Question

sql server string splitting...

Asked by: Extreme66

Hi I have a field that values consist of an id like either xxx-yyy-zzz-ff, or sometimes just xxx-yy-zz.
There typically is only 3 or four parts to an id, and always separated by a hyphen however the is not always 3 characters in each section. I am looking to split this into the 3 or 4 sections using a substring or something. Any ideas? I played around with charindex a little but got strange results when using it inside a function.

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Asked On
2009-11-04 at 10:28:52ID24871883
Topic

MS SQL Server

Participating Experts
5
Points
500
Comments
31

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Answers

 

by: aneeshattingalPosted on 2009-11-04 at 10:31:27ID: 25742302

CREATE function [dbo].[ParseString]
(
@String       varchar(8000)
)
returns @tbl table ( s varchar(1000))
as
begin
declare @i int, @j int

      select       @i = 1
      while @i <= len(@String)
      begin
            select      @j = charindex('-', @String, @i)
            if @j = 0
            begin
                  select      @j = len(@String) + 1
            end
            insert      @tbl select substring(@String, @i, @j - @i)
            select      @i = @j + 1
      end
      return
end
GO

SELECT * from [dbo].[ParseString]('xxx-yyy-zzz-ff' )

 

by: Extreme66Posted on 2009-11-04 at 13:18:30ID: 25744042

im getting a strange error when running it
Major Error 0x80040E14, Minor Error 25501

 

by: aneeshattingalPosted on 2009-11-04 at 17:31:09ID: 25745992

did u try the exact query

 

by: Extreme66Posted on 2009-11-04 at 17:32:44ID: 25746003

yes ,here is the complete message
Major Error 0x80040E14, Minor Error 25501
> CREATE function [dbo].[ParseString]
(
@String       varchar(8000)
)
returns @tbl table ( s varchar(1000))
as
begin
declare @i int, @j int

      select       @i = 1
      while @i <= len(@String)
      begin
            select      @j = charindex('-', @String, @i)
            if @j = 0
            begin
                  select      @j = len(@String) + 1
            end
            insert      @tbl select substring(@String, @i, @j - @i)
            select      @i = @j + 1
      end
      return
end
There was an error parsing the query. [ Token line number = 1,Token line offset = 8,Token in error = function ]

 

by: aneeshattingalPosted on 2009-11-04 at 17:41:12ID: 25746041

is that for sql server

 

by: Extreme66Posted on 2009-11-04 at 17:42:59ID: 25746051

yes, im running sql server 2008 express

 

by: aneeshattingalPosted on 2009-11-04 at 19:21:51ID: 25746500

you have to run it in a new query window

 

by: Extreme66Posted on 2009-11-09 at 15:28:27ID: 25781171

I have run this in a new query window all by itself I dont know why im getting this error, but I tried it on two different sql installations

 

by: Extreme66Posted on 2009-11-09 at 16:27:47ID: 25781468

Somehow I was missing a parenthesis, now I am getting

Server: Msg 444, Level 16, State 2, Procedure ParseItem, Line 10
Select statements included withjin a function cannot return data to a client

 

by: aneeshattingalPosted on 2009-11-09 at 17:19:50ID: 25781692

I think i answered your question..

>Somehow I was missing a parenthesis

Did you try the one i provided without making any changes =, it worked for me

 

by: aneeshattingalPosted on 2009-11-09 at 17:19:52ID: 25781694

I think i answered your question..

>Somehow I was missing a parenthesis

Did you try the one i provided without making any changes =, it worked for me

 

by: aneeshattingalPosted on 2009-11-09 at 17:19:56ID: 25781695

I think i answered your question..

>Somehow I was missing a parenthesis

Did you try the one i provided without making any changes =, it worked for me

 

by: Extreme66Posted on 2009-11-10 at 07:18:38ID: 25786187

I did try it without changes, I believe the first time I may have hit backspace which threw the first error. I coped again and am running as is, but getting hte new error of:

Server: Msg 444, Level 16, State 2, Procedure ParseItem, Line 10
Select statements included withjin a function cannot return data to a client

 

by: aneeshattingalPosted on 2009-11-10 at 08:05:55ID: 25786709

can you tell me how you are doing , are you doing it thru the query window ?

