Question

selecting a data range based on day names

Asked by: bullrout

HI There,

I'm wondering how I can get a range of dates and times based on day names? For example how can I select between midday wednesday and midnight sunday?

Sean

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Asked On
2007-10-03 at 03:17:06ID22868710
Tags

date

,

select

Topics

SQL Server 2005

,

Databases Miscellaneous

,

MS SQL Server

Participating Experts
3
Points
500
Comments
13

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Answers

 

by: angelIIIPosted on 2007-10-03 at 03:20:36ID: 20005170

you will need to create a user defined function that translates the text into a concreate date.
am I right that with midday wednesday, you mean past wednesday 12:00PM ?

 

by: jinesh_kamdarPosted on 2007-10-03 at 03:35:42ID: 20005230

You can use the 'DAY' format of the date, but i m not sure how you can select a range using it.

SELECT *
FROM your_table_name
WHERE TO_CHAR(your_date_column,'DAY') = 'WEDNESDAY'
OR TO_CHAR(your_date_column,'DAY') = 'SATURDAY'

 

by: bullroutPosted on 2007-10-03 at 04:02:43ID: 20005311

Hi angelIII,

Yes that's correct. past midday on wednesday and then before midnight on sunday.

 

by: YveauPosted on 2007-10-03 at 05:15:53ID: 20005681

This one will return all 'wednesdays' for you:

select <YourCol>
from   <YourTable>
where  datename(weekday, <YourCol>) = 'wednesday'

Remains  the 'midday' part ...
Hope this helps ...

 

by: YveauPosted on 2007-10-03 at 05:18:06ID: 20005700

What do you want when saying
>>between midday wednesday and midnight sunday

between most recent wednesday 12:00 and most recent sunday 0:00 ? (that is the start of the sunday !)
or most recent wednesday 12:00 and most recent sunday 23:59.59 ? (that is the end of the sunday !)



 

by: angelIIIPosted on 2007-10-03 at 05:18:25ID: 20005703

@jinesh_kamdar: TO_CHAR is for Oracle, and does not exist in MS SQL server

>Yes that's correct. past midday on wednesday and then before midnight on sunday.
but WHICH wednesday / sunday?

ie, in the following cases, "now" is, October 03, 2007:
* wednesday , 08:00  
* wednesday , 12:00  
* wednesday , 14:00  

what date/time do you want to "start", in those 3 cases?
please explain with "plain enlgish" rules.


 

by: bullroutPosted on 2007-10-03 at 05:23:15ID: 20005753

sorry angelIII:

this one * wednesday , 12:00  

 

by: angelIIIPosted on 2007-10-03 at 05:27:14ID: 20005787

I guess I asked wrongly.
let me rephrase the question:

what day/time in the week do you want to "switch" from "previous" wednesday to the "next" wednesday?

 

by: bullroutPosted on 2007-10-03 at 05:54:17ID: 20005996

I will give you a little background:

the query is for a voting poll that is only open between wednesday 12.00pm midday and sunday 12:am each week. So each time the poll closes it only re-opens on the following wednesday at midday.

I hope I have explained it a little better than before.

 

by: bullroutPosted on 2007-10-03 at 06:22:05ID: 20006261

HI angelIII,


did that make any sense?

 

by: angelIIIPosted on 2007-10-03 at 08:08:55ID: 20007195

please check the following "loop" to check if the results are what you expect as "logic":

declare @d datetime
declare @w datetime
declare @s datetime

set @d = getdate() - 14

while @d < getdate()
begin
  set @w = dateadd(day, case when datepart(weekday, @d) < 4 then - datepart(weekday, @d) - 3  
        when datepart(weekday, @d) > 4 then 4 - datepart(weekday, @d)
        when datepart(hour, @d) < 12 then - datepart(weekday, @d) - 3    
        else 4 - datepart(weekday, @d) end , @d )
  set @w = dateadd(hour,12,convert(datetime, convert(varchar(10), @w, 120),120))
  set @s = dateadd(day, 4, @w)

  select @d date_value, datename(weekday, @d) date_name,  @w wednesday_start, @s sunday_end

  set @d = dateadd(day, 1, @d)

end


if it is, then, your query goes like this:

declare @d datetime
declare @w datetime
declare @s datetime

set @d = getdate()

set @w = dateadd(day, case when datepart(weekday, @d) < 4 then - datepart(weekday, @d) - 3  
        when datepart(weekday, @d) > 4 then 4 - datepart(weekday, @d)
        when datepart(hour, @d) < 12 then - datepart(weekday, @d) - 3    
        else 4 - datepart(weekday, @d) end , @d )
  set @w = dateadd(hour,12,convert(datetime, convert(varchar(10), @w, 120),120))
  set @s = dateadd(day, 4, @w)

select * from yourtable
where yourdatefield >= @w
  and yourdatefield < @s


 

by: bullroutPosted on 2007-10-05 at 18:26:45ID: 20026285

Hi angelIII,

I not getting the results that I expected. The wednesday_start value is a friday and the sunday_end is a tuesday. Can you have a look at it please?


declare @w datetime
declare @s datetime

set @d = getdate() - 14

while @d < getdate()
begin
  set @w = dateadd(day, case when datepart(weekday, @d) < 4 then - datepart(weekday, @d) - 3  
        when datepart(weekday, @d) > 4 then 4 - datepart(weekday, @d)
        when datepart(hour, @d) < 12 then - datepart(weekday, @d) - 3    
        else 4 - datepart(weekday, @d) end , @d )
  set @w = dateadd(hour,12,convert(datetime, convert(varchar(10), @w, 120),120))
  set @s = dateadd(day, 4, @w)

  select @d date_value, datename(weekday, @d) date_name,  @w wednesday_start, @s sunday_end

  set @d = dateadd(day, 1, @d)

end


| date_value                      |     dayname   | wednesday_start             |        sunday_end
2007-09-22 10:27:41.507        Saturday       2007-09-19 12:00:00.000      2007-09-23 12:00:00.000

 

by: bullroutPosted on 2007-10-11 at 03:10:32ID: 20055494

Hi angelIII,

You have given me a good foundation to build on.

Thanks.

20120131-EE-VQP-002

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