignedUsers ON IssueTracker_Issues.IssueAssignedId=AssignedUsers.UserId) LEFT JOIN IssueTracker_Users AS CreatorUsers ON IssueTracker_Issues.IssueCreatorId=CreatorUsers.UserId) LEFT JOIN IssueTracker_Users AS OwnerUsers ON IssueTracker_Issues.IssueOwnerId=OwnerUsers.UserId) LEFT JOIN IssueTracker_ProjectCategories ON IssueTracker_Issues.IssueCategoryId=IssueTracker_ProjectCategories.CategoryId;

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Question Stats

Zone: Microsoft

Question Asked By: Anushart

Solution Provided By: debuggerau

Participating Experts: 1

Solution Grade: B

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03.26.2008 at 06:35PM PDT, ID: 21217921

debuggerau:

Since access does not contain views, I suggest to create another query as its replacement, however your code functions may need modifying as a result.

http://msdn.microsoft.com/library/default.asp?url=/library/en-us/dnacc2k/html/acadvsql.asp
look under the heading views...

03.26.2008 at 07:49PM PDT, ID: 21218148

Anushart:

That did work well! I didnt even know about views in SQL until now. Thanks for that

so this part works now

ALTER PROCEDURE [dbo].[sp_Issue_GetIssuesByRelevancy]
@ProjectId int,
@UserId int
AS
BEGIN
SET NOCOUNT ON;
SELECT *
FROM dbo.IssueView
END

But errors crop up when I try to add a 'where' clause

ALTER PROCEDURE [dbo].[sp_Issue_GetIssuesByRelevancy]
@ProjectId int,
@UserId int
AS
BEGIN
SET NOCOUNT ON;
SELECT *
FROM dbo.IssueView
WHERE tbl_Issues.IssueCreatorId=@UserId
AND tbl_Issues.ProjectId=@ProjectId
ORDER BY tbl_Issues.IssueId DESC;
END

Errors read:
Msg 4104, Level 16, State 1, Procedure sp_Issue_GetIssuesByRelevancy, Line 13
The multi-part identifier "tbl_Issues.IssueCreatorId" could not be bound.
Msg 4104, Level 16, State 1, Procedure sp_Issue_GetIssuesByRelevancy, Line 13
The multi-part identifier "tbl_Issues.ProjectId" could not be bound.
Msg 4104, Level 16, State 1, Procedure sp_Issue_GetIssuesByRelevancy, Line 13
The multi-part identifier "tbl_Issues.IssueId" could not be bound.

Can you please suggest a way out as creating a view would be of no use if this doesnt work

03.26.2008 at 08:09PM PDT, ID: 21218233

Anushart:

Sorry I wasnt declaring tbl_issues

Anyway please ignore my previous message, below code compiles well but doesnt pull up any records.. ny suggestions on that?

ALTER PROCEDURE [dbo].[sp_Issue_GetIssuesByRelevancy]
@ProjectId int,
@UserId int

AS
BEGIN
SET NOCOUNT ON;
SELECT *
FROM dbo.IssueView, tbl_Issues
WHERE (((tbl_Issues.IssueCreatorId)=@UserId)
AND ((tbl_Issues.ProjectId)=@ProjectId)
AND ((tbl_Issues.Disabled)=0))
OR (((tbl_Issues.ProjectId)=@ProjectId)
AND ((tbl_Issues.Disabled)=0)
AND ((tbl_Issues.IssueAssignedId)=@UserId))
OR (((tbl_Issues.ProjectId)=@ProjectId)
AND ((tbl_Issues.Disabled)=0)
AND ((tbl_Issues.IssueOwnerId)=@UserId))
ORDER BY tbl_Issues.IssueId DESC;

END

04.08.2008 at 11:54PM PDT, ID: 21312373

debuggerau:

thats quite a query, I'd have to test it first. Possibly tomorrow, however it should be listed as another question really..

But I'd suspect its not conforming to valid data and returning nill.
Why not build it up slowly, one where at a time...

Accepted Solution

20080236-EE-VQP-29 / EE_QW_2_20070628