 

by: Extreme66Posted on 2009-11-10 at 08:38:42ID: 25787078

I open up a new query window and paste it in verbatim. when I run it I get that error. Should I be running it another way?

 

by: BrandonGalderisiPosted on 2009-11-12 at 07:40:14ID: 25805453

What version of SQL Server are you using?

 

by: Sharath_123Posted on 2009-11-12 at 08:40:28ID: 25806123

Can you provide some sample data for your Id?

 

by: Extreme66Posted on 2009-11-12 at 10:04:57ID: 25807004

sample data would look like the following. I literally am only interested in each piece so if I could even do something like the following I would
select substring(secttion 1 from left to first dash),
substring(second - to next -)
and so one I would be ecstatic.

my_id
xxx-ttt-yys-dd-ccc
xx-rrt-das-ff
ff-sss-rrr-rrr
ss-sss-sss-ss
ss-sss-sss-ddd

 

by: Extreme66Posted on 2009-11-12 at 10:07:19ID: 25807027

thanks for your help in advance...

just to clarify i would expect output to be : (using first id as example) xxx-ttt-yys-dd-ccc

xxx as my first returned col, then tttm then yys etc...


sample data would look like the following. I literally am only interested in each piece so if I could even do something like the following I would
select substring(secttion 1 from left to first dash),
substring(second - to next -)
and so one I would be ecstatic.

my_id
xxx-ttt-yys-dd-ccc
xx-rrt-das-ff
ff-sss-rrr-rrr
ss-sss-sss-ss
ss-sss-sss-ddd

 

by: BrandonGalderisiPosted on 2009-11-12 at 10:09:28ID: 25807050

What is the maximum number of "columns"?  5?

 

by: Extreme66Posted on 2009-11-12 at 10:19:31ID: 25807155

The maximum number of cols would be 5 yes

 

by: BrandonGalderisiPosted on 2009-11-12 at 11:14:53ID: 25807765

Here is a function, with a data sample using outer apply to split your field into columns.

set nocount on
GO
if object_id('dbo.data_to_columns') is not null
drop function dbo.data_to_columns 
GO
create function dbo.data_to_columns (@input varchar(8000),@delimiter varchar(20))
     returns @Output TABLE
     (col1 varchar(8000)
     ,col2 varchar(8000)
     ,col3 varchar(8000)
     ,col4 varchar(8000)
     ,col5 varchar(8000)
     )
AS
begin
declare 
      @i       tinyint
     ,@nInput  varchar(8000) 
set @i=1 
if @input like '%'+@delimiter+'%'
begin
     while @i<=5 and @input is not null
     begin
          if @input like '%'+@delimiter+'%'
          begin
               set @nInput = left(@input,charindex(@delimiter,@input)-1)
               set @Input = right(@input,datalength(@input)-(datalength(@nInput + @delimiter)))
          end
          else
          begin
               set @nInput = @input
               set @input = null
          end 
          if @i=1
               insert into @output(col1) values(@nInput)
          else if @i=2
               update @output set col2=@ninput
          else if @i=3
               update @output set col3=@ninput
          else if @i=4
               update @output set col4=@ninput
          else if @i=5
               update @output set col5=@ninput 
          set @i=@i+1
     end
end
else
     insert into @output(col1,col2,col3,col4,col5)
     select @input,null,null,null,null 
RETURN
end
GO 
declare @t table (ident int identity,my_id varchar(30))
insert into @t (my_id) values('xxx-ttt-yys-dd-ccc')
insert into @t (my_id) values('xx-rrt-das-ff')
insert into @t (my_id) values('ff-sss-rrr')
insert into @t (my_id) values('ss-sss')
insert into @t (my_id) values('ss') 

--select ident,col1,col2,col3,col4,col5 from @t outer apply dbo.data_to_columns(my_id,'-') 
select * from @t outer apply dbo.data_to_columns(my_id,'-')

