Question

how convert big int to hh:mm:ss

Asked by: LukeB

Hi
In SQL 2005/2008 I am getting an integer result from a msdb stored proc that is a time in big int, i.e. 173540. which is 17:35:40

how do I get 173540 (starts out a number, not given as char, so neede to convert to char first?) converted to :
  5:35:40 pm
and
  17:35:40

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Asked On
2009-11-06 at 01:38:23ID24877373
Topics

MS SQL Server

,

SQL Server 2005

Participating Experts
5
Points
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Comments
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Answers

 

by: Allister_ReidPosted on 2009-11-06 at 01:47:28ID: 25757818

Hi,
which is it?  SQL Server 2005 or 2008?


Regards

 

by: saied_geniusPosted on 2009-11-06 at 01:52:13ID: 25757828

Hi

select substring('123456',1,2)+':'+substring('123456',3,2)+':'+substring('123456',5,2) as output

in your case you could use:

select substring(filedName,1,2)+':'+substring(filedName,3,2)+':'+substring(filedName,5,2)

 

by: pratima_mcsPosted on 2009-11-06 at 01:53:00ID: 25757833

Declare @i bigint
set @i = 173540
Declare @str nvarchar(6)
set @str = Convert( varchar(6),@i)

select substring(@str,1,2) + ':' + substring(@str,3,2)+ ':' + substring(@str,5,2)

 

by: Allister_ReidPosted on 2009-11-06 at 02:06:30ID: 25757876

What about the int 12345?  

DECLARE @Int INT
SET @Int = 12345
SELECT
      SUBSTRING(CONVERT(VARCHAR, @Int), 1, LEN(CONVERT(VARCHAR, @Int)) - 4) + ':' +
      SUBSTRING(CONVERT(VARCHAR, @Int), LEN(CONVERT(VARCHAR, @Int)) - 3, 2) + ':' +
      RIGHT(CONVERT(VARCHAR, @Int), 2)

Do you just want a string representation, or do you want a variable on which you can perform time arithmetic?  The reason I ask about 2005/2008 is that 2008 has a time type.

 

by: selva_konguPosted on 2009-11-06 at 02:14:03ID: 25757900

Try This

CREATE FUNCTION [dbo].[fnConvertIntegerToTime]
	(@ArrivalTime24hr int)
	
RETURNS varchar(12)
 
AS
	BEGIN
		DECLARE @ArrivalHour int,
			@ArrivalMinute int,
			@ArrivalTime varchar(12),
			@ArrivalTime24HrChr varchar(4),
			@ArrivalTime24HrLen int,
			@ArrivalSec int
			
	SET @ArrivalTime24HrLen = LEN(@ArrivalTime24hr)
	SET @ArrivalTime24HrChr = CAST(@ArrivalTime24hr AS varchar(2))
	
	IF @ArrivalTime24HrLen = 3
		BEGIN
			SET @ArrivalHour = LEFT(@ArrivalTime24hr,1)
			SET @ArrivalMinute = RIGHT(@ArrivalTime24hr,2)
			SET @ArrivalSec = 0
		END
	ELSE
	IF @ArrivalTime24HrLen = 4
		BEGIN
			SET @ArrivalHour = LEFT(@ArrivalTime24Hr,2)
			SET @ArrivalMinute = RIGHT(@ArrivalTime24Hr,2)
			SET @ArrivalSec = 0
		END
	ELSE
	IF @ArrivalTime24HrLen > 4
		BEGIN
			SET @ArrivalHour = LEFT(@ArrivalTime24Hr,2)
			SET @ArrivalMinute = LEFT(RIGHT(173540,4),2)
			SET @ArrivalSec = RIGHT(@ArrivalTime24Hr,2)
		END
	IF @ArrivalHour < 1200 
	BEGIN
 
		SET @ArrivalTime =  CAST(@ArrivalHour AS varchar(2)) + ':'+ CAST(@ArrivalMinute AS varchar(2)) + ':' + CAST(@ArrivalSec AS varchar(2)) + ' AM'	
	END
 
	ELSE
	IF @ArrivalTime24hr BETWEEN 1200 AND 1259
	BEGIN
		SET @ArrivalTime =  CAST(@ArrivalHour AS varchar(2)) + ':'+ CAST(@ArrivalMinute AS varchar(2)) + ':' + CAST(@ArrivalSec AS varchar(2)) + ' PM'
 
	END	
	ELSE
	IF @ArrivalTime24hr BETWEEN 1300 AND 2359
	BEGIN
		SET @ArrivalTime =  CAST(@ArrivalHour - 12 As varchar(2)) + ':'+ CAST(@ArrivalMinute AS varchar(2)) + ':' + CAST(@ArrivalSec AS varchar(2)) + ' PM'
 
 
	END	
 
RETURN @ArrivalTime
END

                                              
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by: acperkinsPosted on 2009-11-06 at 08:01:42ID: 25760269

I suspect you will find the following a tad more efficient then a lot of character manipulation which is always a dog in T-SQL:

DECLARE @X bigint
SET @X = 173540
SELECT      CONVERT(char(8), DATEADD(second, (@X / 10000) * 3600 + ((@X / 100) % 100) * 60 + @X % 100, '19000101'), 108)

 

by: LukeBPosted on 2009-11-09 at 13:52:26ID: 25780516

Saied + Pratima: your code will not work for early morning hours, i.e. 1:23:45 as Allister points out

Allister :  yours is close, would have liked to have similar to AC's format, i.e. 01:23:45, whereas yours gives 1:23:45 which while correct in "24hr clock speak" the leading zero helps indicate is a 24hr clock, not a 12 hr clock.
Sorry, is SQL 2008 on one machine and SQL 2005 on another so trying to make code compatible. The BIG INT is supplied by :
  msdb.dbo.sysjobs, field run_time
and that table has the field as big int, not a time format unfortunately


AC: thanks, first part of question answered. That is exact format I need for 24hr.

And second part of question, how do I get into :
   5:35:40 pm
format ?

 

by: acperkinsPosted on 2009-11-09 at 16:42:19ID: 25781537

>>msdb.dbo.sysjobs, field run_time
and that table has the field as big int, not a time format unfortunately<<
The sysjobs does not contain a run_time column.  There is a run_time column in the sysjobhistory, but it is an int not a bigint.

In any case to answer your question you can do this:
DECLARE @X bigint
SET @X = 173540
SELECT      RIGHT(CONVERT(varchar(19), DATEADD(second, (@X / 10000) * 3600 + ((@X / 100) % 100) * 60 + @X % 100, '19000101'), 0), 7)

If you also need seconds, then you are going to have to get more creative and do something like this:
SELECT      STUFF(RIGHT(CONVERT(varchar(26), DATEADD(second, (@X / 10000) * 3600 + ((@X / 100) % 100) * 60 + @X % 100, '19000101'), 9), 14), 9, 4, '')

 

by: acperkinsPosted on 2009-11-09 at 16:46:25ID: 25781555

A better approach is not to use SQL Server for presentation problems.  It was never designed for that and does a ratehr lousy job at it.

 

by: LukeBPosted on 2009-11-09 at 17:04:07ID: 25781627

AC

Sorry, yes, I meant msdb.dbo.sysjobhistory ... and is int not big int.

just wanted the syntax for inserting into my own custom  'runtime diary '  table and this seems easiest at the moment. Not for a web report or anything

Tx

luke

20120131-EE-VQP-002

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