[x]
Posted via EE Mobile

Search, ask, and monitor your questions on the go with EE Mobile. Visit Experts Exchange from your mobile device and never be out of touch again.

Question
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!

7.6

A computed column (formula) that contains a JOIN?

Asked by ashblack in SQL Server 2005, Algorithms, Math & Science

Tags: T-SQL

Hi there,

My application involves a multi-step algorithm that requires numerous "parent to children" lookups (states to counties, for example).

My question: is it possible to create a computed column, view, or UDF that will automatically yield the parent (or child) values for a given record without having to perform a costly "join, update and write to disc" operation - and that yields *significant* performance benefit?

Conceptually I need to do this:

   UPDATE A SET A.ThisRecord = SUM(B.ThisRecord_Kids) FROM ThisTable AS A JOIN ThisTable AS B ON A.ThisRowID = B.ThisParentID

Obviously, this can be achieved by carrying the records in a table, and stepping through each step of the algorithm and writing the results to disc before advancing to the next step... what I'm curious to do is to compute "ThisRecord" on-the-fly and pass it onto the next step in the algorithm without writing to disc.

I'm doing about 1.5 million records at a time.

Any ideas? Alternate approaches?

Greatly appreciated!

-ash
[+][-]02/18/08 10:18 AM, ID: 20922146Accepted Solution

View this solution now by starting your 30-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

About this solution

Zones: SQL Server 2005, Algorithms, Math & Science
Tags: T-SQL
Sign Up Now!
Solution Provided By: ashblack
Participating Experts: 3
Solution Grade: A
 
[+][-]02/07/08 01:07 PM, ID: 20845205Expert Comment

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 30-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]02/07/08 02:02 PM, ID: 20845780Author Comment

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 30-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]02/08/08 06:19 AM, ID: 20850239Expert Comment

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 30-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]02/08/08 06:23 AM, ID: 20850273Expert Comment

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 30-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]02/08/08 11:41 AM, ID: 20853344Expert Comment

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 30-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]02/12/08 12:01 PM, ID: 20878226Author Comment

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 30-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]02/12/08 01:43 PM, ID: 20879417Expert Comment

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 30-day free trial to view this Expert Comment or ask the Experts your question.

 
 
Loading Advertisement...
20091111-EE-VQP-92 / EE_QW_2_20070628