                                              
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by: Sharath_123Posted on 2009-11-12 at 11:55:30ID: 25808203

Can you try this?

select my_id
       parsename(col1,4) as col1,
       parsename(col1,3) as col2,
       parsename(col1,2) as col3,
       parsename(col1,1) as col4,
       col5
  from (select my_id,
               case when (LEN(my_id) - LEN(REPLACE(my_id, '-', ''))) > 3 
               then reverse(substring(reverse(my_id),1,charindex('-',1,reverse(my_id))-1)) 
               else null end as col5,
               replace(case when (LEN(my_id) - LEN(REPLACE(my_id, '-', ''))) > 3 
                            then reverese(substring(reverse(my_id),charindex('-',1,reverse(my_id))+1,len(my_id)))
                            else my_id end,'-',':') as col1
          from YourTable) as t1

                                              
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by: rob_farleyPosted on 2009-11-12 at 15:13:24ID: 25809936

Use this:

create function dbo.split(@s varchar(500)) returns table as /* Note we're not declaring the table here, so it's an inline function */
return
(
with
 N0 as (select 1 as n union all select 1)
,N1 as (select 1 as n from N0 t1, N0 t2)
,N2 as (select 1 as n from N1 t1, N1 t2)
,N3 as (select 1 as n from N2 t1, N2 t2)
,N4 as (select 1 as n from N3 t1, N3 t2)
,nums as (select row_number() over (order by (select 1)) as num from N4)
select [1],[2],[3],[4]
from
(
select substring(@s, num, charindex('-',@s+'-',num)-num) as s, row_number() over (order by num) as colnum
from nums
where substring('-' + @s,num,1) = '-'
and num <= len(@s)
) t
pivot
(max(s) for colnum in ([1],[2],[3],[4])) p
)
;

And then you have a few options for calling it:

declare @str varchar(500);
set @str = '123-456-7890-abc';

select *
from dbo.split(@str);

or for rows in a table, use CROSS APPLY.

create table dbo.testvals (somestring varchar(500));
insert testvals (somestring) select '123-456-7890-abc';
insert testvals (somestring) select '234-567-890-abcd';

select *
from testvals t
   cross apply
   dbo.split(t.somestring) s
;

 

by: Extreme66Posted on 2009-11-12 at 15:17:10ID: 25809954

thanks all, im trying these solutions tonight

 

by: mark_willsPosted on 2009-11-12 at 23:49:30ID: 25812089

Just for something different, and maybe there might be NULLs (maybe not) have a look at the following...

It uses some "magic numbers" which are contained in the system table spt_values as described in the Article :
http://www.experts-exchange.com/articles/Microsoft/Development/MS-SQL-Server/Fun-with-MS-SQL-spt-values-for-delimited-strings-and-virtual-calendars.html

-- using Rob's test data and adding a bit more variety to it...
 
create table #testvals (id int identity,somestring varchar(500));
insert #testvals (somestring) select '123-456-7890-abc';
insert #testvals (somestring) select '234-567-890-abcd';
insert #testvals (somestring) select '123';
insert #testvals (somestring) select '234-567';
insert #testvals (somestring) select '123-456-7890';
insert #testvals (somestring) select '234-567-890-abcd-efg';
insert #testvals (somestring) select '1-2-3';
insert #testvals (somestring) select '1-2-3-4-567';
insert #testvals (somestring) select '1-23-456-7890';
insert #testvals (somestring) select '1223234-567-890-abcd-efg';
insert #testvals (somestring) select '1';
insert #testvals (somestring) select null;
 
