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9.4

When dateadd function makes it to next day, my logic fails.

Asked by Mehram in MS SQL Server

Tags: Mateen

SQL Server 2005

If a person has come (timein varchar(8) ) 180 minutes late then his office time (otimein)
he should be treated as 1 day absent.
If he is 77 minutes late, he should be treated as 1/2 absent.
If he is 17 minutes late, he should be treated as 1/4 absent.

My code, (see code snippet) works as long as the otimein is less than 21:00:00,
otherwise it fails because then the dateadd functions makes it to next day.

What is the correct way?





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update a
set  remarks	=   case when a.flag not in ('R','G') then
        case when a.timein > convert(varchar,dateadd(s,180*60,convert(datetime,a.otimein)),108) then '1 Absent' 
   else case when a.timein > convert(varchar,dateadd(s,77*60,convert(datetime,a.otimein)),108) then '1/2 Absent' 
   else case when a.timein > convert(varchar,dateadd(s,17*60,convert(datetime,a.otimein)),108) then '1/4 Absent' 
   else a.remarks
   end end end end 
from @t a
 
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