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9.0

SQL Count trouble

Asked by tselectro in MS SQL Server, SQL Server 2008

Tags: Microsoft SQL server

Hello, I have 4 tables, Plant, Plant_Type, Object and Object_Type.

Plant table
ID
Name
TypeID (linked to ID in Plant_Type)

Plant_Type table
ID
Name

Object table
ID
Plant_ID (linked to ID in Plant table)
TypeID  (linked to ID in Object_Type table)

Object_Type table
ID
Name

TypeID field in Plant and Object tables are linked to respective xxx_Type tables. I want to count number of object in Object table group on TypeID for a specific plant type. If no object exists for given plant type, the query should return 0 for that object type.

I have a query as shown below. It work, but if I try to add where condition it does not work as wanted (it only list object that have count > 0, I want to list every object)

SQL ex:
SELECT tblObject_Type.ID, tblObject_Type.Type, Count(tblObject.ID) As ObjectCount
FROM (tblObject
LEFT  JOIN tblObject_Type On tblObject.TypeID = tblObject_Type.ID)
LEFT  JOIN tblPlant On tblObject.Plant_ID = tblPlant.ID
--WHERE tblPlant.TypeID=1
GROUP BY tblObject_Type.ID, tblObject_Type.Type

Result ex:
TypeID|Type|Count
2      Motor      2
1      Pump      1
3      Valve      1

If it does not exists any object of type Motor and Pump for object linked to plant with plant type xx, the result should for ex. be so:
TypeID|Type|Count
2      Motor      0
1      Pumpe      0
3      Ventil      1

I hope someone can help me!

[+][-]11/02/09 06:43 AM, ID: 25719730Expert Comment

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[+][-]11/02/09 06:59 AM, ID: 25719923Expert Comment

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[+][-]11/02/09 07:20 AM, ID: 25720136Expert Comment

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[+][-]11/02/09 09:06 AM, ID: 25721214Author Comment

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[+][-]11/02/09 09:48 AM, ID: 25721643Expert Comment

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[+][-]11/02/09 05:06 PM, ID: 25725347Expert Comment

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[+][-]11/02/09 05:49 PM, ID: 25725517Expert Comment

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[+][-]11/02/09 05:50 PM, ID: 25725521Accepted Solution

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About this solution

Zones: MS SQL Server, SQL Server 2008
Tags: Microsoft SQL server
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Solution Provided By: acperkins
Participating Experts: 3
Solution Grade: A
 
 
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