-- now using a straight select statement with the help of "magic numbers" already supplied by MS
 
select id,somestring
,case when n1.number is not NULL then SUBSTRING(somestring, 1, n1.number -1) else '' end as N1
,case when n2.number is not NULL then SUBSTRING(somestring, n1.number +1, n2.number - n1.number -1 ) else '' end as N2
,case when n3.number is not NULL then SUBSTRING(somestring, n2.number +1, n3.number - n2.number -1 ) else '' end as N3
,case when n4.number is not NULL then SUBSTRING(somestring, n3.number +1, n4.number - n3.number -1 ) else '' end as N4
,case when n5.number is not NULL then SUBSTRING(somestring, n4.number +1, n5.number - n4.number -1 ) else '' end as N5
FROM #testvals
left JOIN master..spt_values N1 with (nolock) on n1.type = 'P' and n1.number between 1 and len(somestring)+1 and n1.number = CHARINDEX('-', somestring + '-',1)
left JOIN master..spt_values N2 with (nolock) on n2.type = 'P' and n2.number between n1.number and len(somestring)+1 and n2.number = CHARINDEX('-', somestring + '-',n1.number+1)
left JOIN master..spt_values N3 with (nolock) on n3.type = 'P' and n3.number between n2.number and len(somestring)+1 and n3.number = CHARINDEX('-', somestring + '-',n2.number+1)
left JOIN master..spt_values N4 with (nolock) on n4.type = 'P' and n4.number between n3.number and len(somestring)+1 and n4.number = CHARINDEX('-', somestring + '-',n3.number+1)
left JOIN master..spt_values N5 with (nolock) on n5.type = 'P' and n5.number between n4.number and len(somestring)+1 and n5.number = CHARINDEX('-', somestring + '-',n4.number+1)
                                              
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by: Extreme66Posted on 2009-11-13 at 06:43:08ID: 25814251

Sarath, i just tried yours and just running the inner query I get

Msg 8116, Level 16, State 1, Line 2
Argument data type nvarchar is invalid for argument 3 of charindex function.

 

by: Sharath_123Posted on 2009-11-13 at 08:47:04ID: 25815391

Can you try this?

select my_id,
       parsename(col1,4) as col1,
       parsename(col1,3) as col2,
       parsename(col1,2) as col3,
       parsename(col1,1) as col4,
       col5
  from (
            select my_id,
                     case when (LEN(my_id) - LEN(REPLACE(my_id, '-', ''))) > 3
                              then  reverse(substring(reverse(my_id),1,charindex('-',reverse(my_id))-1))
                              else null end as col5,
                     replace(case when (LEN(my_id) - LEN(REPLACE(my_id, '-', ''))) > 3
                              then reverse(substring(reverse(my_id),charindex('-',reverse(my_id))+1,len(my_id)))
                              else my_id end,'-','.') as col1
              from YourTable) as t1

declare @table as table(my_id nvarchar(20)) 
insert into @table values ('xxx-ttt-yys-dd-ccc')
insert into @table values ('xx-rrt-das-ff')
insert into @table values ('ff-sss-rrr-rrr')
insert into @table values ('ss-sss-sss-ss')
insert into @table values ('ss-sss-sss-ddd') 
select my_id,
       parsename(col1,4) as col1,
       parsename(col1,3) as col2,
       parsename(col1,2) as col3,
       parsename(col1,1) as col4,
       col5
  from (
		select my_id,
			   case when (LEN(my_id) - LEN(REPLACE(my_id, '-', ''))) > 3 
					then  reverse(substring(reverse(my_id),1,charindex('-',reverse(my_id))-1))
					else null end as col5,
			   replace(case when (LEN(my_id) - LEN(REPLACE(my_id, '-', ''))) > 3 
					then reverse(substring(reverse(my_id),charindex('-',reverse(my_id))+1,len(my_id)))
					else my_id end,'-','.') as col1
		  from @table) as t1 
/*
my_id               col1 col2  col3 col4 col5
xxx-ttt-yys-dd-ccc	xxx	 ttt	yys	dd	 ccc
xx-rrt-das-ff	    xx	 rrt	das	ff	 NULL
ff-sss-rrr-rrr	    ff	 sss	rrr	rrr	 NULL
ss-sss-sss-ss	    ss	 sss	sss	ss	 NULL
ss-sss-sss-ddd	ss	sss	sss	ddd	NULL
*/

                                              
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by: Extreme66Posted on 2009-11-16 at 10:38:50ID: 31650126

Thanks All, I would have liked to award more points but I really sort of used a combination of these ideas to make a solution.

20120131-EE-VQP-002

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